Lua: replace a substring
I have something like
str = "What a wonderful string //011// this is"
I have to replace the //011// with something like convertToRoman(011) and then get
str = "What a wonderful string XI this is"
However, the conversion into roman numbers is no problem here.
It is also possible that the string str didn't has a //...//. In this case it should simply return the same string.
function convertSTR(str)
if not string.find(str,"//") then
return str
else
replace //...// with convertToRoman(...)
end
return str
end
I know that I can use string.find to get the complete \...\ sequence. Is there an easier solution with pattern matching or something similiar?
lua substring lua-patterns
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
add a comment |
I have something like
str = "What a wonderful string //011// this is"
I have to replace the //011// with something like convertToRoman(011) and then get
str = "What a wonderful string XI this is"
However, the conversion into roman numbers is no problem here.
It is also possible that the string str didn't has a //...//. In this case it should simply return the same string.
function convertSTR(str)
if not string.find(str,"//") then
return str
else
replace //...// with convertToRoman(...)
end
return str
end
I know that I can use string.find to get the complete \...\ sequence. Is there an easier solution with pattern matching or something similiar?
lua substring lua-patterns
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
add a comment |
I have something like
str = "What a wonderful string //011// this is"
I have to replace the //011// with something like convertToRoman(011) and then get
str = "What a wonderful string XI this is"
However, the conversion into roman numbers is no problem here.
It is also possible that the string str didn't has a //...//. In this case it should simply return the same string.
function convertSTR(str)
if not string.find(str,"//") then
return str
else
replace //...// with convertToRoman(...)
end
return str
end
I know that I can use string.find to get the complete \...\ sequence. Is there an easier solution with pattern matching or something similiar?
lua substring lua-patterns
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
I have something like
str = "What a wonderful string //011// this is"
I have to replace the //011// with something like convertToRoman(011) and then get
str = "What a wonderful string XI this is"
However, the conversion into roman numbers is no problem here.
It is also possible that the string str didn't has a //...//. In this case it should simply return the same string.
function convertSTR(str)
if not string.find(str,"//") then
return str
else
replace //...// with convertToRoman(...)
end
return str
end
I know that I can use string.find to get the complete \...\ sequence. Is there an easier solution with pattern matching or something similiar?
lua substring lua-patterns
lua substring lua-patterns
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
edited Nov 21 '18 at 12:12
Wiktor Stribiżew
322k16142223
322k16142223
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
asked Nov 21 '18 at 11:39
HerbertHerbert
22218
22218
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
add a comment |
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
add a comment |
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
add a comment |
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
answered Nov 21 '18 at 11:50
lhflhf
56.4k668104
56.4k668104
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
add a comment |
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
Thanks, works fine!
– Herbert
Nov 21 '18 at 11:56
add a comment |
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
add a comment |
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
add a comment |
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
answered Nov 22 '18 at 3:10
Henri MenkeHenri Menke
7,70011328
7,70011328
add a comment |
add a comment |
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