Getting a value of a python dict
I am getting a syntax error while trying to index a python dict:
(Pdb) o_model.flows
{(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>): <oemof.solph.network.Flow object at 0x7f3e9c50d5f8>}
Here is the key of the dict.:
(Pdb) o_model.flows.keys()
dict_keys([(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)])
So what I am assuming is the key of the dict is (<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)
Problem is that I get an syntax error, while trying to index the o_model.flows with the key, which is mentioned above.
Normally I was expecting to get the value(<oemof.solph.network.Flow object at 0x7f3e9c50d5f8>) of the dict via, but instead I get an syntax error:
(Pdb) o_model.flows[(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)]
*** SyntaxError: invalid syntax
What I do wrong?
Some Extras:
(Pdb) type(o_model.flows)
<class 'dict'>
python dictionary indexing
asked Nov 21 '18 at 11:00
oakcaoakca
354112
|
show 10 more comments
I am getting a syntax error while trying to index a python dict:
(Pdb) o_model.flows
{(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>): <oemof.solph.network.Flow object at 0x7f3e9c50d5f8>}
Here is the key of the dict.:
(Pdb) o_model.flows.keys()
dict_keys([(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)])
So what I am assuming is the key of the dict is (<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)
Problem is that I get an syntax error, while trying to index the o_model.flows with the key, which is mentioned above.
Normally I was expecting to get the value(<oemof.solph.network.Flow object at 0x7f3e9c50d5f8>) of the dict via, but instead I get an syntax error:
(Pdb) o_model.flows[(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)]
*** SyntaxError: invalid syntax
What I do wrong?
Some Extras:
(Pdb) type(o_model.flows)
<class 'dict'>
python dictionary indexing
asked Nov 21 '18 at 11:00
oakcaoakca
354112
3
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
1
I have no idea what aoemof.solph.network.Bus objectis (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict
– Robin Zigmond
Nov 21 '18 at 11:04
1
First, just check values in dictionary - useprintfunction. I guess you'll find out, that that one value is not dictionary key...
– kosist
Nov 21 '18 at 11:04
2
You can iterate over a dict without needing to know its keys, seevalues(),items(). But this dict looks really painful, show us the code that generatedo_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.
– smci
Nov 21 '18 at 11:08
|
show 10 more comments
I am getting a syntax error while trying to index a python dict:
(Pdb) o_model.flows
{(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>): <oemof.solph.network.Flow object at 0x7f3e9c50d5f8>}
Here is the key of the dict.:
(Pdb) o_model.flows.keys()
dict_keys([(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)])
So what I am assuming is the key of the dict is (<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)
Problem is that I get an syntax error, while trying to index the o_model.flows with the key, which is mentioned above.
Normally I was expecting to get the value(<oemof.solph.network.Flow object at 0x7f3e9c50d5f8>) of the dict via, but instead I get an syntax error:
(Pdb) o_model.flows[(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)]
*** SyntaxError: invalid syntax
What I do wrong?
Some Extras:
(Pdb) type(o_model.flows)
<class 'dict'>
python dictionary indexing
asked Nov 21 '18 at 11:00
oakcaoakca
354112
I am getting a syntax error while trying to index a python dict:
(Pdb) o_model.flows
{(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>): <oemof.solph.network.Flow object at 0x7f3e9c50d5f8>}
Here is the key of the dict.:
(Pdb) o_model.flows.keys()
dict_keys([(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)])
So what I am assuming is the key of the dict is (<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)
Problem is that I get an syntax error, while trying to index the o_model.flows with the key, which is mentioned above.
Normally I was expecting to get the value(<oemof.solph.network.Flow object at 0x7f3e9c50d5f8>) of the dict via, but instead I get an syntax error:
(Pdb) o_model.flows[(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)]
*** SyntaxError: invalid syntax
What I do wrong?
Some Extras:
(Pdb) type(o_model.flows)
<class 'dict'>
python dictionary indexing
python dictionary indexing
asked Nov 21 '18 at 11:00
oakcaoakca
354112
asked Nov 21 '18 at 11:00
oakcaoakca
354112
edited Nov 21 '18 at 11:21
oakca
asked Nov 21 '18 at 11:00
oakcaoakca
354112
asked Nov 21 '18 at 11:00
oakcaoakca
354112
asked Nov 21 '18 at 11:00
oakcaoakca
354112
354112
3
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
1
I have no idea what aoemof.solph.network.Bus objectis (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict
– Robin Zigmond
Nov 21 '18 at 11:04
1
First, just check values in dictionary - useprintfunction. I guess you'll find out, that that one value is not dictionary key...
– kosist
Nov 21 '18 at 11:04
2
You can iterate over a dict without needing to know its keys, seevalues(),items(). But this dict looks really painful, show us the code that generatedo_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.
– smci
Nov 21 '18 at 11:08
|
show 10 more comments
3
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
1
I have no idea what aoemof.solph.network.Bus objectis (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict
– Robin Zigmond
Nov 21 '18 at 11:04
1
First, just check values in dictionary - useprintfunction. I guess you'll find out, that that one value is not dictionary key...
– kosist
Nov 21 '18 at 11:04
2
You can iterate over a dict without needing to know its keys, seevalues(),items(). But this dict looks really painful, show us the code that generatedo_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.
– smci
Nov 21 '18 at 11:08
3
3
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
1
1
I have no idea what a
oemof.solph.network.Bus object is (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict– Robin Zigmond
Nov 21 '18 at 11:04
I have no idea what a
oemof.solph.network.Bus object is (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict– Robin Zigmond
Nov 21 '18 at 11:04
1
1
First, just check values in dictionary - use
print function. I guess you'll find out, that that one value is not dictionary key...– kosist
Nov 21 '18 at 11:04
First, just check values in dictionary - use
print function. I guess you'll find out, that that one value is not dictionary key...– kosist
Nov 21 '18 at 11:04
2
2
You can iterate over a dict without needing to know its keys, see
values(), items(). But this dict looks really painful, show us the code that generated o_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.– smci
Nov 21 '18 at 11:08
You can iterate over a dict without needing to know its keys, see
values(), items(). But this dict looks really painful, show us the code that generated o_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.– smci
Nov 21 '18 at 11:08
|
show 10 more comments
1 Answer
1
active
oldest
votes
Your key is a tuple of two objects (Bus, Transformer), so in order to index it, I suppose you have to store that tuple somewhere when that dictionary is created in order to access it later or to extract the key. You can use this:
my_key = list(o_model.flows.keys())[0]
print(o_model.flows[my_key])
Example:
test = {("qwe","zxc"): [4,5,6]}
print(test.keys()) # dict_keys([('qwe', 'zxc')])
my_key = list(testprint(.keys())[0]
print(flow[my_key]) # [4 5 6]
- Why can't just type
(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)as key?
Because that is just the human-readable representation of that objects given that there is no string assigned for printing. Common keys, as strings, are also objects at certain location e.g. (<str object at 0x7f45f4f52c36>), but its bytes are intended to be interpreted as characters when printed.
So you don't use what is printed for indexing, you should use the object itself.
Example:
class ObjNoStr():
def __init__(self, x):
self.x = x
class ObjStr():
def __init__(self, x):
self.x = x
def __str__(self):
return "I have x: %d" % self.x
o1 = ObjNoStr(3)
o2 = ObjStr(3)
print(o1) # <__main__.ObjNoStr object at 0x7f36d38469b0>
print(o2) # I have x: 3
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
this works, but I don't understand why I have to store it? why can't I just type it between[brackets]
– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
add a comment |
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1 Answer
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oldest
votes
Your key is a tuple of two objects (Bus, Transformer), so in order to index it, I suppose you have to store that tuple somewhere when that dictionary is created in order to access it later or to extract the key. You can use this:
my_key = list(o_model.flows.keys())[0]
print(o_model.flows[my_key])
Example:
test = {("qwe","zxc"): [4,5,6]}
print(test.keys()) # dict_keys([('qwe', 'zxc')])
my_key = list(testprint(.keys())[0]
print(flow[my_key]) # [4 5 6]
- Why can't just type
(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)as key?
Because that is just the human-readable representation of that objects given that there is no string assigned for printing. Common keys, as strings, are also objects at certain location e.g. (<str object at 0x7f45f4f52c36>), but its bytes are intended to be interpreted as characters when printed.
So you don't use what is printed for indexing, you should use the object itself.
Example:
class ObjNoStr():
def __init__(self, x):
self.x = x
class ObjStr():
def __init__(self, x):
self.x = x
def __str__(self):
return "I have x: %d" % self.x
o1 = ObjNoStr(3)
o2 = ObjStr(3)
print(o1) # <__main__.ObjNoStr object at 0x7f36d38469b0>
print(o2) # I have x: 3
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
this works, but I don't understand why I have to store it? why can't I just type it between[brackets]
– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
add a comment |
Your key is a tuple of two objects (Bus, Transformer), so in order to index it, I suppose you have to store that tuple somewhere when that dictionary is created in order to access it later or to extract the key. You can use this:
my_key = list(o_model.flows.keys())[0]
print(o_model.flows[my_key])
Example:
test = {("qwe","zxc"): [4,5,6]}
print(test.keys()) # dict_keys([('qwe', 'zxc')])
my_key = list(testprint(.keys())[0]
print(flow[my_key]) # [4 5 6]
- Why can't just type
(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)as key?
Because that is just the human-readable representation of that objects given that there is no string assigned for printing. Common keys, as strings, are also objects at certain location e.g. (<str object at 0x7f45f4f52c36>), but its bytes are intended to be interpreted as characters when printed.
So you don't use what is printed for indexing, you should use the object itself.
Example:
class ObjNoStr():
def __init__(self, x):
self.x = x
class ObjStr():
def __init__(self, x):
self.x = x
def __str__(self):
return "I have x: %d" % self.x
o1 = ObjNoStr(3)
o2 = ObjStr(3)
print(o1) # <__main__.ObjNoStr object at 0x7f36d38469b0>
print(o2) # I have x: 3
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
this works, but I don't understand why I have to store it? why can't I just type it between[brackets]
– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
add a comment |
Your key is a tuple of two objects (Bus, Transformer), so in order to index it, I suppose you have to store that tuple somewhere when that dictionary is created in order to access it later or to extract the key. You can use this:
my_key = list(o_model.flows.keys())[0]
print(o_model.flows[my_key])
Example:
test = {("qwe","zxc"): [4,5,6]}
print(test.keys()) # dict_keys([('qwe', 'zxc')])
my_key = list(testprint(.keys())[0]
print(flow[my_key]) # [4 5 6]
- Why can't just type
(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)as key?
Because that is just the human-readable representation of that objects given that there is no string assigned for printing. Common keys, as strings, are also objects at certain location e.g. (<str object at 0x7f45f4f52c36>), but its bytes are intended to be interpreted as characters when printed.
So you don't use what is printed for indexing, you should use the object itself.
Example:
class ObjNoStr():
def __init__(self, x):
self.x = x
class ObjStr():
def __init__(self, x):
self.x = x
def __str__(self):
return "I have x: %d" % self.x
o1 = ObjNoStr(3)
o2 = ObjStr(3)
print(o1) # <__main__.ObjNoStr object at 0x7f36d38469b0>
print(o2) # I have x: 3
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
Your key is a tuple of two objects (Bus, Transformer), so in order to index it, I suppose you have to store that tuple somewhere when that dictionary is created in order to access it later or to extract the key. You can use this:
my_key = list(o_model.flows.keys())[0]
print(o_model.flows[my_key])
Example:
test = {("qwe","zxc"): [4,5,6]}
print(test.keys()) # dict_keys([('qwe', 'zxc')])
my_key = list(testprint(.keys())[0]
print(flow[my_key]) # [4 5 6]
- Why can't just type
(<oemof.solph.network.Bus object at 0x7f3e9c6b3ea8>, <oemof.solph.network.Transformer object at 0x7f3e9c52ce08>)as key?
Because that is just the human-readable representation of that objects given that there is no string assigned for printing. Common keys, as strings, are also objects at certain location e.g. (<str object at 0x7f45f4f52c36>), but its bytes are intended to be interpreted as characters when printed.
So you don't use what is printed for indexing, you should use the object itself.
Example:
class ObjNoStr():
def __init__(self, x):
self.x = x
class ObjStr():
def __init__(self, x):
self.x = x
def __str__(self):
return "I have x: %d" % self.x
o1 = ObjNoStr(3)
o2 = ObjStr(3)
print(o1) # <__main__.ObjNoStr object at 0x7f36d38469b0>
print(o2) # I have x: 3
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
edited Nov 21 '18 at 11:42
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
answered Nov 21 '18 at 11:21
gustavovelascohgustavovelascoh
5301417
5301417
this works, but I don't understand why I have to store it? why can't I just type it between[brackets]
– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
add a comment |
this works, but I don't understand why I have to store it? why can't I just type it between[brackets]
– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
this works, but I don't understand why I have to store it? why can't I just type it between
[brackets]– oakca
Nov 21 '18 at 11:25
this works, but I don't understand why I have to store it? why can't I just type it between
[brackets]– oakca
Nov 21 '18 at 11:25
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
Hi @oakca I updated the answer.
– gustavovelascoh
Nov 21 '18 at 11:36
add a comment |
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3
this is not the key of the dictionary, only a represenation !!!!!!!
– Xatyrian
Nov 21 '18 at 11:03
how would I get the key then?
– oakca
Nov 21 '18 at 11:04
1
I have no idea what a
oemof.solph.network.Bus objectis (presumably it's a class defined in some library you're using) - but it's definitely not the same as a dict– Robin Zigmond
Nov 21 '18 at 11:04
1
First, just check values in dictionary - use
printfunction. I guess you'll find out, that that one value is not dictionary key...– kosist
Nov 21 '18 at 11:04
2
You can iterate over a dict without needing to know its keys, see
values(),items(). But this dict looks really painful, show us the code that generatedo_model.flows. Its keys are not strings, they're lists of objects. Handling those keys would just be a pain. So don't construct it that way, if at all possible.– smci
Nov 21 '18 at 11:08