Get shape index in powerpoint VBA












0














I hope this is a super simple question but for some reason i cant figure it out.



I need to delete a subset of the selected shapes on a powerpoint slide using VBA. I can do this using:



ActivePresentation.Slides(1).Shapes.Range(_Index_).Delete


Where _Index_ is either an array of shape indexes (integers) or shape names (stings).



Since the shape names are not unique (and people i am making this macro for have a nasty habit of having multiple shapes with the same name) i need to rely on the shape index number. My problem is i dont know how to get the index number of a given shape.



I can only see how i get the shape name or shape ID using:



ActiveWindow.Selection.ShapeRange(IdNum).Name
ActiveWindow.Selection.ShapeRange(IdNum).ID


So my question is: How do i get the shape index of selected shapes?










share|improve this question
























  • The id should give the order they were added to the slide.
    – QHarr
    Nov 10 at 20:33










  • Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
    – Peter
    Nov 10 at 21:08












  • I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
    – QHarr
    Nov 10 at 21:19










  • " My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
    – Steve Rindsberg
    Nov 11 at 16:00










  • Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
    – Peter
    Nov 12 at 9:03


















0














I hope this is a super simple question but for some reason i cant figure it out.



I need to delete a subset of the selected shapes on a powerpoint slide using VBA. I can do this using:



ActivePresentation.Slides(1).Shapes.Range(_Index_).Delete


Where _Index_ is either an array of shape indexes (integers) or shape names (stings).



Since the shape names are not unique (and people i am making this macro for have a nasty habit of having multiple shapes with the same name) i need to rely on the shape index number. My problem is i dont know how to get the index number of a given shape.



I can only see how i get the shape name or shape ID using:



ActiveWindow.Selection.ShapeRange(IdNum).Name
ActiveWindow.Selection.ShapeRange(IdNum).ID


So my question is: How do i get the shape index of selected shapes?










share|improve this question
























  • The id should give the order they were added to the slide.
    – QHarr
    Nov 10 at 20:33










  • Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
    – Peter
    Nov 10 at 21:08












  • I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
    – QHarr
    Nov 10 at 21:19










  • " My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
    – Steve Rindsberg
    Nov 11 at 16:00










  • Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
    – Peter
    Nov 12 at 9:03
















0












0








0


0





I hope this is a super simple question but for some reason i cant figure it out.



I need to delete a subset of the selected shapes on a powerpoint slide using VBA. I can do this using:



ActivePresentation.Slides(1).Shapes.Range(_Index_).Delete


Where _Index_ is either an array of shape indexes (integers) or shape names (stings).



Since the shape names are not unique (and people i am making this macro for have a nasty habit of having multiple shapes with the same name) i need to rely on the shape index number. My problem is i dont know how to get the index number of a given shape.



I can only see how i get the shape name or shape ID using:



ActiveWindow.Selection.ShapeRange(IdNum).Name
ActiveWindow.Selection.ShapeRange(IdNum).ID


So my question is: How do i get the shape index of selected shapes?










share|improve this question















I hope this is a super simple question but for some reason i cant figure it out.



I need to delete a subset of the selected shapes on a powerpoint slide using VBA. I can do this using:



ActivePresentation.Slides(1).Shapes.Range(_Index_).Delete


Where _Index_ is either an array of shape indexes (integers) or shape names (stings).



Since the shape names are not unique (and people i am making this macro for have a nasty habit of having multiple shapes with the same name) i need to rely on the shape index number. My problem is i dont know how to get the index number of a given shape.



I can only see how i get the shape name or shape ID using:



ActiveWindow.Selection.ShapeRange(IdNum).Name
ActiveWindow.Selection.ShapeRange(IdNum).ID


So my question is: How do i get the shape index of selected shapes?







vba powerpoint powerpoint-vba






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 9:11

























asked Nov 10 at 19:57









Peter

32




32












  • The id should give the order they were added to the slide.
    – QHarr
    Nov 10 at 20:33










  • Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
    – Peter
    Nov 10 at 21:08












  • I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
    – QHarr
    Nov 10 at 21:19










  • " My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
    – Steve Rindsberg
    Nov 11 at 16:00










  • Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
    – Peter
    Nov 12 at 9:03




















  • The id should give the order they were added to the slide.
    – QHarr
    Nov 10 at 20:33










  • Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
    – Peter
    Nov 10 at 21:08












  • I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
    – QHarr
    Nov 10 at 21:19










  • " My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
    – Steve Rindsberg
    Nov 11 at 16:00










  • Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
    – Peter
    Nov 12 at 9:03


















The id should give the order they were added to the slide.
– QHarr
Nov 10 at 20:33




The id should give the order they were added to the slide.
– QHarr
Nov 10 at 20:33












Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
– Peter
Nov 10 at 21:08






Yes but how can i translate an ID into an index? The Index is always numbered 1 to number of shapes on slide while ID can be anything with gaps in between (e.g., it could be that index 1 has ID 5 and index 2 has ID 211). It seems like there should be an easy way to just get the index..
– Peter
Nov 10 at 21:08














I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
– QHarr
Nov 10 at 21:19




I don't think a separate list of indices is maintained for the Shapes collection. You could write a loop over the shapes collection to assign names you can use to differentiate.
– QHarr
Nov 10 at 21:19












" My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
– Steve Rindsberg
Nov 11 at 16:00




" My problem is i dont know how to get the index number of a given shape." If by "given" you mean selected, then ActiveWindow.Selection.ShapeRange(1)..ZOrderPosition will give you the index.
– Steve Rindsberg
Nov 11 at 16:00












Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
– Peter
Nov 12 at 9:03






Steve Rindsberg this was exactly what i needed! Thanks a lot! Im not exactly sure how this site works in terms of credit for answers but will you leave your comment as an answer so i can mark it as solved? Thanks again.
– Peter
Nov 12 at 9:03














2 Answers
2






active

oldest

votes


















0














When you group a selection of shapes, the group becomes a new shape appended to the end of the previous z-order position. All of the individual shapes within the group are appended to the z-order after the group shape itself.



I can't find a way of determining which individual item within a group is selected (sub-selected, I guess we should say, since the original parent group remains selected and that's what PPT returns when you query ActiveWindow.Selection.ShapeRange(1).



To identify the currently subselected item within a group, you can use this as a starting point:



Sub WorkWithSubSelectedShapes()
' Do stuff with sub-selected shapes within a group
' Courtesy of Andy Pope

Dim oSh As Shape
Dim oGSh As Shape
Dim x As Long

Set oSh = ActiveWindow.Selection.ShapeRange(1)

' Do something with each shape in the group:
For Each oGSh In oSh.GroupItems
Debug.Print oGSh.TextFrame.TextRange.Text
Next

' Now do something with each SUB-SELECTED
' shape within the group
With ActiveWindow.Selection.ChildShapeRange
For x = 1 To .Count
Debug.Print .Item(x).Name
Debug.Print .Item(x).TextFrame.TextRange.Text
Next
End With

End Sub


Here's some code that may help generally in processing shapes/groups. It takes account of the fact that there might be groups within groups (within groups (within groups)) ...



Sub ProcessShapes()

Dim oSh As Shape

For Each oSh In ActivePresentation.Slides(1).Shapes
If oSh.Type = msoGroup Then
Debug.Print "GROUP" & vbTab & oSh.Name & vbTab & oSh.ZOrderPosition

Call DealWithGroup(oSh)
Else
Debug.Print oSh.Name & vbTab & oSh.ZOrderPosition
End If
Next

End Sub

Sub DealWithGroup(oSh As Shape)
Dim x As Long
For x = 1 To oSh.GroupItems.Count
If oSh.GroupItems(x).Type = msoGroup Then
Call DealWithGroup(oSh.GroupItems(x))
Else
Debug.Print "GROUP ITEM" & vbTab & oSh.GroupItems(x).Name & vbTab & oSh.GroupItems(x).ZOrderPosition
End If
Next
End Sub


And to answer Peter's further (excellent) question, this should work:



Sub TestIndexOf()
MsgBox IndexOf(ActiveWindow.Selection.ShapeRange(1))
End Sub

Function IndexOf(oSh As Shape) As Long

Dim x As Long

With ActiveWindow.Selection.SlideRange.Shapes
For x = 1 To .Count
If .Item(x).Name = oSh.Name Then
' Found it, report it
IndexOf = x
End If
Next
End With
End Function





share|improve this answer



















  • 1




    Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
    – Peter
    Nov 14 at 22:58










  • @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
    – Steve Rindsberg
    Nov 15 at 19:02



















0














Try the few lines of code and yow will get names of all the shapes in immediate window (Cttl+G to view Immediate window)



Dim shp As Shape, I As Integer
For Each shp In ActivePresentation.Slides(1).Shapes
I = I + 1
Debug.Print "Index=" & I & " Name= " & shp.Name & " ID= " & shp.Id & " Type= " & shp.Type
Next





share|improve this answer





















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    2 Answers
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    2 Answers
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    active

    oldest

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    active

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    0














    When you group a selection of shapes, the group becomes a new shape appended to the end of the previous z-order position. All of the individual shapes within the group are appended to the z-order after the group shape itself.



    I can't find a way of determining which individual item within a group is selected (sub-selected, I guess we should say, since the original parent group remains selected and that's what PPT returns when you query ActiveWindow.Selection.ShapeRange(1).



    To identify the currently subselected item within a group, you can use this as a starting point:



    Sub WorkWithSubSelectedShapes()
    ' Do stuff with sub-selected shapes within a group
    ' Courtesy of Andy Pope

    Dim oSh As Shape
    Dim oGSh As Shape
    Dim x As Long

    Set oSh = ActiveWindow.Selection.ShapeRange(1)

    ' Do something with each shape in the group:
    For Each oGSh In oSh.GroupItems
    Debug.Print oGSh.TextFrame.TextRange.Text
    Next

    ' Now do something with each SUB-SELECTED
    ' shape within the group
    With ActiveWindow.Selection.ChildShapeRange
    For x = 1 To .Count
    Debug.Print .Item(x).Name
    Debug.Print .Item(x).TextFrame.TextRange.Text
    Next
    End With

    End Sub


    Here's some code that may help generally in processing shapes/groups. It takes account of the fact that there might be groups within groups (within groups (within groups)) ...



    Sub ProcessShapes()

    Dim oSh As Shape

    For Each oSh In ActivePresentation.Slides(1).Shapes
    If oSh.Type = msoGroup Then
    Debug.Print "GROUP" & vbTab & oSh.Name & vbTab & oSh.ZOrderPosition

    Call DealWithGroup(oSh)
    Else
    Debug.Print oSh.Name & vbTab & oSh.ZOrderPosition
    End If
    Next

    End Sub

    Sub DealWithGroup(oSh As Shape)
    Dim x As Long
    For x = 1 To oSh.GroupItems.Count
    If oSh.GroupItems(x).Type = msoGroup Then
    Call DealWithGroup(oSh.GroupItems(x))
    Else
    Debug.Print "GROUP ITEM" & vbTab & oSh.GroupItems(x).Name & vbTab & oSh.GroupItems(x).ZOrderPosition
    End If
    Next
    End Sub


    And to answer Peter's further (excellent) question, this should work:



    Sub TestIndexOf()
    MsgBox IndexOf(ActiveWindow.Selection.ShapeRange(1))
    End Sub

    Function IndexOf(oSh As Shape) As Long

    Dim x As Long

    With ActiveWindow.Selection.SlideRange.Shapes
    For x = 1 To .Count
    If .Item(x).Name = oSh.Name Then
    ' Found it, report it
    IndexOf = x
    End If
    Next
    End With
    End Function





    share|improve this answer



















    • 1




      Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
      – Peter
      Nov 14 at 22:58










    • @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
      – Steve Rindsberg
      Nov 15 at 19:02
















    0














    When you group a selection of shapes, the group becomes a new shape appended to the end of the previous z-order position. All of the individual shapes within the group are appended to the z-order after the group shape itself.



    I can't find a way of determining which individual item within a group is selected (sub-selected, I guess we should say, since the original parent group remains selected and that's what PPT returns when you query ActiveWindow.Selection.ShapeRange(1).



    To identify the currently subselected item within a group, you can use this as a starting point:



    Sub WorkWithSubSelectedShapes()
    ' Do stuff with sub-selected shapes within a group
    ' Courtesy of Andy Pope

    Dim oSh As Shape
    Dim oGSh As Shape
    Dim x As Long

    Set oSh = ActiveWindow.Selection.ShapeRange(1)

    ' Do something with each shape in the group:
    For Each oGSh In oSh.GroupItems
    Debug.Print oGSh.TextFrame.TextRange.Text
    Next

    ' Now do something with each SUB-SELECTED
    ' shape within the group
    With ActiveWindow.Selection.ChildShapeRange
    For x = 1 To .Count
    Debug.Print .Item(x).Name
    Debug.Print .Item(x).TextFrame.TextRange.Text
    Next
    End With

    End Sub


    Here's some code that may help generally in processing shapes/groups. It takes account of the fact that there might be groups within groups (within groups (within groups)) ...



    Sub ProcessShapes()

    Dim oSh As Shape

    For Each oSh In ActivePresentation.Slides(1).Shapes
    If oSh.Type = msoGroup Then
    Debug.Print "GROUP" & vbTab & oSh.Name & vbTab & oSh.ZOrderPosition

    Call DealWithGroup(oSh)
    Else
    Debug.Print oSh.Name & vbTab & oSh.ZOrderPosition
    End If
    Next

    End Sub

    Sub DealWithGroup(oSh As Shape)
    Dim x As Long
    For x = 1 To oSh.GroupItems.Count
    If oSh.GroupItems(x).Type = msoGroup Then
    Call DealWithGroup(oSh.GroupItems(x))
    Else
    Debug.Print "GROUP ITEM" & vbTab & oSh.GroupItems(x).Name & vbTab & oSh.GroupItems(x).ZOrderPosition
    End If
    Next
    End Sub


    And to answer Peter's further (excellent) question, this should work:



    Sub TestIndexOf()
    MsgBox IndexOf(ActiveWindow.Selection.ShapeRange(1))
    End Sub

    Function IndexOf(oSh As Shape) As Long

    Dim x As Long

    With ActiveWindow.Selection.SlideRange.Shapes
    For x = 1 To .Count
    If .Item(x).Name = oSh.Name Then
    ' Found it, report it
    IndexOf = x
    End If
    Next
    End With
    End Function





    share|improve this answer



















    • 1




      Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
      – Peter
      Nov 14 at 22:58










    • @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
      – Steve Rindsberg
      Nov 15 at 19:02














    0












    0








    0






    When you group a selection of shapes, the group becomes a new shape appended to the end of the previous z-order position. All of the individual shapes within the group are appended to the z-order after the group shape itself.



    I can't find a way of determining which individual item within a group is selected (sub-selected, I guess we should say, since the original parent group remains selected and that's what PPT returns when you query ActiveWindow.Selection.ShapeRange(1).



    To identify the currently subselected item within a group, you can use this as a starting point:



    Sub WorkWithSubSelectedShapes()
    ' Do stuff with sub-selected shapes within a group
    ' Courtesy of Andy Pope

    Dim oSh As Shape
    Dim oGSh As Shape
    Dim x As Long

    Set oSh = ActiveWindow.Selection.ShapeRange(1)

    ' Do something with each shape in the group:
    For Each oGSh In oSh.GroupItems
    Debug.Print oGSh.TextFrame.TextRange.Text
    Next

    ' Now do something with each SUB-SELECTED
    ' shape within the group
    With ActiveWindow.Selection.ChildShapeRange
    For x = 1 To .Count
    Debug.Print .Item(x).Name
    Debug.Print .Item(x).TextFrame.TextRange.Text
    Next
    End With

    End Sub


    Here's some code that may help generally in processing shapes/groups. It takes account of the fact that there might be groups within groups (within groups (within groups)) ...



    Sub ProcessShapes()

    Dim oSh As Shape

    For Each oSh In ActivePresentation.Slides(1).Shapes
    If oSh.Type = msoGroup Then
    Debug.Print "GROUP" & vbTab & oSh.Name & vbTab & oSh.ZOrderPosition

    Call DealWithGroup(oSh)
    Else
    Debug.Print oSh.Name & vbTab & oSh.ZOrderPosition
    End If
    Next

    End Sub

    Sub DealWithGroup(oSh As Shape)
    Dim x As Long
    For x = 1 To oSh.GroupItems.Count
    If oSh.GroupItems(x).Type = msoGroup Then
    Call DealWithGroup(oSh.GroupItems(x))
    Else
    Debug.Print "GROUP ITEM" & vbTab & oSh.GroupItems(x).Name & vbTab & oSh.GroupItems(x).ZOrderPosition
    End If
    Next
    End Sub


    And to answer Peter's further (excellent) question, this should work:



    Sub TestIndexOf()
    MsgBox IndexOf(ActiveWindow.Selection.ShapeRange(1))
    End Sub

    Function IndexOf(oSh As Shape) As Long

    Dim x As Long

    With ActiveWindow.Selection.SlideRange.Shapes
    For x = 1 To .Count
    If .Item(x).Name = oSh.Name Then
    ' Found it, report it
    IndexOf = x
    End If
    Next
    End With
    End Function





    share|improve this answer














    When you group a selection of shapes, the group becomes a new shape appended to the end of the previous z-order position. All of the individual shapes within the group are appended to the z-order after the group shape itself.



    I can't find a way of determining which individual item within a group is selected (sub-selected, I guess we should say, since the original parent group remains selected and that's what PPT returns when you query ActiveWindow.Selection.ShapeRange(1).



    To identify the currently subselected item within a group, you can use this as a starting point:



    Sub WorkWithSubSelectedShapes()
    ' Do stuff with sub-selected shapes within a group
    ' Courtesy of Andy Pope

    Dim oSh As Shape
    Dim oGSh As Shape
    Dim x As Long

    Set oSh = ActiveWindow.Selection.ShapeRange(1)

    ' Do something with each shape in the group:
    For Each oGSh In oSh.GroupItems
    Debug.Print oGSh.TextFrame.TextRange.Text
    Next

    ' Now do something with each SUB-SELECTED
    ' shape within the group
    With ActiveWindow.Selection.ChildShapeRange
    For x = 1 To .Count
    Debug.Print .Item(x).Name
    Debug.Print .Item(x).TextFrame.TextRange.Text
    Next
    End With

    End Sub


    Here's some code that may help generally in processing shapes/groups. It takes account of the fact that there might be groups within groups (within groups (within groups)) ...



    Sub ProcessShapes()

    Dim oSh As Shape

    For Each oSh In ActivePresentation.Slides(1).Shapes
    If oSh.Type = msoGroup Then
    Debug.Print "GROUP" & vbTab & oSh.Name & vbTab & oSh.ZOrderPosition

    Call DealWithGroup(oSh)
    Else
    Debug.Print oSh.Name & vbTab & oSh.ZOrderPosition
    End If
    Next

    End Sub

    Sub DealWithGroup(oSh As Shape)
    Dim x As Long
    For x = 1 To oSh.GroupItems.Count
    If oSh.GroupItems(x).Type = msoGroup Then
    Call DealWithGroup(oSh.GroupItems(x))
    Else
    Debug.Print "GROUP ITEM" & vbTab & oSh.GroupItems(x).Name & vbTab & oSh.GroupItems(x).ZOrderPosition
    End If
    Next
    End Sub


    And to answer Peter's further (excellent) question, this should work:



    Sub TestIndexOf()
    MsgBox IndexOf(ActiveWindow.Selection.ShapeRange(1))
    End Sub

    Function IndexOf(oSh As Shape) As Long

    Dim x As Long

    With ActiveWindow.Selection.SlideRange.Shapes
    For x = 1 To .Count
    If .Item(x).Name = oSh.Name Then
    ' Found it, report it
    IndexOf = x
    End If
    Next
    End With
    End Function






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 14 at 15:15

























    answered Nov 12 at 15:42









    Steve Rindsberg

    10.1k11526




    10.1k11526








    • 1




      Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
      – Peter
      Nov 14 at 22:58










    • @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
      – Steve Rindsberg
      Nov 15 at 19:02














    • 1




      Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
      – Peter
      Nov 14 at 22:58










    • @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
      – Steve Rindsberg
      Nov 15 at 19:02








    1




    1




    Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
    – Peter
    Nov 14 at 22:58




    Thanks @SteveRindsberg I had hoped for a more clean way (e.g., like ZOrderPosition without having to loop through shapes) but i guess this gets the job done. One small edit i would make is to change it to compare .ID instead of .Name since (as far as i understand) the ID is unique while the Name is not. Then it will also work if multiple shapes on the slide has the same name.
    – Peter
    Nov 14 at 22:58












    @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
    – Steve Rindsberg
    Nov 15 at 19:02




    @Peter Good point. While names are theoretically unique, PowerPoint has a habit of sometimes creating multiple same-named shape, which can cause all sorts of odd problems.
    – Steve Rindsberg
    Nov 15 at 19:02













    0














    Try the few lines of code and yow will get names of all the shapes in immediate window (Cttl+G to view Immediate window)



    Dim shp As Shape, I As Integer
    For Each shp In ActivePresentation.Slides(1).Shapes
    I = I + 1
    Debug.Print "Index=" & I & " Name= " & shp.Name & " ID= " & shp.Id & " Type= " & shp.Type
    Next





    share|improve this answer


























      0














      Try the few lines of code and yow will get names of all the shapes in immediate window (Cttl+G to view Immediate window)



      Dim shp As Shape, I As Integer
      For Each shp In ActivePresentation.Slides(1).Shapes
      I = I + 1
      Debug.Print "Index=" & I & " Name= " & shp.Name & " ID= " & shp.Id & " Type= " & shp.Type
      Next





      share|improve this answer
























        0












        0








        0






        Try the few lines of code and yow will get names of all the shapes in immediate window (Cttl+G to view Immediate window)



        Dim shp As Shape, I As Integer
        For Each shp In ActivePresentation.Slides(1).Shapes
        I = I + 1
        Debug.Print "Index=" & I & " Name= " & shp.Name & " ID= " & shp.Id & " Type= " & shp.Type
        Next





        share|improve this answer












        Try the few lines of code and yow will get names of all the shapes in immediate window (Cttl+G to view Immediate window)



        Dim shp As Shape, I As Integer
        For Each shp In ActivePresentation.Slides(1).Shapes
        I = I + 1
        Debug.Print "Index=" & I & " Name= " & shp.Name & " ID= " & shp.Id & " Type= " & shp.Type
        Next






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 0:49









        Ahmed AU

        67028




        67028






























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