Java: passing variable one time but different values












0














I'm a Java newbie and I have this question.



Can I pass a variable to a method multiple times without creating a new object?



For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".



If I write:



String x = Scanner.next();


And I create the object passing the x variable, when I write,



System.out.println(obj.m);


If the input was h It will print out "example1"



But if write down this after what i showed up:



x = Scanner.next();
System.out.println(obj.m);


Whatever character I write down the output will be "example 1"



If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time



So is it possible to pass a variable only one time with a value that changes over time without creating a new object?










share|improve this question
























  • Your question does not make sense. We don't know what obj is. Post a MCVE.
    – Elliott Frisch
    Nov 10 at 20:32










  • can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
    – dubes
    Nov 10 at 20:37
















0














I'm a Java newbie and I have this question.



Can I pass a variable to a method multiple times without creating a new object?



For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".



If I write:



String x = Scanner.next();


And I create the object passing the x variable, when I write,



System.out.println(obj.m);


If the input was h It will print out "example1"



But if write down this after what i showed up:



x = Scanner.next();
System.out.println(obj.m);


Whatever character I write down the output will be "example 1"



If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time



So is it possible to pass a variable only one time with a value that changes over time without creating a new object?










share|improve this question
























  • Your question does not make sense. We don't know what obj is. Post a MCVE.
    – Elliott Frisch
    Nov 10 at 20:32










  • can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
    – dubes
    Nov 10 at 20:37














0












0








0







I'm a Java newbie and I have this question.



Can I pass a variable to a method multiple times without creating a new object?



For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".



If I write:



String x = Scanner.next();


And I create the object passing the x variable, when I write,



System.out.println(obj.m);


If the input was h It will print out "example1"



But if write down this after what i showed up:



x = Scanner.next();
System.out.println(obj.m);


Whatever character I write down the output will be "example 1"



If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time



So is it possible to pass a variable only one time with a value that changes over time without creating a new object?










share|improve this question















I'm a Java newbie and I have this question.



Can I pass a variable to a method multiple times without creating a new object?



For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".



If I write:



String x = Scanner.next();


And I create the object passing the x variable, when I write,



System.out.println(obj.m);


If the input was h It will print out "example1"



But if write down this after what i showed up:



x = Scanner.next();
System.out.println(obj.m);


Whatever character I write down the output will be "example 1"



If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time



So is it possible to pass a variable only one time with a value that changes over time without creating a new object?







java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 20:34









Pushpesh Kumar Rajwanshi

4,8141826




4,8141826










asked Nov 10 at 20:30









Akk

35




35












  • Your question does not make sense. We don't know what obj is. Post a MCVE.
    – Elliott Frisch
    Nov 10 at 20:32










  • can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
    – dubes
    Nov 10 at 20:37


















  • Your question does not make sense. We don't know what obj is. Post a MCVE.
    – Elliott Frisch
    Nov 10 at 20:32










  • can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
    – dubes
    Nov 10 at 20:37
















Your question does not make sense. We don't know what obj is. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32




Your question does not make sense. We don't know what obj is. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32












can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
– dubes
Nov 10 at 20:37




can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the m assignment everytime you change the value of x
– dubes
Nov 10 at 20:37












2 Answers
2






active

oldest

votes


















1














If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:



public class Test {
public String m;

public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}


If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:



public class MainClass {
public static void main(String args) {
Test obj = new Test();

String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1

x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}





share|improve this answer



















  • 1




    Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
    – Francisco Delmar Kurpiel
    Nov 10 at 22:52










  • Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
    – Akk
    Nov 21 at 6:55





















0














As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you



import java.util.Scanner;

public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}

class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}





share|improve this answer





















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:



    public class Test {
    public String m;

    public void testMethod(String x) {
    if (x.equals("h")) {
    m = "example1";
    } else if (x.equals("f")) {
    m = "example2";
    } else {
    m = "other";
    }
    }
    }


    If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:



    public class MainClass {
    public static void main(String args) {
    Test obj = new Test();

    String x = "h";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example1

    x = "f";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example2
    }
    }





    share|improve this answer



















    • 1




      Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
      – Francisco Delmar Kurpiel
      Nov 10 at 22:52










    • Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
      – Akk
      Nov 21 at 6:55


















    1














    If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:



    public class Test {
    public String m;

    public void testMethod(String x) {
    if (x.equals("h")) {
    m = "example1";
    } else if (x.equals("f")) {
    m = "example2";
    } else {
    m = "other";
    }
    }
    }


    If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:



    public class MainClass {
    public static void main(String args) {
    Test obj = new Test();

    String x = "h";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example1

    x = "f";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example2
    }
    }





    share|improve this answer



















    • 1




      Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
      – Francisco Delmar Kurpiel
      Nov 10 at 22:52










    • Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
      – Akk
      Nov 21 at 6:55
















    1












    1








    1






    If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:



    public class Test {
    public String m;

    public void testMethod(String x) {
    if (x.equals("h")) {
    m = "example1";
    } else if (x.equals("f")) {
    m = "example2";
    } else {
    m = "other";
    }
    }
    }


    If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:



    public class MainClass {
    public static void main(String args) {
    Test obj = new Test();

    String x = "h";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example1

    x = "f";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example2
    }
    }





    share|improve this answer














    If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:



    public class Test {
    public String m;

    public void testMethod(String x) {
    if (x.equals("h")) {
    m = "example1";
    } else if (x.equals("f")) {
    m = "example2";
    } else {
    m = "other";
    }
    }
    }


    If you created an object from this class in a main method and pass in different values of x as the argument for testMethod(), the value of m would change:



    public class MainClass {
    public static void main(String args) {
    Test obj = new Test();

    String x = "h";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example1

    x = "f";
    obj.testMethod(x);
    System.out.println(obj.m); // prints example2
    }
    }






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 10 at 22:40

























    answered Nov 10 at 20:52









    Sahil Makhijani

    538




    538








    • 1




      Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
      – Francisco Delmar Kurpiel
      Nov 10 at 22:52










    • Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
      – Akk
      Nov 21 at 6:55
















    • 1




      Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
      – Francisco Delmar Kurpiel
      Nov 10 at 22:52










    • Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
      – Akk
      Nov 21 at 6:55










    1




    1




    Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
    – Francisco Delmar Kurpiel
    Nov 10 at 22:52




    Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
    – Francisco Delmar Kurpiel
    Nov 10 at 22:52












    Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
    – Akk
    Nov 21 at 6:55






    Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
    – Akk
    Nov 21 at 6:55















    0














    As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you



    import java.util.Scanner;

    public class A {
    public static void main(String args) {
    Scanner scanner = new Scanner(System.in);
    ClassOfYourObject object = new ClassOfYourObject();
    while (true) {
    System.out.print("Enter letter : ");
    String x = scanner.next();
    object.yourMethodToPrint(x);
    }
    }
    }

    class ClassOfYourObject {
    void yourMethodToPrint(String value) {
    if (value.equals("h")) {
    System.out.println("example1");
    } else if (value.equals("f")) {
    System.out.println("example2");
    } else {
    System.out.println("Invalid letter");
    }
    }
    }





    share|improve this answer


























      0














      As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you



      import java.util.Scanner;

      public class A {
      public static void main(String args) {
      Scanner scanner = new Scanner(System.in);
      ClassOfYourObject object = new ClassOfYourObject();
      while (true) {
      System.out.print("Enter letter : ");
      String x = scanner.next();
      object.yourMethodToPrint(x);
      }
      }
      }

      class ClassOfYourObject {
      void yourMethodToPrint(String value) {
      if (value.equals("h")) {
      System.out.println("example1");
      } else if (value.equals("f")) {
      System.out.println("example2");
      } else {
      System.out.println("Invalid letter");
      }
      }
      }





      share|improve this answer
























        0












        0








        0






        As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you



        import java.util.Scanner;

        public class A {
        public static void main(String args) {
        Scanner scanner = new Scanner(System.in);
        ClassOfYourObject object = new ClassOfYourObject();
        while (true) {
        System.out.print("Enter letter : ");
        String x = scanner.next();
        object.yourMethodToPrint(x);
        }
        }
        }

        class ClassOfYourObject {
        void yourMethodToPrint(String value) {
        if (value.equals("h")) {
        System.out.println("example1");
        } else if (value.equals("f")) {
        System.out.println("example2");
        } else {
        System.out.println("Invalid letter");
        }
        }
        }





        share|improve this answer












        As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you



        import java.util.Scanner;

        public class A {
        public static void main(String args) {
        Scanner scanner = new Scanner(System.in);
        ClassOfYourObject object = new ClassOfYourObject();
        while (true) {
        System.out.print("Enter letter : ");
        String x = scanner.next();
        object.yourMethodToPrint(x);
        }
        }
        }

        class ClassOfYourObject {
        void yourMethodToPrint(String value) {
        if (value.equals("h")) {
        System.out.println("example1");
        } else if (value.equals("f")) {
        System.out.println("example2");
        } else {
        System.out.println("Invalid letter");
        }
        }
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 10 at 20:52









        Sand

        752112




        752112






























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