How to receive error messages/exceptions from REST API using Swagger generated client code?
0
Below is the scala code snippet generated by Swagger Codegen.
def v4TestPostCheck(payload: TestResourceEntityRequest ): Option[TestResource] = {
val await = Try(Await.result(v4TestPostAsync(payload), Duration.Inf))
await match {
case Success(i) => Some(await.get)
case Failure(t) => None
}
}
def v4TestPostAsync(payload: TestResourceEntityRequest): Future[TestResource] = {
helper.v4TestPost(payload)
}
def v4TestPost(payload: TestResourceEntityRequest)(implicit reader: ClientResponseReader[TestResource], writer: RequestWriter[TestResourceEntityRequest]): Future[TestResource] = {
// create path and map variables
val path = (addFmt("/v4/test"))
// query params
val queryParams = new mutable.HashMap[String, String]
var headerParams = new mutable.HashMap[String, String]
headerParams = ApiInvoker.defaultHeaders
val resFuture = client.submit("POST", path, queryParams.toMap, headerParams.toMap, writer.write(payload))
resFuture flatMap { resp =>
println("response:"+resp.status)
println(resp.body)
println(resp.statusText) // this is printing the error message sent by Service, but how to return this message from this method
println(resp.uri)
Try {process(reader.read(resp))} match {
case Success(obj) => obj
case Failure(_) => throw new Exception("")
}
}
}
For success case, this code is receiving the TestResource object successfully.
However in case of any error/BadRequest, its receiving empty TestResource object.
Instead, it should report the error message thrown by Service.
How do we catch those messages using the swagger generated code?
swagger swagger-2.0 swagger-codegen
asked Nov 12 '18 at 5:03
Pratap D
4110
add a comment |
0
Below is the scala code snippet generated by Swagger Codegen.
def v4TestPostCheck(payload: TestResourceEntityRequest ): Option[TestResource] = {
val await = Try(Await.result(v4TestPostAsync(payload), Duration.Inf))
await match {
case Success(i) => Some(await.get)
case Failure(t) => None
}
}
def v4TestPostAsync(payload: TestResourceEntityRequest): Future[TestResource] = {
helper.v4TestPost(payload)
}
def v4TestPost(payload: TestResourceEntityRequest)(implicit reader: ClientResponseReader[TestResource], writer: RequestWriter[TestResourceEntityRequest]): Future[TestResource] = {
// create path and map variables
val path = (addFmt("/v4/test"))
// query params
val queryParams = new mutable.HashMap[String, String]
var headerParams = new mutable.HashMap[String, String]
headerParams = ApiInvoker.defaultHeaders
val resFuture = client.submit("POST", path, queryParams.toMap, headerParams.toMap, writer.write(payload))
resFuture flatMap { resp =>
println("response:"+resp.status)
println(resp.body)
println(resp.statusText) // this is printing the error message sent by Service, but how to return this message from this method
println(resp.uri)
Try {process(reader.read(resp))} match {
case Success(obj) => obj
case Failure(_) => throw new Exception("")
}
}
}
For success case, this code is receiving the TestResource object successfully.
However in case of any error/BadRequest, its receiving empty TestResource object.
Instead, it should report the error message thrown by Service.
How do we catch those messages using the swagger generated code?
swagger swagger-2.0 swagger-codegen
asked Nov 12 '18 at 5:03
Pratap D
4110
20 views but no response?
– Pratap D
Nov 12 '18 at 16:16
add a comment |
0
0
0
Below is the scala code snippet generated by Swagger Codegen.
def v4TestPostCheck(payload: TestResourceEntityRequest ): Option[TestResource] = {
val await = Try(Await.result(v4TestPostAsync(payload), Duration.Inf))
await match {
case Success(i) => Some(await.get)
case Failure(t) => None
}
}
def v4TestPostAsync(payload: TestResourceEntityRequest): Future[TestResource] = {
helper.v4TestPost(payload)
}
def v4TestPost(payload: TestResourceEntityRequest)(implicit reader: ClientResponseReader[TestResource], writer: RequestWriter[TestResourceEntityRequest]): Future[TestResource] = {
// create path and map variables
val path = (addFmt("/v4/test"))
// query params
val queryParams = new mutable.HashMap[String, String]
var headerParams = new mutable.HashMap[String, String]
headerParams = ApiInvoker.defaultHeaders
val resFuture = client.submit("POST", path, queryParams.toMap, headerParams.toMap, writer.write(payload))
resFuture flatMap { resp =>
println("response:"+resp.status)
println(resp.body)
println(resp.statusText) // this is printing the error message sent by Service, but how to return this message from this method
println(resp.uri)
Try {process(reader.read(resp))} match {
case Success(obj) => obj
case Failure(_) => throw new Exception("")
}
}
}
For success case, this code is receiving the TestResource object successfully.
However in case of any error/BadRequest, its receiving empty TestResource object.
Instead, it should report the error message thrown by Service.
How do we catch those messages using the swagger generated code?
swagger swagger-2.0 swagger-codegen
asked Nov 12 '18 at 5:03
Pratap D
4110
Below is the scala code snippet generated by Swagger Codegen.
def v4TestPostCheck(payload: TestResourceEntityRequest ): Option[TestResource] = {
val await = Try(Await.result(v4TestPostAsync(payload), Duration.Inf))
await match {
case Success(i) => Some(await.get)
case Failure(t) => None
}
}
def v4TestPostAsync(payload: TestResourceEntityRequest): Future[TestResource] = {
helper.v4TestPost(payload)
}
def v4TestPost(payload: TestResourceEntityRequest)(implicit reader: ClientResponseReader[TestResource], writer: RequestWriter[TestResourceEntityRequest]): Future[TestResource] = {
// create path and map variables
val path = (addFmt("/v4/test"))
// query params
val queryParams = new mutable.HashMap[String, String]
var headerParams = new mutable.HashMap[String, String]
headerParams = ApiInvoker.defaultHeaders
val resFuture = client.submit("POST", path, queryParams.toMap, headerParams.toMap, writer.write(payload))
resFuture flatMap { resp =>
println("response:"+resp.status)
println(resp.body)
println(resp.statusText) // this is printing the error message sent by Service, but how to return this message from this method
println(resp.uri)
Try {process(reader.read(resp))} match {
case Success(obj) => obj
case Failure(_) => throw new Exception("")
}
}
}
For success case, this code is receiving the TestResource object successfully.
However in case of any error/BadRequest, its receiving empty TestResource object.
Instead, it should report the error message thrown by Service.
How do we catch those messages using the swagger generated code?
swagger swagger-2.0 swagger-codegen
swagger swagger-2.0 swagger-codegen
asked Nov 12 '18 at 5:03
Pratap D
4110
asked Nov 12 '18 at 5:03
Pratap D
4110
edited Nov 12 '18 at 5:27
asked Nov 12 '18 at 5:03
Pratap D
4110
asked Nov 12 '18 at 5:03
Pratap D
4110
asked Nov 12 '18 at 5:03
Pratap D
4110
4110
20 views but no response?
– Pratap D
Nov 12 '18 at 16:16
add a comment |
20 views but no response?
– Pratap D
Nov 12 '18 at 16:16
20 views but no response?
– Pratap D
Nov 12 '18 at 16:16
20 views but no response?
– Pratap D
Nov 12 '18 at 16:16
add a comment |
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20 views but no response?
– Pratap D
Nov 12 '18 at 16:16