Java: passing variable one time but different values
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
add a comment |
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
Your question does not make sense. We don't know whatobj
is. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate them
assignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
add a comment |
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
I'm a Java newbie and I have this question.
Can I pass a variable to a method multiple times without creating a new object?
For example, if I have a variable x which is the user input, another variable called m and a method were: if x is "h" then m is "example1" else if x is "f" m is "example2".
If I write:
String x = Scanner.next();
And I create the object passing the x variable, when I write,
System.out.println(obj.m);
If the input was h It will print out "example1"
But if write down this after what i showed up:
x = Scanner.next();
System.out.println(obj.m);
Whatever character I write down the output will be "example 1"
If I type "f" the first time the output will be "example2"
But the second system.out.println() will print "example2" eventually if I typed "h" the second time
So is it possible to pass a variable only one time with a value that changes over time without creating a new object?
java
java
edited Nov 10 at 20:34
Pushpesh Kumar Rajwanshi
4,8141826
4,8141826
asked Nov 10 at 20:30
Akk
35
35
Your question does not make sense. We don't know whatobj
is. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate them
assignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
add a comment |
Your question does not make sense. We don't know whatobj
is. Post a MCVE.
– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate them
assignment everytime you change the value ofx
– dubes
Nov 10 at 20:37
Your question does not make sense. We don't know what
obj
is. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
Your question does not make sense. We don't know what
obj
is. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
m
assignment everytime you change the value of x
– dubes
Nov 10 at 20:37
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
m
assignment everytime you change the value of x
– dubes
Nov 10 at 20:37
add a comment |
2 Answers
2
active
oldest
votes
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x
as the argument for testMethod()
, the value of m
would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
add a comment |
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243137%2fjava-passing-variable-one-time-but-different-values%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x
as the argument for testMethod()
, the value of m
would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
add a comment |
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x
as the argument for testMethod()
, the value of m
would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
add a comment |
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x
as the argument for testMethod()
, the value of m
would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
If I understand your question correctly, then yes, you can pass a variable to a method multiple times without creating a new object. Let's say you create a class like this:
public class Test {
public String m;
public void testMethod(String x) {
if (x.equals("h")) {
m = "example1";
} else if (x.equals("f")) {
m = "example2";
} else {
m = "other";
}
}
}
If you created an object from this class in a main method and pass in different values of x
as the argument for testMethod()
, the value of m
would change:
public class MainClass {
public static void main(String args) {
Test obj = new Test();
String x = "h";
obj.testMethod(x);
System.out.println(obj.m); // prints example1
x = "f";
obj.testMethod(x);
System.out.println(obj.m); // prints example2
}
}
edited Nov 10 at 22:40
answered Nov 10 at 20:52
Sahil Makhijani
538
538
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
add a comment |
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
1
1
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Instead of x.equals("h") I always use "h".equals(x), because it works even if x is null. No NullPointerException.
– Francisco Delmar Kurpiel
Nov 10 at 22:52
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
Thank you so much for the answer! But would a "Setter" method do tthe trick as well?
– Akk
Nov 21 at 6:55
add a comment |
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
add a comment |
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
As I understood your question, I have added a solution that will create the object you mentioned one time and call the method inside it repeatedly as you enter values. This might help you
import java.util.Scanner;
public class A {
public static void main(String args) {
Scanner scanner = new Scanner(System.in);
ClassOfYourObject object = new ClassOfYourObject();
while (true) {
System.out.print("Enter letter : ");
String x = scanner.next();
object.yourMethodToPrint(x);
}
}
}
class ClassOfYourObject {
void yourMethodToPrint(String value) {
if (value.equals("h")) {
System.out.println("example1");
} else if (value.equals("f")) {
System.out.println("example2");
} else {
System.out.println("Invalid letter");
}
}
}
answered Nov 10 at 20:52
Sand
752112
752112
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53243137%2fjava-passing-variable-one-time-but-different-values%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Your question does not make sense. We don't know what
obj
is. Post a MCVE.– Elliott Frisch
Nov 10 at 20:32
can you show the logic of how "m" is assigned a value? most probably, you need to evaluate the
m
assignment everytime you change the value ofx
– dubes
Nov 10 at 20:37