Swagger UI doesn't show module name in its url and
I have followed https://dzone.com/articles/spring-boot-restful-api-documentation-with-swagger and developing the Swagger using the springfox-swagger-ui and springfox-swagger2 version 2.9.2.
I used the below configurations, but I want module-name to be printed out here. Also, @Api(tags = "User Catalouge", description = "List Of Users"), description is deprecated.
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket productApi() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("guru.springframework.controllers"))
.paths(regex("/product.*"))
.build()
.apiInfo(metaData());
}
private ApiInfo metaData() {
ApiInfo apiInfo = new ApiInfo(
"Spring Boot REST API",
"Spring Boot REST API for Online Store",
"1.0",
"Terms of service",
new Contact("John Thompson", "https://springframework.guru/about/", "john@springfrmework.guru"),
"Apache License Version 2.0",
"https://www.apache.org/licenses/LICENSE-2.0");
return apiInfo;
}
}
swagger-2.0 springfox
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
add a comment |
I have followed https://dzone.com/articles/spring-boot-restful-api-documentation-with-swagger and developing the Swagger using the springfox-swagger-ui and springfox-swagger2 version 2.9.2.
I used the below configurations, but I want module-name to be printed out here. Also, @Api(tags = "User Catalouge", description = "List Of Users"), description is deprecated.
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket productApi() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("guru.springframework.controllers"))
.paths(regex("/product.*"))
.build()
.apiInfo(metaData());
}
private ApiInfo metaData() {
ApiInfo apiInfo = new ApiInfo(
"Spring Boot REST API",
"Spring Boot REST API for Online Store",
"1.0",
"Terms of service",
new Contact("John Thompson", "https://springframework.guru/about/", "john@springfrmework.guru"),
"Apache License Version 2.0",
"https://www.apache.org/licenses/LICENSE-2.0");
return apiInfo;
}
}
swagger-2.0 springfox
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
add a comment |
I have followed https://dzone.com/articles/spring-boot-restful-api-documentation-with-swagger and developing the Swagger using the springfox-swagger-ui and springfox-swagger2 version 2.9.2.
I used the below configurations, but I want module-name to be printed out here. Also, @Api(tags = "User Catalouge", description = "List Of Users"), description is deprecated.
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket productApi() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("guru.springframework.controllers"))
.paths(regex("/product.*"))
.build()
.apiInfo(metaData());
}
private ApiInfo metaData() {
ApiInfo apiInfo = new ApiInfo(
"Spring Boot REST API",
"Spring Boot REST API for Online Store",
"1.0",
"Terms of service",
new Contact("John Thompson", "https://springframework.guru/about/", "john@springfrmework.guru"),
"Apache License Version 2.0",
"https://www.apache.org/licenses/LICENSE-2.0");
return apiInfo;
}
}
swagger-2.0 springfox
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
I have followed https://dzone.com/articles/spring-boot-restful-api-documentation-with-swagger and developing the Swagger using the springfox-swagger-ui and springfox-swagger2 version 2.9.2.
I used the below configurations, but I want module-name to be printed out here. Also, @Api(tags = "User Catalouge", description = "List Of Users"), description is deprecated.
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket productApi() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("guru.springframework.controllers"))
.paths(regex("/product.*"))
.build()
.apiInfo(metaData());
}
private ApiInfo metaData() {
ApiInfo apiInfo = new ApiInfo(
"Spring Boot REST API",
"Spring Boot REST API for Online Store",
"1.0",
"Terms of service",
new Contact("John Thompson", "https://springframework.guru/about/", "john@springfrmework.guru"),
"Apache License Version 2.0",
"https://www.apache.org/licenses/LICENSE-2.0");
return apiInfo;
}
}
swagger-2.0 springfox
swagger-2.0 springfox
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
asked Nov 19 '18 at 14:55
PAAPAA
2,67522237
2,67522237
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You just need to set the servlet context path. Spring Boot & Swagger are smart enough to recognized the URL and take it in the url.
server.servlet.context-path=/product-details
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You just need to set the servlet context path. Spring Boot & Swagger are smart enough to recognized the URL and take it in the url.
server.servlet.context-path=/product-details
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
add a comment |
You just need to set the servlet context path. Spring Boot & Swagger are smart enough to recognized the URL and take it in the url.
server.servlet.context-path=/product-details
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
add a comment |
You just need to set the servlet context path. Spring Boot & Swagger are smart enough to recognized the URL and take it in the url.
server.servlet.context-path=/product-details
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
You just need to set the servlet context path. Spring Boot & Swagger are smart enough to recognized the URL and take it in the url.
server.servlet.context-path=/product-details
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
answered Nov 19 '18 at 16:46
PAAPAA
2,67522237
2,67522237
add a comment |
add a comment |
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