How can I convert a data frame into 3-D matrix with the values of two columns of data frame forming column...
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
Let's say I have following dataframe
A B C C
a 1 ca da
b 2 cb db
c 3 cc dc
I want to convert above to the form .
[,,1]
a b c
1 ca 0 0
2 0 cb 0
3 0 0 cc
[,,2]
a b c
1 da 0 0
2 0 db 0
3 0 0 dc
r dataframe
|
show 1 more comment
Let's say I have following dataframe
A B C C
a 1 ca da
b 2 cb db
c 3 cc dc
I want to convert above to the form .
[,,1]
a b c
1 ca 0 0
2 0 cb 0
3 0 0 cc
[,,2]
a b c
1 da 0 0
2 0 db 0
3 0 0 dc
r dataframe
not sure this is exactly what you want (its not 3D) but ...reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
1
okay, here is a monster!simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
1
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48
|
show 1 more comment
Let's say I have following dataframe
A B C C
a 1 ca da
b 2 cb db
c 3 cc dc
I want to convert above to the form .
[,,1]
a b c
1 ca 0 0
2 0 cb 0
3 0 0 cc
[,,2]
a b c
1 da 0 0
2 0 db 0
3 0 0 dc
r dataframe
Let's say I have following dataframe
A B C C
a 1 ca da
b 2 cb db
c 3 cc dc
I want to convert above to the form .
[,,1]
a b c
1 ca 0 0
2 0 cb 0
3 0 0 cc
[,,2]
a b c
1 da 0 0
2 0 db 0
3 0 0 dc
r dataframe
r dataframe
edited Nov 23 '18 at 23:28
Amb
asked Nov 23 '18 at 23:10
AmbAmb
193
193
not sure this is exactly what you want (its not 3D) but ...reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
1
okay, here is a monster!simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
1
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48
|
show 1 more comment
not sure this is exactly what you want (its not 3D) but ...reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
1
okay, here is a monster!simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
1
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48
not sure this is exactly what you want (its not 3D) but ...
reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
not sure this is exactly what you want (its not 3D) but ...
reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
1
1
okay, here is a monster!
simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
okay, here is a monster!
simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
1
1
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48
|
show 1 more comment
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53453754%2fhow-can-i-convert-a-data-frame-into-3-d-matrix-with-the-values-of-two-columns-of%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53453754%2fhow-can-i-convert-a-data-frame-into-3-d-matrix-with-the-values-of-two-columns-of%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
not sure this is exactly what you want (its not 3D) but ...
reshape2::dcast(data=dat, B ~ A, value.var="C", fill=0)
– user20650
Nov 23 '18 at 23:21
@user20650 Can you give one more look
– Amb
Nov 23 '18 at 23:29
I'm not sure. I must admit, the fact you are using matrices/arrays to mix characters and zeros makes this a wee bit weird ;)
– user20650
Nov 23 '18 at 23:33
1
okay, here is a monster!
simplify2array(lapply(c("C", "D"), function(i) reshape2::acast(data=dat, B ~ A , value.var=i, fill=0)))
– user20650
Nov 23 '18 at 23:39
1
@user20650 Wow! It works. Thanks! Now, time for me to understand how it works
– Amb
Nov 23 '18 at 23:48