What is the location of output of thrust::reduce operation(GPU RAM or CPU RAM)? [duplicate]












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  • thrust reduction result on device memory

    2 answers




When we use thrust::reduce in the following example, the output is an int. Is this output (sum variable in code) located on the GPU or CPU RAM?



If it is in CPU RAM, how to access/retain the variable in the gpu?
The reduce operation happens on the device(GPU) so at some point the output should be in the GPU.



#include <thrust/reduce.h>
#include <thrust/execution_policy.h>
#include <thrust/device_vector.h>

int main()
{
thrust::device_vector<int> D(6);
D[0]=0;
D[1]=1;
D[2]=2;
D[3]=3;
D[4]=4;
D[5]=5;
int sum = thrust::reduce(thrust::device,D.begin(), D.end(), (int) 0, thrust::plus<int>());

}









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Nov 21 '18 at 16:47


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • 1





    Please check this answer by Robert Crovella

    – sgarizvi
    Nov 21 '18 at 10:44
















0
















This question already has an answer here:




  • thrust reduction result on device memory

    2 answers




When we use thrust::reduce in the following example, the output is an int. Is this output (sum variable in code) located on the GPU or CPU RAM?



If it is in CPU RAM, how to access/retain the variable in the gpu?
The reduce operation happens on the device(GPU) so at some point the output should be in the GPU.



#include <thrust/reduce.h>
#include <thrust/execution_policy.h>
#include <thrust/device_vector.h>

int main()
{
thrust::device_vector<int> D(6);
D[0]=0;
D[1]=1;
D[2]=2;
D[3]=3;
D[4]=4;
D[5]=5;
int sum = thrust::reduce(thrust::device,D.begin(), D.end(), (int) 0, thrust::plus<int>());

}









share|improve this question













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Nov 21 '18 at 16:47


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • 1





    Please check this answer by Robert Crovella

    – sgarizvi
    Nov 21 '18 at 10:44














0












0








0









This question already has an answer here:




  • thrust reduction result on device memory

    2 answers




When we use thrust::reduce in the following example, the output is an int. Is this output (sum variable in code) located on the GPU or CPU RAM?



If it is in CPU RAM, how to access/retain the variable in the gpu?
The reduce operation happens on the device(GPU) so at some point the output should be in the GPU.



#include <thrust/reduce.h>
#include <thrust/execution_policy.h>
#include <thrust/device_vector.h>

int main()
{
thrust::device_vector<int> D(6);
D[0]=0;
D[1]=1;
D[2]=2;
D[3]=3;
D[4]=4;
D[5]=5;
int sum = thrust::reduce(thrust::device,D.begin(), D.end(), (int) 0, thrust::plus<int>());

}









share|improve this question















This question already has an answer here:




  • thrust reduction result on device memory

    2 answers




When we use thrust::reduce in the following example, the output is an int. Is this output (sum variable in code) located on the GPU or CPU RAM?



If it is in CPU RAM, how to access/retain the variable in the gpu?
The reduce operation happens on the device(GPU) so at some point the output should be in the GPU.



#include <thrust/reduce.h>
#include <thrust/execution_policy.h>
#include <thrust/device_vector.h>

int main()
{
thrust::device_vector<int> D(6);
D[0]=0;
D[1]=1;
D[2]=2;
D[3]=3;
D[4]=4;
D[5]=5;
int sum = thrust::reduce(thrust::device,D.begin(), D.end(), (int) 0, thrust::plus<int>());

}




This question already has an answer here:




  • thrust reduction result on device memory

    2 answers








cuda reduce ram thrust






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asked Nov 21 '18 at 10:10









user27665user27665

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marked as duplicate by talonmies cuda
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Nov 21 '18 at 16:47


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









marked as duplicate by talonmies cuda
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Nov 21 '18 at 16:47


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.










  • 1





    Please check this answer by Robert Crovella

    – sgarizvi
    Nov 21 '18 at 10:44














  • 1





    Please check this answer by Robert Crovella

    – sgarizvi
    Nov 21 '18 at 10:44








1




1





Please check this answer by Robert Crovella

– sgarizvi
Nov 21 '18 at 10:44





Please check this answer by Robert Crovella

– sgarizvi
Nov 21 '18 at 10:44












1 Answer
1






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oldest

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1














The result sum is on the CPU, you can refer to this documentation.



The result was probably at some point on the GPU, if the final result was computed on it. I didn't checked the implementation, but it could be possible that the final result is computed on the CPU. If you need to access it on the GPU, just pass it as a kernel argument, or copy it into global memory.






share|improve this answer






























    1 Answer
    1






    active

    oldest

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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes









    1














    The result sum is on the CPU, you can refer to this documentation.



    The result was probably at some point on the GPU, if the final result was computed on it. I didn't checked the implementation, but it could be possible that the final result is computed on the CPU. If you need to access it on the GPU, just pass it as a kernel argument, or copy it into global memory.






    share|improve this answer




























      1














      The result sum is on the CPU, you can refer to this documentation.



      The result was probably at some point on the GPU, if the final result was computed on it. I didn't checked the implementation, but it could be possible that the final result is computed on the CPU. If you need to access it on the GPU, just pass it as a kernel argument, or copy it into global memory.






      share|improve this answer


























        1












        1








        1







        The result sum is on the CPU, you can refer to this documentation.



        The result was probably at some point on the GPU, if the final result was computed on it. I didn't checked the implementation, but it could be possible that the final result is computed on the CPU. If you need to access it on the GPU, just pass it as a kernel argument, or copy it into global memory.






        share|improve this answer













        The result sum is on the CPU, you can refer to this documentation.



        The result was probably at some point on the GPU, if the final result was computed on it. I didn't checked the implementation, but it could be possible that the final result is computed on the CPU. If you need to access it on the GPU, just pass it as a kernel argument, or copy it into global memory.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 10:43









        Robin ThoniRobin Thoni

        949718




        949718

















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