Wsrtjtyk

I am beginner to c programming. Hope you guys can help me.

i=0;

while(i++<12)

printf("%dn",i);

My question not regarding operators or how the code works. I have checked various forms so i know what this piece of code does and the final value in i will be 13. What I want to know is this:

From my perspective operators must follow operator priority(preference). So ++ must be evaluated before <.
Operator priority link: https://www.geeksforgeeks.org/c-operator-precedence-associativity/

lets i=3 for now,

Step 1:while(i++<12)

Step 2:while((i+1)<12)

Step 3:while(4<12)

Step 4:true and enters while loop

If operator preference is neglected(but I don't know why):

Step 1:while(i++<12)

Step 2:while(i<12)

Step 3:while(3<12) which returns value 1

Step 4:while(1++) operator ++ on the return value 1 from above step

Step 5:while(2) which is true and enters while loop

I hope you guys can understand my question. Please help.

An example:

i = 0;

while(i<12)       //compare i with 12

    printf("%dn",i);



i = 0; 

while(i++<12)        //compare i with 12 and THEN i=i+1

    printf("%dn",i);



i = 0;

while(++i<12)        //first i=i+1 and then compare i with 12

    printf("%dn",i);