Protecting against directory traversal












0














newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.



<%
if(request.getParameter("file")!=null)
{
String context = request.getContextPath();

int BUFSIZE = 4096;
String filePath;


filePath = request.getParameter("file");
File file = new File(getServletContext().getRealPath("/") +context);
file = new File(file.getParent()+"/documents/"+filePath);
int length = 0;
ServletOutputStream outStream = response.getOutputStream();
//response.setContentType("text/html");
response.setContentLength((int)file.length());
String fileName = (new File(filePath)).getName();
response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);

//response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);

byte byteBuffer = new byte[BUFSIZE];
DataInputStream in = new DataInputStream(new FileInputStream(file));

while ((in != null) && ((length = in.read(byteBuffer)) != -1))
{
outStream.write(byteBuffer,0,length);
}

in.close();
outStream.close();
}
else
{

}


%>










share|improve this question





























    0














    newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.



    <%
    if(request.getParameter("file")!=null)
    {
    String context = request.getContextPath();

    int BUFSIZE = 4096;
    String filePath;


    filePath = request.getParameter("file");
    File file = new File(getServletContext().getRealPath("/") +context);
    file = new File(file.getParent()+"/documents/"+filePath);
    int length = 0;
    ServletOutputStream outStream = response.getOutputStream();
    //response.setContentType("text/html");
    response.setContentLength((int)file.length());
    String fileName = (new File(filePath)).getName();
    response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);

    //response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);

    byte byteBuffer = new byte[BUFSIZE];
    DataInputStream in = new DataInputStream(new FileInputStream(file));

    while ((in != null) && ((length = in.read(byteBuffer)) != -1))
    {
    outStream.write(byteBuffer,0,length);
    }

    in.close();
    outStream.close();
    }
    else
    {

    }


    %>










    share|improve this question



























      0












      0








      0







      newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.



      <%
      if(request.getParameter("file")!=null)
      {
      String context = request.getContextPath();

      int BUFSIZE = 4096;
      String filePath;


      filePath = request.getParameter("file");
      File file = new File(getServletContext().getRealPath("/") +context);
      file = new File(file.getParent()+"/documents/"+filePath);
      int length = 0;
      ServletOutputStream outStream = response.getOutputStream();
      //response.setContentType("text/html");
      response.setContentLength((int)file.length());
      String fileName = (new File(filePath)).getName();
      response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);

      //response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);

      byte byteBuffer = new byte[BUFSIZE];
      DataInputStream in = new DataInputStream(new FileInputStream(file));

      while ((in != null) && ((length = in.read(byteBuffer)) != -1))
      {
      outStream.write(byteBuffer,0,length);
      }

      in.close();
      outStream.close();
      }
      else
      {

      }


      %>










      share|improve this question















      newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.



      <%
      if(request.getParameter("file")!=null)
      {
      String context = request.getContextPath();

      int BUFSIZE = 4096;
      String filePath;


      filePath = request.getParameter("file");
      File file = new File(getServletContext().getRealPath("/") +context);
      file = new File(file.getParent()+"/documents/"+filePath);
      int length = 0;
      ServletOutputStream outStream = response.getOutputStream();
      //response.setContentType("text/html");
      response.setContentLength((int)file.length());
      String fileName = (new File(filePath)).getName();
      response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);

      //response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);

      byte byteBuffer = new byte[BUFSIZE];
      DataInputStream in = new DataInputStream(new FileInputStream(file));

      while ((in != null) && ((length = in.read(byteBuffer)) != -1))
      {
      outStream.write(byteBuffer,0,length);
      }

      in.close();
      outStream.close();
      }
      else
      {

      }


      %>







      jsp web-applications url-encoding owasp directory-traversal






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 16:18

























      asked Nov 11 at 13:21









      averageCoder

      81




      81
























          1 Answer
          1






          active

          oldest

          votes


















          0














          The problem consist of the creation of the outputFile with a non trusted filename.
          Validate the filename will solve your PathTraversal.



          Example of a remediation :



          if (validateFileName(request.getParameter("file")));
          filePath = request.getParameter("file");
          else
          // Error


          //....
          //.....

          boolean validateFilename(String fileName)
          {
          // This represents the format /myapp/temp/<filename>
          String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
          File file = new File (fileName);
          Pattern p = Pattern.compile(goodPattern);
          Matcher m = p.matcher(file.getCanonicalPath());
          if (!m.matches())
          {
          return false;
          }
          return true;
          }


          See:




          • What's the best way to defend against a path traversal attack?

          • https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal

          • https://www.owasp.org/index.php/File_System#Path_traversal

          • https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them






          share|improve this answer





















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            1 Answer
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            active

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            active

            oldest

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            active

            oldest

            votes









            0














            The problem consist of the creation of the outputFile with a non trusted filename.
            Validate the filename will solve your PathTraversal.



            Example of a remediation :



            if (validateFileName(request.getParameter("file")));
            filePath = request.getParameter("file");
            else
            // Error


            //....
            //.....

            boolean validateFilename(String fileName)
            {
            // This represents the format /myapp/temp/<filename>
            String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
            File file = new File (fileName);
            Pattern p = Pattern.compile(goodPattern);
            Matcher m = p.matcher(file.getCanonicalPath());
            if (!m.matches())
            {
            return false;
            }
            return true;
            }


            See:




            • What's the best way to defend against a path traversal attack?

            • https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal

            • https://www.owasp.org/index.php/File_System#Path_traversal

            • https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them






            share|improve this answer


























              0














              The problem consist of the creation of the outputFile with a non trusted filename.
              Validate the filename will solve your PathTraversal.



              Example of a remediation :



              if (validateFileName(request.getParameter("file")));
              filePath = request.getParameter("file");
              else
              // Error


              //....
              //.....

              boolean validateFilename(String fileName)
              {
              // This represents the format /myapp/temp/<filename>
              String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
              File file = new File (fileName);
              Pattern p = Pattern.compile(goodPattern);
              Matcher m = p.matcher(file.getCanonicalPath());
              if (!m.matches())
              {
              return false;
              }
              return true;
              }


              See:




              • What's the best way to defend against a path traversal attack?

              • https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal

              • https://www.owasp.org/index.php/File_System#Path_traversal

              • https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them






              share|improve this answer
























                0












                0








                0






                The problem consist of the creation of the outputFile with a non trusted filename.
                Validate the filename will solve your PathTraversal.



                Example of a remediation :



                if (validateFileName(request.getParameter("file")));
                filePath = request.getParameter("file");
                else
                // Error


                //....
                //.....

                boolean validateFilename(String fileName)
                {
                // This represents the format /myapp/temp/<filename>
                String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
                File file = new File (fileName);
                Pattern p = Pattern.compile(goodPattern);
                Matcher m = p.matcher(file.getCanonicalPath());
                if (!m.matches())
                {
                return false;
                }
                return true;
                }


                See:




                • What's the best way to defend against a path traversal attack?

                • https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal

                • https://www.owasp.org/index.php/File_System#Path_traversal

                • https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them






                share|improve this answer












                The problem consist of the creation of the outputFile with a non trusted filename.
                Validate the filename will solve your PathTraversal.



                Example of a remediation :



                if (validateFileName(request.getParameter("file")));
                filePath = request.getParameter("file");
                else
                // Error


                //....
                //.....

                boolean validateFilename(String fileName)
                {
                // This represents the format /myapp/temp/<filename>
                String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
                File file = new File (fileName);
                Pattern p = Pattern.compile(goodPattern);
                Matcher m = p.matcher(file.getCanonicalPath());
                if (!m.matches())
                {
                return false;
                }
                return true;
                }


                See:




                • What's the best way to defend against a path traversal attack?

                • https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal

                • https://www.owasp.org/index.php/File_System#Path_traversal

                • https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 18 at 7:01









                SPoint

                1277




                1277






























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