laravel cannot display jsondata












0















I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question

























  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

    – Istiaque Ahmed
    Nov 19 '18 at 10:10













  • look at my edit It's will answer your questions

    – user8693711
    Nov 19 '18 at 10:18











  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

    – Yoram de Langen
    Nov 19 '18 at 10:18











  • I just saved the string.

    – user8693711
    Nov 19 '18 at 10:20
















0















I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question

























  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

    – Istiaque Ahmed
    Nov 19 '18 at 10:10













  • look at my edit It's will answer your questions

    – user8693711
    Nov 19 '18 at 10:18











  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

    – Yoram de Langen
    Nov 19 '18 at 10:18











  • I just saved the string.

    – user8693711
    Nov 19 '18 at 10:20














0












0








0








I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here










share|improve this question
















I'm try to use jsondata to display the results.

This is my output.
Now i just try to display the result



enter image description here



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$json = json_decode($justResults, true);


$aQuestions = array();
$aAnswers = array();
foreach($json as $sKey => $oItem) {
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


in pure php i just use a but in the laravel it's not work.



<div class="container"> 
<table class="table table-striped">
<thead>
<tr>
<?php foreach($aQuestions as $aQuestionsn){?>
<th scope="col"><?php echo $aQuestionsn; ?></th>
<?php }?>
</tr>
</thead>
<tbody>
<tr>
<?php foreach($aAnswers as $aAnswersn) {?>
<td><?php echo $aAnswersn;?></td>
<?php }?>
</tr>
</tbody>
</table>
</div>


How i can display the jsonstring ?



All i need look like this



enter image description here







php json laravel






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 10:17

























asked Nov 19 '18 at 10:04







user8693711




















  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

    – Istiaque Ahmed
    Nov 19 '18 at 10:10













  • look at my edit It's will answer your questions

    – user8693711
    Nov 19 '18 at 10:18











  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

    – Yoram de Langen
    Nov 19 '18 at 10:18











  • I just saved the string.

    – user8693711
    Nov 19 '18 at 10:20



















  • use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

    – Istiaque Ahmed
    Nov 19 '18 at 10:10













  • look at my edit It's will answer your questions

    – user8693711
    Nov 19 '18 at 10:18











  • How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

    – Yoram de Langen
    Nov 19 '18 at 10:18











  • I just saved the string.

    – user8693711
    Nov 19 '18 at 10:20

















use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

– Istiaque Ahmed
Nov 19 '18 at 10:10







use $json = json_encode($justResults, JSON_HEX_QUOT | JSON_HEX_APOS); instead of $json = json_decode($justResults, true); if you really need to make any json data. BTW why do you need json in your case? You can just pass the array from controller to view.

– Istiaque Ahmed
Nov 19 '18 at 10:10















look at my edit It's will answer your questions

– user8693711
Nov 19 '18 at 10:18





look at my edit It's will answer your questions

– user8693711
Nov 19 '18 at 10:18













How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

– Yoram de Langen
Nov 19 '18 at 10:18





How does your data column look like when it is saved? If it's escaped with " it probably means your JSON is encoded twice.

– Yoram de Langen
Nov 19 '18 at 10:18













I just saved the string.

– user8693711
Nov 19 '18 at 10:20





I just saved the string.

– user8693711
Nov 19 '18 at 10:20












2 Answers
2






active

oldest

votes


















2














well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer
























  • it's work thank you

    – user8693711
    Nov 20 '18 at 2:05



















0














At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer
























  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

    – user8693711
    Nov 19 '18 at 10:45













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer
























  • it's work thank you

    – user8693711
    Nov 20 '18 at 2:05
















2














well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer
























  • it's work thank you

    – user8693711
    Nov 20 '18 at 2:05














2












2








2







well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}





share|improve this answer













well i think in your case there is another array inside your array you need to go inside that array



foreach($aAnswers as $aAnswersn)
{
foreach ($aAnswersn as $value)
{
echo $value;
}
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 10:55









Adnan RasheedAdnan Rasheed

20423




20423













  • it's work thank you

    – user8693711
    Nov 20 '18 at 2:05



















  • it's work thank you

    – user8693711
    Nov 20 '18 at 2:05

















it's work thank you

– user8693711
Nov 20 '18 at 2:05





it's work thank you

– user8693711
Nov 20 '18 at 2:05













0














At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer
























  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

    – user8693711
    Nov 19 '18 at 10:45


















0














At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer
























  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

    – user8693711
    Nov 19 '18 at 10:45
















0












0








0







At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes






share|improve this answer













At least your json_encode is possibly in the wrong location, try this:



public function resultsurvey($survey_id)
{
//$results=;

$allResults= Results::where('survey_id', $survey_id)->get()->toArray();
$justResults=Results::select('results')->where('survey_id', $survey_id)->get();

$aQuestions = array();
$aAnswers = array();
// $justResults is a collection so loop through it
foreach($justResults as $sKey => $oItem) {
// $oItem is possibly JSON encoded at this stage
$oItem = json_decode($oItem, true);
array_push($aQuestions, $sKey);
array_push($aAnswers, $oItem);
}

dd($aQuestions , $aAnswers);
}


Please note all changes







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 10:21









Yoram de LangenYoram de Langen

3,91311727




3,91311727













  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

    – user8693711
    Nov 19 '18 at 10:45





















  • I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

    – user8693711
    Nov 19 '18 at 10:45



















I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

– user8693711
Nov 19 '18 at 10:45







I can't display my code is <div class="container"> <table class="table table-striped"> <thead> <tr> <?php foreach($aQuestions as $aQuestionsn){?> <th scope="col"><?php echo $aQuestionsn; ?></th> <?php }?> </tr> </thead> <tbody> <tr> <?php foreach($aAnswers as $aAnswersn) {?> <td><?php echo $aAnswersn;?></td> <?php }?> </tr> </tbody> </table> </div>

– user8693711
Nov 19 '18 at 10:45




















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