Pandas sort data frame by logical day
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1
I have the following resulting pandas DateFrame:
How can I get this to sort properly? For example have the sort so that Day 2 comes after Day 1, not Day 11. As seen in Group 2 below?
python pandas sorting dataframe indexing
edited Nov 24 '18 at 0:31
jpp
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
add a comment |
1
I have the following resulting pandas DateFrame:
How can I get this to sort properly? For example have the sort so that Day 2 comes after Day 1, not Day 11. As seen in Group 2 below?
python pandas sorting dataframe indexing
edited Nov 24 '18 at 0:31
jpp
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
add a comment |
1
1
1
I have the following resulting pandas DateFrame:
How can I get this to sort properly? For example have the sort so that Day 2 comes after Day 1, not Day 11. As seen in Group 2 below?
python pandas sorting dataframe indexing
edited Nov 24 '18 at 0:31
jpp
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
I have the following resulting pandas DateFrame:
How can I get this to sort properly? For example have the sort so that Day 2 comes after Day 1, not Day 11. As seen in Group 2 below?
python pandas sorting dataframe indexing
python pandas sorting dataframe indexing
edited Nov 24 '18 at 0:31
jpp
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
edited Nov 24 '18 at 0:31
jpp
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
edited Nov 24 '18 at 0:31
jpp
103k2167117
edited Nov 24 '18 at 0:31
jpp
103k2167117
edited Nov 24 '18 at 0:31
jpp
103k2167117
103k2167117
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
asked Nov 24 '18 at 0:09
TheCuriouslyCodingFoxahTheCuriouslyCodingFoxah
647
647
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
3
set_levels + sort_index
The issue is your strings are being sorted as strings rather than numerically. First convert your first index level to numeric, then sort by index:
# split by whitespace, take last split, convert to integers
new_index_values = df.index.levels[1].str.split().str[-1].astype(int)
# set 'Day' level
df.index = df.index.set_levels(new_index_values, level='Day')
# sort by index
df = df.sort_index()
print(df)
Value
Group Day
A 0 1
2 3
11 2
B 5 5
7 6
10 4
Setup
The above demonstration uses this example setup:
df = pd.DataFrame({'Group': ['A', 'A', 'A', 'B', 'B', 'B'],
'Day': ['Day 0', 'Day 11', 'Day 2', 'Day 10', 'Day 5', 'Day 7'],
'Value': [1, 2, 3, 4, 5, 6]}).set_index(['Group', 'Day'])
print(df)
Value
Group Day
A Day 0 1
Day 11 2
Day 2 3
B Day 10 4
Day 5 5
Day 7 6
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
add a comment |
1
You need to sort integers instead of strings:
import pandas as pd
x = pd.Series([1,2,3,4,6], index=[3,2,1,11,12])
x.sort_index()
1 3
2 2
3 1
11 4
12 6
dtype: int64
y = pd.Series([1,2,3,4,5], index=['3','2','1','11','12'])
y.sort_index()
1 3
11 4
12 5
2 2
3 1
dtype: int64
I would suggest to have only numbers in the column instead of strings 'Day..'.
answered Nov 24 '18 at 0:24
PyJanPyJan
484
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
set_levels + sort_index
The issue is your strings are being sorted as strings rather than numerically. First convert your first index level to numeric, then sort by index:
# split by whitespace, take last split, convert to integers
new_index_values = df.index.levels[1].str.split().str[-1].astype(int)
# set 'Day' level
df.index = df.index.set_levels(new_index_values, level='Day')
# sort by index
df = df.sort_index()
print(df)
Value
Group Day
A 0 1
2 3
11 2
B 5 5
7 6
10 4
Setup
The above demonstration uses this example setup:
df = pd.DataFrame({'Group': ['A', 'A', 'A', 'B', 'B', 'B'],
'Day': ['Day 0', 'Day 11', 'Day 2', 'Day 10', 'Day 5', 'Day 7'],
'Value': [1, 2, 3, 4, 5, 6]}).set_index(['Group', 'Day'])
print(df)
Value
Group Day
A Day 0 1
Day 11 2
Day 2 3
B Day 10 4
Day 5 5
Day 7 6
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
add a comment |
3
set_levels + sort_index
The issue is your strings are being sorted as strings rather than numerically. First convert your first index level to numeric, then sort by index:
# split by whitespace, take last split, convert to integers
new_index_values = df.index.levels[1].str.split().str[-1].astype(int)
# set 'Day' level
df.index = df.index.set_levels(new_index_values, level='Day')
# sort by index
df = df.sort_index()
print(df)
Value
Group Day
A 0 1
2 3
11 2
B 5 5
7 6
10 4
Setup
The above demonstration uses this example setup:
df = pd.DataFrame({'Group': ['A', 'A', 'A', 'B', 'B', 'B'],
'Day': ['Day 0', 'Day 11', 'Day 2', 'Day 10', 'Day 5', 'Day 7'],
'Value': [1, 2, 3, 4, 5, 6]}).set_index(['Group', 'Day'])
print(df)
Value
Group Day
A Day 0 1
Day 11 2
Day 2 3
B Day 10 4
Day 5 5
Day 7 6
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
add a comment |
3
3
3
set_levels + sort_index
The issue is your strings are being sorted as strings rather than numerically. First convert your first index level to numeric, then sort by index:
# split by whitespace, take last split, convert to integers
new_index_values = df.index.levels[1].str.split().str[-1].astype(int)
# set 'Day' level
df.index = df.index.set_levels(new_index_values, level='Day')
# sort by index
df = df.sort_index()
print(df)
Value
Group Day
A 0 1
2 3
11 2
B 5 5
7 6
10 4
Setup
The above demonstration uses this example setup:
df = pd.DataFrame({'Group': ['A', 'A', 'A', 'B', 'B', 'B'],
'Day': ['Day 0', 'Day 11', 'Day 2', 'Day 10', 'Day 5', 'Day 7'],
'Value': [1, 2, 3, 4, 5, 6]}).set_index(['Group', 'Day'])
print(df)
Value
Group Day
A Day 0 1
Day 11 2
Day 2 3
B Day 10 4
Day 5 5
Day 7 6
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
set_levels + sort_index
The issue is your strings are being sorted as strings rather than numerically. First convert your first index level to numeric, then sort by index:
# split by whitespace, take last split, convert to integers
new_index_values = df.index.levels[1].str.split().str[-1].astype(int)
# set 'Day' level
df.index = df.index.set_levels(new_index_values, level='Day')
# sort by index
df = df.sort_index()
print(df)
Value
Group Day
A 0 1
2 3
11 2
B 5 5
7 6
10 4
Setup
The above demonstration uses this example setup:
df = pd.DataFrame({'Group': ['A', 'A', 'A', 'B', 'B', 'B'],
'Day': ['Day 0', 'Day 11', 'Day 2', 'Day 10', 'Day 5', 'Day 7'],
'Value': [1, 2, 3, 4, 5, 6]}).set_index(['Group', 'Day'])
print(df)
Value
Group Day
A Day 0 1
Day 11 2
Day 2 3
B Day 10 4
Day 5 5
Day 7 6
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
answered Nov 24 '18 at 0:29
jppjpp
103k2167117
103k2167117
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
add a comment |
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Thanks for the help, I really appreciate it!
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:20
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
Is there anyway to have the index still return as 'Day 0', 'Day 1', etc. instead of just the integer?
– TheCuriouslyCodingFoxah
Nov 26 '18 at 15:27
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
@TheCuriouslyCodingFoxah, Once you've done the conversion, no. Of course, you can calculate your string index from the integers if you wish. But there's a rarely a need.
– jpp
Nov 26 '18 at 15:31
add a comment |
1
You need to sort integers instead of strings:
import pandas as pd
x = pd.Series([1,2,3,4,6], index=[3,2,1,11,12])
x.sort_index()
1 3
2 2
3 1
11 4
12 6
dtype: int64
y = pd.Series([1,2,3,4,5], index=['3','2','1','11','12'])
y.sort_index()
1 3
11 4
12 5
2 2
3 1
dtype: int64
I would suggest to have only numbers in the column instead of strings 'Day..'.
answered Nov 24 '18 at 0:24
PyJanPyJan
484
add a comment |
1
You need to sort integers instead of strings:
import pandas as pd
x = pd.Series([1,2,3,4,6], index=[3,2,1,11,12])
x.sort_index()
1 3
2 2
3 1
11 4
12 6
dtype: int64
y = pd.Series([1,2,3,4,5], index=['3','2','1','11','12'])
y.sort_index()
1 3
11 4
12 5
2 2
3 1
dtype: int64
I would suggest to have only numbers in the column instead of strings 'Day..'.
answered Nov 24 '18 at 0:24
PyJanPyJan
484
add a comment |
1
1
1
You need to sort integers instead of strings:
import pandas as pd
x = pd.Series([1,2,3,4,6], index=[3,2,1,11,12])
x.sort_index()
1 3
2 2
3 1
11 4
12 6
dtype: int64
y = pd.Series([1,2,3,4,5], index=['3','2','1','11','12'])
y.sort_index()
1 3
11 4
12 5
2 2
3 1
dtype: int64
I would suggest to have only numbers in the column instead of strings 'Day..'.
answered Nov 24 '18 at 0:24
PyJanPyJan
484
You need to sort integers instead of strings:
import pandas as pd
x = pd.Series([1,2,3,4,6], index=[3,2,1,11,12])
x.sort_index()
1 3
2 2
3 1
11 4
12 6
dtype: int64
y = pd.Series([1,2,3,4,5], index=['3','2','1','11','12'])
y.sort_index()
1 3
11 4
12 5
2 2
3 1
dtype: int64
I would suggest to have only numbers in the column instead of strings 'Day..'.
answered Nov 24 '18 at 0:24
PyJanPyJan
484
answered Nov 24 '18 at 0:24
PyJanPyJan
484
answered Nov 24 '18 at 0:24
PyJanPyJan
484
answered Nov 24 '18 at 0:24
PyJanPyJan
484
484
add a comment |
add a comment |
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