how to check if a div with a certain value is duplicated and then hide the duplicated div in jQuery

up vote
0
down vote

favorite

I am having trouble checking if a div with a certain value is duplicated and then hiding that duplicated div.

Here's my code:

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

What javascript have you tried?
– Nick Parsons
Nov 10 at 5:45

@NickParsons Nothing yet because I don't know where to start
– Ajay Nath
Nov 10 at 5:53

add a comment |

up vote
0
down vote

favorite

I am having trouble checking if a div with a certain value is duplicated and then hiding that duplicated div.

Here's my code:

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

What javascript have you tried?
– Nick Parsons
Nov 10 at 5:45

@NickParsons Nothing yet because I don't know where to start
– Ajay Nath
Nov 10 at 5:53

add a comment |

up vote
0
down vote

favorite

I am having trouble checking if a div with a certain value is duplicated and then hiding that duplicated div.

Here's my code:

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

I am having trouble checking if a div with a certain value is duplicated and then hiding that duplicated div.

Here's my code:

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

javascript jquery html

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

edited Nov 10 at 5:45

Nick Parsons

4,3712721

edited Nov 10 at 5:45

Nick Parsons

4,3712721

edited Nov 10 at 5:45

Nick Parsons

4,3712721

asked Nov 10 at 5:44

Ajay Nath

asked Nov 10 at 5:44

Ajay Nath

asked Nov 10 at 5:44

Ajay Nath

What javascript have you tried?
– Nick Parsons
Nov 10 at 5:45

@NickParsons Nothing yet because I don't know where to start
– Ajay Nath
Nov 10 at 5:53

add a comment |

What javascript have you tried?
– Nick Parsons
Nov 10 at 5:45

@NickParsons Nothing yet because I don't know where to start
– Ajay Nath
Nov 10 at 5:53

What javascript have you tried?
– Nick Parsons
Nov 10 at 5:45

@NickParsons Nothing yet because I don't know where to start
– Ajay Nath
Nov 10 at 5:53

add a comment |

4 Answers
4

active

oldest

votes

up vote
0
down vote

accepted

Try this,I hope this is what you are looking for.

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:58

Ashwin

1616

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

add a comment |

up vote
0
down vote

You need to loop through all div classes and then check if the current div class is already exist, this will check using div class html content. Script is like this:

var divs = ;

$(".div").each(function(i,v){

   if(divs.indexOf(v.html())>=0){

       divs.push(v.html()); //collect all unique divs

   }else{

      //this is the duplicate div. need to hide it.

      $(this).hide();

   }

});

answered Nov 10 at 5:56

McBern

18826

add a comment |

up vote
0
down vote

well, it depends, if you want to check if hes inside text is the same then you can run over all the divs and use something like array to check if already exists.

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:59

Talg123

21118

add a comment |

up vote
0
down vote

You can wrap all the elements you want to remove the duplicates in a class .container
You can then get all the children of this element, and turn it into an array using .toArray(). You can then use a Set to remove all the duplicates in this array:
and then use a Set to remove the duplicates within the array and then display this:

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

If you wish you could use this as a one-liner:

$('.container').html([...new Set($('.container').children().toArray().map(e => ''+e.outerHTML))].join(''));

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

add a comment |

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

up vote
0
down vote

accepted

Try this,I hope this is what you are looking for.

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:58

Ashwin

1616

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

add a comment |

up vote
0
down vote

accepted

Try this,I hope this is what you are looking for.

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:58

Ashwin

1616

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

add a comment |

up vote
0
down vote

accepted

Try this,I hope this is what you are looking for.

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:58

Ashwin

1616

Try this,I hope this is what you are looking for.

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

var a = new Array();



$('.div').each(function(index) {

    text = $(this).text();

    if($.inArray(text, a)!=-1){

        $(this).closest('.div').hide();

    }else{

        a.push(text);

    }

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:58

Ashwin

1616

answered Nov 10 at 5:58

Ashwin

1616

answered Nov 10 at 5:58

Ashwin

1616

answered Nov 10 at 5:58

Ashwin

1616

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

add a comment |

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

thanks so much this has fixed my problem :)
– Ajay Nath
Nov 10 at 7:25

ok..Happy to help you..All the best :)
– Ashwin
Nov 10 at 9:03

add a comment |

up vote
0
down vote

You need to loop through all div classes and then check if the current div class is already exist, this will check using div class html content. Script is like this:

var divs = ;

$(".div").each(function(i,v){

   if(divs.indexOf(v.html())>=0){

       divs.push(v.html()); //collect all unique divs

   }else{

      //this is the duplicate div. need to hide it.

      $(this).hide();

   }

});

answered Nov 10 at 5:56

McBern

18826

add a comment |

up vote
0
down vote

You need to loop through all div classes and then check if the current div class is already exist, this will check using div class html content. Script is like this:

var divs = ;

$(".div").each(function(i,v){

   if(divs.indexOf(v.html())>=0){

       divs.push(v.html()); //collect all unique divs

   }else{

      //this is the duplicate div. need to hide it.

      $(this).hide();

   }

});

answered Nov 10 at 5:56

McBern

18826

add a comment |

up vote
0
down vote

You need to loop through all div classes and then check if the current div class is already exist, this will check using div class html content. Script is like this:

var divs = ;

$(".div").each(function(i,v){

   if(divs.indexOf(v.html())>=0){

       divs.push(v.html()); //collect all unique divs

   }else{

      //this is the duplicate div. need to hide it.

      $(this).hide();

   }

});

answered Nov 10 at 5:56

McBern

18826

You need to loop through all div classes and then check if the current div class is already exist, this will check using div class html content. Script is like this:

var divs = ;

$(".div").each(function(i,v){

   if(divs.indexOf(v.html())>=0){

       divs.push(v.html()); //collect all unique divs

   }else{

      //this is the duplicate div. need to hide it.

      $(this).hide();

   }

});

answered Nov 10 at 5:56

McBern

18826

answered Nov 10 at 5:56

McBern

18826

answered Nov 10 at 5:56

McBern

18826

answered Nov 10 at 5:56

McBern

18826

add a comment |

up vote
0
down vote

well, it depends, if you want to check if hes inside text is the same then you can run over all the divs and use something like array to check if already exists.

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:59

Talg123

21118

add a comment |

up vote
0
down vote

well, it depends, if you want to check if hes inside text is the same then you can run over all the divs and use something like array to check if already exists.

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:59

Talg123

21118

add a comment |

up vote
0
down vote

well, it depends, if you want to check if hes inside text is the same then you can run over all the divs and use something like array to check if already exists.

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:59

Talg123

21118

well, it depends, if you want to check if hes inside text is the same then you can run over all the divs and use something like array to check if already exists.

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

var exists = ;

$(document).ready(function(){

  

  $(".div").each(function(){

    var text = $(this).text();

    if(exists.indexOf(text) != -1){

      $(this).hide();

    }else{

      exists.push(text);

    }

  })

  

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>





<div class="div">Java</div>

<div class="div">Python</div>

<div class="div">Php</div>



<div class="div">Java</div>

<div class="div">Java</div>

<div class="div">Java</div>

answered Nov 10 at 5:59

Talg123

21118

answered Nov 10 at 5:59

Talg123

21118

answered Nov 10 at 5:59

Talg123

21118

answered Nov 10 at 5:59

Talg123

21118

add a comment |

up vote
0
down vote

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

If you wish you could use this as a one-liner:

$('.container').html([...new Set($('.container').children().toArray().map(e => ''+e.outerHTML))].join(''));

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

add a comment |

up vote
0
down vote

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

If you wish you could use this as a one-liner:

$('.container').html([...new Set($('.container').children().toArray().map(e => ''+e.outerHTML))].join(''));

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

add a comment |

up vote
0
down vote

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

If you wish you could use this as a one-liner:

$('.container').html([...new Set($('.container').children().toArray().map(e => ''+e.outerHTML))].join(''));

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

If you wish you could use this as a one-liner:

$('.container').html([...new Set($('.container').children().toArray().map(e => ''+e.outerHTML))].join(''));

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

const unique = $('.container').children().toArray().map(e => '' + e.outerHTML);

const elems = [...new Set(unique)].join('');

$('.container').html(elems);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <div class="div">Java</div>

  <br />

  <div class="div">Python</div>

  <div class="div">Php</div>

  

  <div class="div">Java</div>

  <div class="div">Java</div>

  <div class="div">Java</div>

</div>

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

edited Nov 10 at 6:11

answered Nov 10 at 6:05

Nick Parsons

4,3712721

answered Nov 10 at 6:05

Nick Parsons

4,3712721

answered Nov 10 at 6:05

Nick Parsons

4,3712721

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