Is there a way to detect if a block of code in the script itself contains a specific word
... and decide execution of that block based on the presence of that word?
For example I have this:
for frame in range(10):
with open('frame_init.gro', 'w') as g:
# do something
with open('frame_next.gro', 'w') as h:
# do something
When "frame" reaches 9, I don't want the whole with open('frame_next.gro', 'w') as h
block to execute at all. Of course I have considered just encasing it in a if frame != 9
but my actual entire code is really long so it would be nice if I could just scan my script within the script itself if it is possible.
For those curious about what other things frame_next.gro
is involved in, the answer is lots of calculations
python
add a comment |
... and decide execution of that block based on the presence of that word?
For example I have this:
for frame in range(10):
with open('frame_init.gro', 'w') as g:
# do something
with open('frame_next.gro', 'w') as h:
# do something
When "frame" reaches 9, I don't want the whole with open('frame_next.gro', 'w') as h
block to execute at all. Of course I have considered just encasing it in a if frame != 9
but my actual entire code is really long so it would be nice if I could just scan my script within the script itself if it is possible.
For those curious about what other things frame_next.gro
is involved in, the answer is lots of calculations
python
This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56
add a comment |
... and decide execution of that block based on the presence of that word?
For example I have this:
for frame in range(10):
with open('frame_init.gro', 'w') as g:
# do something
with open('frame_next.gro', 'w') as h:
# do something
When "frame" reaches 9, I don't want the whole with open('frame_next.gro', 'w') as h
block to execute at all. Of course I have considered just encasing it in a if frame != 9
but my actual entire code is really long so it would be nice if I could just scan my script within the script itself if it is possible.
For those curious about what other things frame_next.gro
is involved in, the answer is lots of calculations
python
... and decide execution of that block based on the presence of that word?
For example I have this:
for frame in range(10):
with open('frame_init.gro', 'w') as g:
# do something
with open('frame_next.gro', 'w') as h:
# do something
When "frame" reaches 9, I don't want the whole with open('frame_next.gro', 'w') as h
block to execute at all. Of course I have considered just encasing it in a if frame != 9
but my actual entire code is really long so it would be nice if I could just scan my script within the script itself if it is possible.
For those curious about what other things frame_next.gro
is involved in, the answer is lots of calculations
python
python
asked Nov 12 '18 at 4:57
sneedshelp
14
14
This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56
add a comment |
This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56
This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56
add a comment |
1 Answer
1
active
oldest
votes
You can do something like this:
a = 0
b = 1
print a + b
with open(__file__, 'r') as f:
lines = f.read().split('n')
val = int(lines[0].split(' = ')[-1])
new_line = 'a = {}'.format(val+1)
new_file = 'n'.join([new_line] + lines[1:])
with open(__file__, 'w') as f:
f.write('n'.join([new_line] + lines[1:]))
From here:
How can I make a python script change itself?
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can do something like this:
a = 0
b = 1
print a + b
with open(__file__, 'r') as f:
lines = f.read().split('n')
val = int(lines[0].split(' = ')[-1])
new_line = 'a = {}'.format(val+1)
new_file = 'n'.join([new_line] + lines[1:])
with open(__file__, 'w') as f:
f.write('n'.join([new_line] + lines[1:]))
From here:
How can I make a python script change itself?
add a comment |
You can do something like this:
a = 0
b = 1
print a + b
with open(__file__, 'r') as f:
lines = f.read().split('n')
val = int(lines[0].split(' = ')[-1])
new_line = 'a = {}'.format(val+1)
new_file = 'n'.join([new_line] + lines[1:])
with open(__file__, 'w') as f:
f.write('n'.join([new_line] + lines[1:]))
From here:
How can I make a python script change itself?
add a comment |
You can do something like this:
a = 0
b = 1
print a + b
with open(__file__, 'r') as f:
lines = f.read().split('n')
val = int(lines[0].split(' = ')[-1])
new_line = 'a = {}'.format(val+1)
new_file = 'n'.join([new_line] + lines[1:])
with open(__file__, 'w') as f:
f.write('n'.join([new_line] + lines[1:]))
From here:
How can I make a python script change itself?
You can do something like this:
a = 0
b = 1
print a + b
with open(__file__, 'r') as f:
lines = f.read().split('n')
val = int(lines[0].split(' = ')[-1])
new_line = 'a = {}'.format(val+1)
new_file = 'n'.join([new_line] + lines[1:])
with open(__file__, 'w') as f:
f.write('n'.join([new_line] + lines[1:]))
From here:
How can I make a python script change itself?
edited Nov 12 '18 at 5:06
Klaus D.
7,37911834
7,37911834
answered Nov 12 '18 at 5:05
ChaosPredictor
1,91311624
1,91311624
add a comment |
add a comment |
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This sounds like an XY problem. Can you explain what problem you are trying to solve with it?
– Klaus D.
Nov 12 '18 at 5:05
wow, this is actually really condescending. Thanks a lot.
– sneedshelp
Nov 12 '18 at 9:56