Joining nested lists and adding column











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I have a list containing two matrices:



a <- list("m1"=matrix(1:9, nrow = 3, ncol = 3),
"m2"=matrix(1:9, nrow = 3, ncol = 3))


I want to bind the two matrices (row-bind), and to distinguish the rows, I want to add a column that contains the name of the matrix. I can bind the rows using r bind:



b <- do.call(rbind, a) %>% as.data.frame


which yields



  V1 V2 V3
1 1 4 7
2 2 5 8
3 3 6 9
4 1 4 7
5 2 5 8
6 3 6 9


But how do I add a column containing the names? I can do b$id <- c("m1","m1","m1","m2","m2","m2"), but there must be an easier way than this (?)










share|improve this question


























    up vote
    0
    down vote

    favorite












    I have a list containing two matrices:



    a <- list("m1"=matrix(1:9, nrow = 3, ncol = 3),
    "m2"=matrix(1:9, nrow = 3, ncol = 3))


    I want to bind the two matrices (row-bind), and to distinguish the rows, I want to add a column that contains the name of the matrix. I can bind the rows using r bind:



    b <- do.call(rbind, a) %>% as.data.frame


    which yields



      V1 V2 V3
    1 1 4 7
    2 2 5 8
    3 3 6 9
    4 1 4 7
    5 2 5 8
    6 3 6 9


    But how do I add a column containing the names? I can do b$id <- c("m1","m1","m1","m2","m2","m2"), but there must be an easier way than this (?)










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a list containing two matrices:



      a <- list("m1"=matrix(1:9, nrow = 3, ncol = 3),
      "m2"=matrix(1:9, nrow = 3, ncol = 3))


      I want to bind the two matrices (row-bind), and to distinguish the rows, I want to add a column that contains the name of the matrix. I can bind the rows using r bind:



      b <- do.call(rbind, a) %>% as.data.frame


      which yields



        V1 V2 V3
      1 1 4 7
      2 2 5 8
      3 3 6 9
      4 1 4 7
      5 2 5 8
      6 3 6 9


      But how do I add a column containing the names? I can do b$id <- c("m1","m1","m1","m2","m2","m2"), but there must be an easier way than this (?)










      share|improve this question













      I have a list containing two matrices:



      a <- list("m1"=matrix(1:9, nrow = 3, ncol = 3),
      "m2"=matrix(1:9, nrow = 3, ncol = 3))


      I want to bind the two matrices (row-bind), and to distinguish the rows, I want to add a column that contains the name of the matrix. I can bind the rows using r bind:



      b <- do.call(rbind, a) %>% as.data.frame


      which yields



        V1 V2 V3
      1 1 4 7
      2 2 5 8
      3 3 6 9
      4 1 4 7
      5 2 5 8
      6 3 6 9


      But how do I add a column containing the names? I can do b$id <- c("m1","m1","m1","m2","m2","m2"), but there must be an easier way than this (?)







      r dplyr






      share|improve this question













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      share|improve this question










      asked Nov 8 at 11:28









      N08

      49518




      49518
























          2 Answers
          2






          active

          oldest

          votes

















          up vote
          2
          down vote



          accepted










          Here's how to do it in dplyr / purrr



          a %>% purrr::map(as.data.frame) %>% dplyr::bind_rows(.id = "origin")
          origin V1 V2 V3
          1 m1 1 4 7
          2 m1 2 5 8
          3 m1 3 6 9
          4 m2 1 4 7
          5 m2 2 5 8
          6 m2 3 6 9


          That converts the matrices to data-frames before row-binding them.



          You can use bind_rows on a list of matrices. But it doesn't return what you expect.



          a %>% bind_rows(.id = "origin")
          # A tibble: 9 x 3
          origin m1 m2
          <chr> <int> <int>
          1 1 1 1
          2 1 2 2
          3 1 3 3
          4 1 4 4
          5 1 5 5
          6 1 6 6
          7 1 7 7
          8 1 8 8
          9 1 9 9


          This happens because m1 and m2 are vectors (because they are matrices) of the same length, and bind_rows sees a list of constant-length vectors as a single data-frame. So the latter call is equivalent to



          bind_rows(data.frame(m1 = as.vector(m1), m2 = as.vector(m2)), .id = "origin")


          So, make sure you convert your matrices to data.frames before you bind them together.






          share|improve this answer






























            up vote
            1
            down vote













            You can do:



            b <- do.call(rbind.data.frame, a)

            # V1 V2 V3
            #m1.1 1 4 7
            #m1.2 2 5 8
            #m1.3 3 6 9
            #m2.1 1 4 7
            #m2.2 2 5 8
            #m2.3 3 6 9


            or if you not happy with this,



            b    <- do.call(rbind.data.frame, a)
            b$id <- sub("[.].+", "", rownames(b))

            # V1 V2 V3 id
            #m1.1 1 4 7 m1
            #m1.2 2 5 8 m1
            #m1.3 3 6 9 m1
            #m2.1 1 4 7 m2
            #m2.2 2 5 8 m2
            #m2.3 3 6 9 m2





            share|improve this answer























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              2
              down vote



              accepted










              Here's how to do it in dplyr / purrr



              a %>% purrr::map(as.data.frame) %>% dplyr::bind_rows(.id = "origin")
              origin V1 V2 V3
              1 m1 1 4 7
              2 m1 2 5 8
              3 m1 3 6 9
              4 m2 1 4 7
              5 m2 2 5 8
              6 m2 3 6 9


              That converts the matrices to data-frames before row-binding them.



              You can use bind_rows on a list of matrices. But it doesn't return what you expect.



              a %>% bind_rows(.id = "origin")
              # A tibble: 9 x 3
              origin m1 m2
              <chr> <int> <int>
              1 1 1 1
              2 1 2 2
              3 1 3 3
              4 1 4 4
              5 1 5 5
              6 1 6 6
              7 1 7 7
              8 1 8 8
              9 1 9 9


              This happens because m1 and m2 are vectors (because they are matrices) of the same length, and bind_rows sees a list of constant-length vectors as a single data-frame. So the latter call is equivalent to



              bind_rows(data.frame(m1 = as.vector(m1), m2 = as.vector(m2)), .id = "origin")


              So, make sure you convert your matrices to data.frames before you bind them together.






              share|improve this answer



























                up vote
                2
                down vote



                accepted










                Here's how to do it in dplyr / purrr



                a %>% purrr::map(as.data.frame) %>% dplyr::bind_rows(.id = "origin")
                origin V1 V2 V3
                1 m1 1 4 7
                2 m1 2 5 8
                3 m1 3 6 9
                4 m2 1 4 7
                5 m2 2 5 8
                6 m2 3 6 9


                That converts the matrices to data-frames before row-binding them.



                You can use bind_rows on a list of matrices. But it doesn't return what you expect.



                a %>% bind_rows(.id = "origin")
                # A tibble: 9 x 3
                origin m1 m2
                <chr> <int> <int>
                1 1 1 1
                2 1 2 2
                3 1 3 3
                4 1 4 4
                5 1 5 5
                6 1 6 6
                7 1 7 7
                8 1 8 8
                9 1 9 9


                This happens because m1 and m2 are vectors (because they are matrices) of the same length, and bind_rows sees a list of constant-length vectors as a single data-frame. So the latter call is equivalent to



                bind_rows(data.frame(m1 = as.vector(m1), m2 = as.vector(m2)), .id = "origin")


                So, make sure you convert your matrices to data.frames before you bind them together.






                share|improve this answer

























                  up vote
                  2
                  down vote



                  accepted







                  up vote
                  2
                  down vote



                  accepted






                  Here's how to do it in dplyr / purrr



                  a %>% purrr::map(as.data.frame) %>% dplyr::bind_rows(.id = "origin")
                  origin V1 V2 V3
                  1 m1 1 4 7
                  2 m1 2 5 8
                  3 m1 3 6 9
                  4 m2 1 4 7
                  5 m2 2 5 8
                  6 m2 3 6 9


                  That converts the matrices to data-frames before row-binding them.



                  You can use bind_rows on a list of matrices. But it doesn't return what you expect.



                  a %>% bind_rows(.id = "origin")
                  # A tibble: 9 x 3
                  origin m1 m2
                  <chr> <int> <int>
                  1 1 1 1
                  2 1 2 2
                  3 1 3 3
                  4 1 4 4
                  5 1 5 5
                  6 1 6 6
                  7 1 7 7
                  8 1 8 8
                  9 1 9 9


                  This happens because m1 and m2 are vectors (because they are matrices) of the same length, and bind_rows sees a list of constant-length vectors as a single data-frame. So the latter call is equivalent to



                  bind_rows(data.frame(m1 = as.vector(m1), m2 = as.vector(m2)), .id = "origin")


                  So, make sure you convert your matrices to data.frames before you bind them together.






                  share|improve this answer














                  Here's how to do it in dplyr / purrr



                  a %>% purrr::map(as.data.frame) %>% dplyr::bind_rows(.id = "origin")
                  origin V1 V2 V3
                  1 m1 1 4 7
                  2 m1 2 5 8
                  3 m1 3 6 9
                  4 m2 1 4 7
                  5 m2 2 5 8
                  6 m2 3 6 9


                  That converts the matrices to data-frames before row-binding them.



                  You can use bind_rows on a list of matrices. But it doesn't return what you expect.



                  a %>% bind_rows(.id = "origin")
                  # A tibble: 9 x 3
                  origin m1 m2
                  <chr> <int> <int>
                  1 1 1 1
                  2 1 2 2
                  3 1 3 3
                  4 1 4 4
                  5 1 5 5
                  6 1 6 6
                  7 1 7 7
                  8 1 8 8
                  9 1 9 9


                  This happens because m1 and m2 are vectors (because they are matrices) of the same length, and bind_rows sees a list of constant-length vectors as a single data-frame. So the latter call is equivalent to



                  bind_rows(data.frame(m1 = as.vector(m1), m2 = as.vector(m2)), .id = "origin")


                  So, make sure you convert your matrices to data.frames before you bind them together.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 8 at 11:45

























                  answered Nov 8 at 11:36









                  Russ Hyde

                  921513




                  921513
























                      up vote
                      1
                      down vote













                      You can do:



                      b <- do.call(rbind.data.frame, a)

                      # V1 V2 V3
                      #m1.1 1 4 7
                      #m1.2 2 5 8
                      #m1.3 3 6 9
                      #m2.1 1 4 7
                      #m2.2 2 5 8
                      #m2.3 3 6 9


                      or if you not happy with this,



                      b    <- do.call(rbind.data.frame, a)
                      b$id <- sub("[.].+", "", rownames(b))

                      # V1 V2 V3 id
                      #m1.1 1 4 7 m1
                      #m1.2 2 5 8 m1
                      #m1.3 3 6 9 m1
                      #m2.1 1 4 7 m2
                      #m2.2 2 5 8 m2
                      #m2.3 3 6 9 m2





                      share|improve this answer



























                        up vote
                        1
                        down vote













                        You can do:



                        b <- do.call(rbind.data.frame, a)

                        # V1 V2 V3
                        #m1.1 1 4 7
                        #m1.2 2 5 8
                        #m1.3 3 6 9
                        #m2.1 1 4 7
                        #m2.2 2 5 8
                        #m2.3 3 6 9


                        or if you not happy with this,



                        b    <- do.call(rbind.data.frame, a)
                        b$id <- sub("[.].+", "", rownames(b))

                        # V1 V2 V3 id
                        #m1.1 1 4 7 m1
                        #m1.2 2 5 8 m1
                        #m1.3 3 6 9 m1
                        #m2.1 1 4 7 m2
                        #m2.2 2 5 8 m2
                        #m2.3 3 6 9 m2





                        share|improve this answer

























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          You can do:



                          b <- do.call(rbind.data.frame, a)

                          # V1 V2 V3
                          #m1.1 1 4 7
                          #m1.2 2 5 8
                          #m1.3 3 6 9
                          #m2.1 1 4 7
                          #m2.2 2 5 8
                          #m2.3 3 6 9


                          or if you not happy with this,



                          b    <- do.call(rbind.data.frame, a)
                          b$id <- sub("[.].+", "", rownames(b))

                          # V1 V2 V3 id
                          #m1.1 1 4 7 m1
                          #m1.2 2 5 8 m1
                          #m1.3 3 6 9 m1
                          #m2.1 1 4 7 m2
                          #m2.2 2 5 8 m2
                          #m2.3 3 6 9 m2





                          share|improve this answer














                          You can do:



                          b <- do.call(rbind.data.frame, a)

                          # V1 V2 V3
                          #m1.1 1 4 7
                          #m1.2 2 5 8
                          #m1.3 3 6 9
                          #m2.1 1 4 7
                          #m2.2 2 5 8
                          #m2.3 3 6 9


                          or if you not happy with this,



                          b    <- do.call(rbind.data.frame, a)
                          b$id <- sub("[.].+", "", rownames(b))

                          # V1 V2 V3 id
                          #m1.1 1 4 7 m1
                          #m1.2 2 5 8 m1
                          #m1.3 3 6 9 m1
                          #m2.1 1 4 7 m2
                          #m2.2 2 5 8 m2
                          #m2.3 3 6 9 m2






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 8 at 11:51

























                          answered Nov 8 at 11:37









                          Andre Elrico

                          5,40311027




                          5,40311027






























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