How to create outputs in columns using Printf with varied output lengths - Java
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I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf
I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.
import java.util.Scanner;
public class Convert {
public static void main(String args) {
Scanner input = new Scanner(System.in);
System.out.println("Please enter your decimal number");
int decimal = input.nextInt();
System.out.printf("Decimal: %dn", decimal);
String binary=decimalToBinary(decimal);
System.out.printf("Binary: %sn", binary);
String octa=decimalToOctal(decimal);
System.out.printf("Octal: %sn", octa);
String hexa=decimalToOctal(decimal);
System.out.printf("Hexa:%sn", hexa);
}
public static String decimalToBinary(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%2;
decimal=decimal/2;
answer=remainder+answer;
}
return answer;
}
public static String decimalToOctal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%8;
decimal=decimal/8;
answer=remainder+answer;
}
return answer;
}
public static String decimalToHexadecimal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%16;
decimal=decimal/16;
if (remainder==10)
answer= "A" + answer;
else if (remainder==11)
answer= "B" + answer;
else if (remainder==12)
answer= "C" + answer;
else if (remainder==13)
answer= "D" + answer;
else if (remainder==14)
answer= "E" + answer;
else if (remainder==15)
answer= "F" + answer;
else answer=remainder+answer;
}
return answer;
}
}
java string eclipse printf
add a comment |
I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf
I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.
import java.util.Scanner;
public class Convert {
public static void main(String args) {
Scanner input = new Scanner(System.in);
System.out.println("Please enter your decimal number");
int decimal = input.nextInt();
System.out.printf("Decimal: %dn", decimal);
String binary=decimalToBinary(decimal);
System.out.printf("Binary: %sn", binary);
String octa=decimalToOctal(decimal);
System.out.printf("Octal: %sn", octa);
String hexa=decimalToOctal(decimal);
System.out.printf("Hexa:%sn", hexa);
}
public static String decimalToBinary(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%2;
decimal=decimal/2;
answer=remainder+answer;
}
return answer;
}
public static String decimalToOctal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%8;
decimal=decimal/8;
answer=remainder+answer;
}
return answer;
}
public static String decimalToHexadecimal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%16;
decimal=decimal/16;
if (remainder==10)
answer= "A" + answer;
else if (remainder==11)
answer= "B" + answer;
else if (remainder==12)
answer= "C" + answer;
else if (remainder==13)
answer= "D" + answer;
else if (remainder==14)
answer= "E" + answer;
else if (remainder==15)
answer= "F" + answer;
else answer=remainder+answer;
}
return answer;
}
}
java string eclipse printf
add a comment |
I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf
I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.
import java.util.Scanner;
public class Convert {
public static void main(String args) {
Scanner input = new Scanner(System.in);
System.out.println("Please enter your decimal number");
int decimal = input.nextInt();
System.out.printf("Decimal: %dn", decimal);
String binary=decimalToBinary(decimal);
System.out.printf("Binary: %sn", binary);
String octa=decimalToOctal(decimal);
System.out.printf("Octal: %sn", octa);
String hexa=decimalToOctal(decimal);
System.out.printf("Hexa:%sn", hexa);
}
public static String decimalToBinary(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%2;
decimal=decimal/2;
answer=remainder+answer;
}
return answer;
}
public static String decimalToOctal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%8;
decimal=decimal/8;
answer=remainder+answer;
}
return answer;
}
public static String decimalToHexadecimal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%16;
decimal=decimal/16;
if (remainder==10)
answer= "A" + answer;
else if (remainder==11)
answer= "B" + answer;
else if (remainder==12)
answer= "C" + answer;
else if (remainder==13)
answer= "D" + answer;
else if (remainder==14)
answer= "E" + answer;
else if (remainder==15)
answer= "F" + answer;
else answer=remainder+answer;
}
return answer;
}
}
java string eclipse printf
I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf
I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.
import java.util.Scanner;
public class Convert {
public static void main(String args) {
Scanner input = new Scanner(System.in);
System.out.println("Please enter your decimal number");
int decimal = input.nextInt();
System.out.printf("Decimal: %dn", decimal);
String binary=decimalToBinary(decimal);
System.out.printf("Binary: %sn", binary);
String octa=decimalToOctal(decimal);
System.out.printf("Octal: %sn", octa);
String hexa=decimalToOctal(decimal);
System.out.printf("Hexa:%sn", hexa);
}
public static String decimalToBinary(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%2;
decimal=decimal/2;
answer=remainder+answer;
}
return answer;
}
public static String decimalToOctal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%8;
decimal=decimal/8;
answer=remainder+answer;
}
return answer;
}
public static String decimalToHexadecimal(int decimal) {
int remainder;
String answer="";
while (decimal>0) {
remainder=decimal%16;
decimal=decimal/16;
if (remainder==10)
answer= "A" + answer;
else if (remainder==11)
answer= "B" + answer;
else if (remainder==12)
answer= "C" + answer;
else if (remainder==13)
answer= "D" + answer;
else if (remainder==14)
answer= "E" + answer;
else if (remainder==15)
answer= "F" + answer;
else answer=remainder+answer;
}
return answer;
}
}
java string eclipse printf
java string eclipse printf
asked Nov 24 '18 at 0:09
Rebecca Allyson MorrisRebecca Allyson Morris
203
203
add a comment |
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1 Answer
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Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,
printf("%20s", s);
will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,
printf("%20s", s);
will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
add a comment |
Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,
printf("%20s", s);
will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
add a comment |
Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,
printf("%20s", s);
will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.
Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,
printf("%20s", s);
will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.
answered Nov 24 '18 at 0:18
davedave
8,85353252
8,85353252
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
add a comment |
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.
– Rebecca Allyson Morris
Nov 24 '18 at 0:20
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline
– Rebecca Allyson Morris
Nov 24 '18 at 0:26
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