Haskell: Converting a .lua table to Haskell workable types





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I'm a beginner trying to practice coding haskell by translating some simple repo from different languages to Haskell.



Many simple games use .lua to store character/ability data.



What I want is to take that .lua table and convert it into haskell workable types.



This is what the .lua file looks like



local Data =
{
["Weapons"] = {
["AB"] = {
Name = "AB",
Cost = {
Spells = 65000,
BCost = 15000,
MCost = 150,
sh = 35,
Time = 24,
Parts = {
{ Name = "Top",Type = "Item",Count = 1,},},
},
Resist = 0.85,
Class = "Shield",
Attack = {
Damage = {
["First"] = 5,
["Second"] = 5,
["Third"] = 40,},
Chance = 0.2,
X = 2,
},
},
["PG"] = {
...
...
...
}

return Data


When woking with Aeson, there's this simple function decode which you can use as decode someJSON :: Maybe Object and get the entirety of JSON file content put in default Aeson datatypes which you can work on with library functions. I haven't been able to find something similar for .lua.










share|improve this question























  • You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

    – Redu
    Nov 24 '18 at 17:42











  • @Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

    – atis
    Nov 24 '18 at 19:59











  • @Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

    – atis
    Nov 24 '18 at 20:12













  • Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

    – Redu
    Nov 24 '18 at 20:39








  • 1





    No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

    – atis
    Nov 25 '18 at 7:19


















1















I'm a beginner trying to practice coding haskell by translating some simple repo from different languages to Haskell.



Many simple games use .lua to store character/ability data.



What I want is to take that .lua table and convert it into haskell workable types.



This is what the .lua file looks like



local Data =
{
["Weapons"] = {
["AB"] = {
Name = "AB",
Cost = {
Spells = 65000,
BCost = 15000,
MCost = 150,
sh = 35,
Time = 24,
Parts = {
{ Name = "Top",Type = "Item",Count = 1,},},
},
Resist = 0.85,
Class = "Shield",
Attack = {
Damage = {
["First"] = 5,
["Second"] = 5,
["Third"] = 40,},
Chance = 0.2,
X = 2,
},
},
["PG"] = {
...
...
...
}

return Data


When woking with Aeson, there's this simple function decode which you can use as decode someJSON :: Maybe Object and get the entirety of JSON file content put in default Aeson datatypes which you can work on with library functions. I haven't been able to find something similar for .lua.










share|improve this question























  • You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

    – Redu
    Nov 24 '18 at 17:42











  • @Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

    – atis
    Nov 24 '18 at 19:59











  • @Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

    – atis
    Nov 24 '18 at 20:12













  • Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

    – Redu
    Nov 24 '18 at 20:39








  • 1





    No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

    – atis
    Nov 25 '18 at 7:19














1












1








1








I'm a beginner trying to practice coding haskell by translating some simple repo from different languages to Haskell.



Many simple games use .lua to store character/ability data.



What I want is to take that .lua table and convert it into haskell workable types.



This is what the .lua file looks like



local Data =
{
["Weapons"] = {
["AB"] = {
Name = "AB",
Cost = {
Spells = 65000,
BCost = 15000,
MCost = 150,
sh = 35,
Time = 24,
Parts = {
{ Name = "Top",Type = "Item",Count = 1,},},
},
Resist = 0.85,
Class = "Shield",
Attack = {
Damage = {
["First"] = 5,
["Second"] = 5,
["Third"] = 40,},
Chance = 0.2,
X = 2,
},
},
["PG"] = {
...
...
...
}

return Data


When woking with Aeson, there's this simple function decode which you can use as decode someJSON :: Maybe Object and get the entirety of JSON file content put in default Aeson datatypes which you can work on with library functions. I haven't been able to find something similar for .lua.










share|improve this question














I'm a beginner trying to practice coding haskell by translating some simple repo from different languages to Haskell.



Many simple games use .lua to store character/ability data.



What I want is to take that .lua table and convert it into haskell workable types.



This is what the .lua file looks like



local Data =
{
["Weapons"] = {
["AB"] = {
Name = "AB",
Cost = {
Spells = 65000,
BCost = 15000,
MCost = 150,
sh = 35,
Time = 24,
Parts = {
{ Name = "Top",Type = "Item",Count = 1,},},
},
Resist = 0.85,
Class = "Shield",
Attack = {
Damage = {
["First"] = 5,
["Second"] = 5,
["Third"] = 40,},
Chance = 0.2,
X = 2,
},
},
["PG"] = {
...
...
...
}

return Data


When woking with Aeson, there's this simple function decode which you can use as decode someJSON :: Maybe Object and get the entirety of JSON file content put in default Aeson datatypes which you can work on with library functions. I haven't been able to find something similar for .lua.







parsing haskell lua-table






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 17:21









atisatis

388213




388213













  • You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

    – Redu
    Nov 24 '18 at 17:42











  • @Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

    – atis
    Nov 24 '18 at 19:59











  • @Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

    – atis
    Nov 24 '18 at 20:12













  • Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

    – Redu
    Nov 24 '18 at 20:39








  • 1





    No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

    – atis
    Nov 25 '18 at 7:19



















  • You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

    – Redu
    Nov 24 '18 at 17:42











  • @Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

    – atis
    Nov 24 '18 at 19:59











  • @Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

    – atis
    Nov 24 '18 at 20:12













  • Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

    – Redu
    Nov 24 '18 at 20:39








  • 1





    No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

    – atis
    Nov 25 '18 at 7:19

















You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

– Redu
Nov 24 '18 at 17:42





You may check hslua-aeson package. It seems to have instances to push and receive Aeson's Value type to and from the Lua stack.

– Redu
Nov 24 '18 at 17:42













@Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

– atis
Nov 24 '18 at 19:59





@Redu From its README.md it seems like the package does JSON to Lua. Is converting Lua to JSON possible with that package?

– atis
Nov 24 '18 at 19:59













@Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

– atis
Nov 24 '18 at 20:12







@Redu This is what I tried main = do openlibs dofile "src/configfile.lua" wData <- getglobal "Data" *> peek (-1) liftIO $ print (wData :: Value) after removing local from the .lua file.

– atis
Nov 24 '18 at 20:12















Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

– Redu
Nov 24 '18 at 20:39







Sorry.. i have no experience with Lua - Haskell workflow at all. It was just an idea. Have you tried going through the code?

– Redu
Nov 24 '18 at 20:39






1




1





No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

– atis
Nov 25 '18 at 7:19





No worries! The code you linked does seem to convert Lua table values to Haskell in Peekable instance. It might just work! I'll just need to work out how it operates.

– atis
Nov 25 '18 at 7:19












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