Creating nested dictionary dynamically in python

I am trying to create a nested dictionary dynamically using python.

for example I need to create a function that will take the nodes and construct a nested dictionary with these nodes.

For example:

inputs:
'customers.applicant.individual.first_name'

output:

customers : {

      applicant: {

                 individual:{

                              firstname: {}



             }

           }

         }

and for each node, i need to make sure if it exist already if it does than skip else create the node. Can anyone please provide any help on this.

Thanks

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

What have you tried so far?

– b-fg
Nov 14 '18 at 5:52

add a comment |

I am trying to create a nested dictionary dynamically using python.

for example I need to create a function that will take the nodes and construct a nested dictionary with these nodes.

For example:

inputs:
'customers.applicant.individual.first_name'

output:

customers : {

      applicant: {

                 individual:{

                              firstname: {}



             }

           }

         }

and for each node, i need to make sure if it exist already if it does than skip else create the node. Can anyone please provide any help on this.

Thanks

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

What have you tried so far?

– b-fg
Nov 14 '18 at 5:52

add a comment |

I am trying to create a nested dictionary dynamically using python.

for example I need to create a function that will take the nodes and construct a nested dictionary with these nodes.

For example:

inputs:
'customers.applicant.individual.first_name'

output:

customers : {

      applicant: {

                 individual:{

                              firstname: {}



             }

           }

         }

and for each node, i need to make sure if it exist already if it does than skip else create the node. Can anyone please provide any help on this.

Thanks

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

I am trying to create a nested dictionary dynamically using python.

for example I need to create a function that will take the nodes and construct a nested dictionary with these nodes.

For example:

inputs:
'customers.applicant.individual.first_name'

output:

customers : {

      applicant: {

                 individual:{

                              firstname: {}



             }

           }

         }

and for each node, i need to make sure if it exist already if it does than skip else create the node. Can anyone please provide any help on this.

Thanks

python python-3.x

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

edited Nov 14 '18 at 4:12

khelwood

30.7k74263

asked Nov 14 '18 at 3:37

skidwa

asked Nov 14 '18 at 3:37

skidwa

asked Nov 14 '18 at 3:37

skidwa

What have you tried so far?

– b-fg
Nov 14 '18 at 5:52

add a comment |

What have you tried so far?

– b-fg
Nov 14 '18 at 5:52

What have you tried so far?

– b-fg
Nov 14 '18 at 5:52

add a comment |

1 Answer
1

active

oldest

votes

You can take advantage of the fact that python dictionaries are mutable and do something like the following:

input_item1 = 'customers.applicant.individual.first_name.Bob'

input_item2 = 'customers.applicant.individual.first_name.Jim'



inputs = [input_item1, input_item2]

output_dictionary = dict()





for input_item in inputs:

    current_dict = output_dictionary

    for item in input_item.split('.'):   

        if item in current_dict:

            current_dict = current_dict[item]

        else:

            current_dict[item] = dict()

            current_dict = current_dict[item]



print(output_dictionary)

Basically, because dictionaries are mutable, if you modify 'current_dict', the entry in the larger dictionary that you are referencing gets updated too.

This gives an output of:

{'customers': {'applicant': {'individual': {'first_name': {'Bob': {}, 'Jim': {}}}}}}

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You can take advantage of the fact that python dictionaries are mutable and do something like the following:

input_item1 = 'customers.applicant.individual.first_name.Bob'

input_item2 = 'customers.applicant.individual.first_name.Jim'



inputs = [input_item1, input_item2]

output_dictionary = dict()





for input_item in inputs:

    current_dict = output_dictionary

    for item in input_item.split('.'):   

        if item in current_dict:

            current_dict = current_dict[item]

        else:

            current_dict[item] = dict()

            current_dict = current_dict[item]



print(output_dictionary)

Basically, because dictionaries are mutable, if you modify 'current_dict', the entry in the larger dictionary that you are referencing gets updated too.

This gives an output of:

{'customers': {'applicant': {'individual': {'first_name': {'Bob': {}, 'Jim': {}}}}}}

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

add a comment |

You can take advantage of the fact that python dictionaries are mutable and do something like the following:

input_item1 = 'customers.applicant.individual.first_name.Bob'

input_item2 = 'customers.applicant.individual.first_name.Jim'



inputs = [input_item1, input_item2]

output_dictionary = dict()





for input_item in inputs:

    current_dict = output_dictionary

    for item in input_item.split('.'):   

        if item in current_dict:

            current_dict = current_dict[item]

        else:

            current_dict[item] = dict()

            current_dict = current_dict[item]



print(output_dictionary)

Basically, because dictionaries are mutable, if you modify 'current_dict', the entry in the larger dictionary that you are referencing gets updated too.

This gives an output of:

{'customers': {'applicant': {'individual': {'first_name': {'Bob': {}, 'Jim': {}}}}}}

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

add a comment |

You can take advantage of the fact that python dictionaries are mutable and do something like the following:

input_item1 = 'customers.applicant.individual.first_name.Bob'

input_item2 = 'customers.applicant.individual.first_name.Jim'



inputs = [input_item1, input_item2]

output_dictionary = dict()





for input_item in inputs:

    current_dict = output_dictionary

    for item in input_item.split('.'):   

        if item in current_dict:

            current_dict = current_dict[item]

        else:

            current_dict[item] = dict()

            current_dict = current_dict[item]



print(output_dictionary)

Basically, because dictionaries are mutable, if you modify 'current_dict', the entry in the larger dictionary that you are referencing gets updated too.

This gives an output of:

{'customers': {'applicant': {'individual': {'first_name': {'Bob': {}, 'Jim': {}}}}}}

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

You can take advantage of the fact that python dictionaries are mutable and do something like the following:

input_item1 = 'customers.applicant.individual.first_name.Bob'

input_item2 = 'customers.applicant.individual.first_name.Jim'



inputs = [input_item1, input_item2]

output_dictionary = dict()





for input_item in inputs:

    current_dict = output_dictionary

    for item in input_item.split('.'):   

        if item in current_dict:

            current_dict = current_dict[item]

        else:

            current_dict[item] = dict()

            current_dict = current_dict[item]



print(output_dictionary)

Basically, because dictionaries are mutable, if you modify 'current_dict', the entry in the larger dictionary that you are referencing gets updated too.

This gives an output of:

{'customers': {'applicant': {'individual': {'first_name': {'Bob': {}, 'Jim': {}}}}}}

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

edited Nov 14 '18 at 9:30

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

answered Nov 14 '18 at 9:04

Andrew McDowell

1,6031216

add a comment |

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