Protecting against directory traversal
newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.
<%
if(request.getParameter("file")!=null)
{
String context = request.getContextPath();
int BUFSIZE = 4096;
String filePath;
filePath = request.getParameter("file");
File file = new File(getServletContext().getRealPath("/") +context);
file = new File(file.getParent()+"/documents/"+filePath);
int length = 0;
ServletOutputStream outStream = response.getOutputStream();
//response.setContentType("text/html");
response.setContentLength((int)file.length());
String fileName = (new File(filePath)).getName();
response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);
//response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);
byte byteBuffer = new byte[BUFSIZE];
DataInputStream in = new DataInputStream(new FileInputStream(file));
while ((in != null) && ((length = in.read(byteBuffer)) != -1))
{
outStream.write(byteBuffer,0,length);
}
in.close();
outStream.close();
}
else
{
}
%>
jsp web-applications url-encoding owasp directory-traversal
add a comment |
newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.
<%
if(request.getParameter("file")!=null)
{
String context = request.getContextPath();
int BUFSIZE = 4096;
String filePath;
filePath = request.getParameter("file");
File file = new File(getServletContext().getRealPath("/") +context);
file = new File(file.getParent()+"/documents/"+filePath);
int length = 0;
ServletOutputStream outStream = response.getOutputStream();
//response.setContentType("text/html");
response.setContentLength((int)file.length());
String fileName = (new File(filePath)).getName();
response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);
//response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);
byte byteBuffer = new byte[BUFSIZE];
DataInputStream in = new DataInputStream(new FileInputStream(file));
while ((in != null) && ((length = in.read(byteBuffer)) != -1))
{
outStream.write(byteBuffer,0,length);
}
in.close();
outStream.close();
}
else
{
}
%>
jsp web-applications url-encoding owasp directory-traversal
add a comment |
newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.
<%
if(request.getParameter("file")!=null)
{
String context = request.getContextPath();
int BUFSIZE = 4096;
String filePath;
filePath = request.getParameter("file");
File file = new File(getServletContext().getRealPath("/") +context);
file = new File(file.getParent()+"/documents/"+filePath);
int length = 0;
ServletOutputStream outStream = response.getOutputStream();
//response.setContentType("text/html");
response.setContentLength((int)file.length());
String fileName = (new File(filePath)).getName();
response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);
//response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);
byte byteBuffer = new byte[BUFSIZE];
DataInputStream in = new DataInputStream(new FileInputStream(file));
while ((in != null) && ((length = in.read(byteBuffer)) != -1))
{
outStream.write(byteBuffer,0,length);
}
in.close();
outStream.close();
}
else
{
}
%>
jsp web-applications url-encoding owasp directory-traversal
newbie here, int the following the it takes in a file as a parameter and concatenates it to the directory string, it then looks for the file and using streams fetches and serves the file to the browser for downloading. This code is susceptible to directory traversal and im not sure how to go about hardening the code to counteract this.
<%
if(request.getParameter("file")!=null)
{
String context = request.getContextPath();
int BUFSIZE = 4096;
String filePath;
filePath = request.getParameter("file");
File file = new File(getServletContext().getRealPath("/") +context);
file = new File(file.getParent()+"/documents/"+filePath);
int length = 0;
ServletOutputStream outStream = response.getOutputStream();
//response.setContentType("text/html");
response.setContentLength((int)file.length());
String fileName = (new File(filePath)).getName();
response.setHeader("Content-Disposition", "attachment; filename="" + fileName + """);
//response.setHeader("Content-Disposition", "attachment; filename="" +new Random().nextInt(10000)+ """);
byte byteBuffer = new byte[BUFSIZE];
DataInputStream in = new DataInputStream(new FileInputStream(file));
while ((in != null) && ((length = in.read(byteBuffer)) != -1))
{
outStream.write(byteBuffer,0,length);
}
in.close();
outStream.close();
}
else
{
}
%>
jsp web-applications url-encoding owasp directory-traversal
jsp web-applications url-encoding owasp directory-traversal
edited Nov 11 at 16:18
asked Nov 11 at 13:21
averageCoder
81
81
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The problem consist of the creation of the outputFile with a non trusted filename.
Validate the filename will solve your PathTraversal.
Example of a remediation :
if (validateFileName(request.getParameter("file")));
filePath = request.getParameter("file");
else
// Error
//....
//.....
boolean validateFilename(String fileName)
{
// This represents the format /myapp/temp/<filename>
String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
File file = new File (fileName);
Pattern p = Pattern.compile(goodPattern);
Matcher m = p.matcher(file.getCanonicalPath());
if (!m.matches())
{
return false;
}
return true;
}
See:
- What's the best way to defend against a path traversal attack?
- https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal
- https://www.owasp.org/index.php/File_System#Path_traversal
- https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem consist of the creation of the outputFile with a non trusted filename.
Validate the filename will solve your PathTraversal.
Example of a remediation :
if (validateFileName(request.getParameter("file")));
filePath = request.getParameter("file");
else
// Error
//....
//.....
boolean validateFilename(String fileName)
{
// This represents the format /myapp/temp/<filename>
String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
File file = new File (fileName);
Pattern p = Pattern.compile(goodPattern);
Matcher m = p.matcher(file.getCanonicalPath());
if (!m.matches())
{
return false;
}
return true;
}
See:
- What's the best way to defend against a path traversal attack?
- https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal
- https://www.owasp.org/index.php/File_System#Path_traversal
- https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them
add a comment |
The problem consist of the creation of the outputFile with a non trusted filename.
Validate the filename will solve your PathTraversal.
Example of a remediation :
if (validateFileName(request.getParameter("file")));
filePath = request.getParameter("file");
else
// Error
//....
//.....
boolean validateFilename(String fileName)
{
// This represents the format /myapp/temp/<filename>
String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
File file = new File (fileName);
Pattern p = Pattern.compile(goodPattern);
Matcher m = p.matcher(file.getCanonicalPath());
if (!m.matches())
{
return false;
}
return true;
}
See:
- What's the best way to defend against a path traversal attack?
- https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal
- https://www.owasp.org/index.php/File_System#Path_traversal
- https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them
add a comment |
The problem consist of the creation of the outputFile with a non trusted filename.
Validate the filename will solve your PathTraversal.
Example of a remediation :
if (validateFileName(request.getParameter("file")));
filePath = request.getParameter("file");
else
// Error
//....
//.....
boolean validateFilename(String fileName)
{
// This represents the format /myapp/temp/<filename>
String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
File file = new File (fileName);
Pattern p = Pattern.compile(goodPattern);
Matcher m = p.matcher(file.getCanonicalPath());
if (!m.matches())
{
return false;
}
return true;
}
See:
- What's the best way to defend against a path traversal attack?
- https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal
- https://www.owasp.org/index.php/File_System#Path_traversal
- https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them
The problem consist of the creation of the outputFile with a non trusted filename.
Validate the filename will solve your PathTraversal.
Example of a remediation :
if (validateFileName(request.getParameter("file")));
filePath = request.getParameter("file");
else
// Error
//....
//.....
boolean validateFilename(String fileName)
{
// This represents the format /myapp/temp/<filename>
String goodPattern = "/myapp/temp/(\w|\s|\.|-|){1,20}";
File file = new File (fileName);
Pattern p = Pattern.compile(goodPattern);
Matcher m = p.matcher(file.getCanonicalPath());
if (!m.matches())
{
return false;
}
return true;
}
See:
- What's the best way to defend against a path traversal attack?
- https://vulncat.fortify.com/en/detail?id=desc.dynamic.xtended_preview.path_manipulation_absolute_path_traversal
- https://www.owasp.org/index.php/File_System#Path_traversal
- https://wiki.sei.cmu.edu/confluence/display/java/FIO16-J.+Canonicalize+path+names+before+validating+them
answered Nov 18 at 7:01
SPoint
1277
1277
add a comment |
add a comment |
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