Ambigous args when sourcing another bash file in a bash file












0















I create a bash file test.sh. The content of this bash is like below:



#!/bin/bash
#source another file
export ICS_START=/rdrive/ics/itools/unx/bin/
source $ICS_START/icssetup.sh

XMAIN=false
MAINLINE=false
STARTDIR=${PWD}

# Get args.
usage() {
echo "Usage: $0 [-t <timestamp>] [-m] [-x]"
exit 1
}
parse_args(){
while getopts "ht:mx" OPT; do
case $OPT in
t) DATE=${OPTARG};;
m) MAINLINE=true;;
x) XMAIN=true;;
h) usage;;
?) usage;;
esac
done
}
echo "$@"
parse_args "$@"
#other commands
myrun -d xxx -p xxx --time xxxx


I run this bash file with ./test.sh -t xxx -m -x



During this process,the second source command is affected by the args -t xxx -m -x, it always throw errors as :
Ambigous switch. Please use more characters. I think icssetup.sh also define these args so we have conflicts with each other. How could I avoid this without changing arg characters?



I checked that the first two lines(source command) and the parse_args can both work well separately.



Any help would be appreciated.










share|improve this question



























    0















    I create a bash file test.sh. The content of this bash is like below:



    #!/bin/bash
    #source another file
    export ICS_START=/rdrive/ics/itools/unx/bin/
    source $ICS_START/icssetup.sh

    XMAIN=false
    MAINLINE=false
    STARTDIR=${PWD}

    # Get args.
    usage() {
    echo "Usage: $0 [-t <timestamp>] [-m] [-x]"
    exit 1
    }
    parse_args(){
    while getopts "ht:mx" OPT; do
    case $OPT in
    t) DATE=${OPTARG};;
    m) MAINLINE=true;;
    x) XMAIN=true;;
    h) usage;;
    ?) usage;;
    esac
    done
    }
    echo "$@"
    parse_args "$@"
    #other commands
    myrun -d xxx -p xxx --time xxxx


    I run this bash file with ./test.sh -t xxx -m -x



    During this process,the second source command is affected by the args -t xxx -m -x, it always throw errors as :
    Ambigous switch. Please use more characters. I think icssetup.sh also define these args so we have conflicts with each other. How could I avoid this without changing arg characters?



    I checked that the first two lines(source command) and the parse_args can both work well separately.



    Any help would be appreciated.










    share|improve this question

























      0












      0








      0








      I create a bash file test.sh. The content of this bash is like below:



      #!/bin/bash
      #source another file
      export ICS_START=/rdrive/ics/itools/unx/bin/
      source $ICS_START/icssetup.sh

      XMAIN=false
      MAINLINE=false
      STARTDIR=${PWD}

      # Get args.
      usage() {
      echo "Usage: $0 [-t <timestamp>] [-m] [-x]"
      exit 1
      }
      parse_args(){
      while getopts "ht:mx" OPT; do
      case $OPT in
      t) DATE=${OPTARG};;
      m) MAINLINE=true;;
      x) XMAIN=true;;
      h) usage;;
      ?) usage;;
      esac
      done
      }
      echo "$@"
      parse_args "$@"
      #other commands
      myrun -d xxx -p xxx --time xxxx


      I run this bash file with ./test.sh -t xxx -m -x



      During this process,the second source command is affected by the args -t xxx -m -x, it always throw errors as :
      Ambigous switch. Please use more characters. I think icssetup.sh also define these args so we have conflicts with each other. How could I avoid this without changing arg characters?



      I checked that the first two lines(source command) and the parse_args can both work well separately.



      Any help would be appreciated.










      share|improve this question














      I create a bash file test.sh. The content of this bash is like below:



      #!/bin/bash
      #source another file
      export ICS_START=/rdrive/ics/itools/unx/bin/
      source $ICS_START/icssetup.sh

      XMAIN=false
      MAINLINE=false
      STARTDIR=${PWD}

      # Get args.
      usage() {
      echo "Usage: $0 [-t <timestamp>] [-m] [-x]"
      exit 1
      }
      parse_args(){
      while getopts "ht:mx" OPT; do
      case $OPT in
      t) DATE=${OPTARG};;
      m) MAINLINE=true;;
      x) XMAIN=true;;
      h) usage;;
      ?) usage;;
      esac
      done
      }
      echo "$@"
      parse_args "$@"
      #other commands
      myrun -d xxx -p xxx --time xxxx


      I run this bash file with ./test.sh -t xxx -m -x



      During this process,the second source command is affected by the args -t xxx -m -x, it always throw errors as :
      Ambigous switch. Please use more characters. I think icssetup.sh also define these args so we have conflicts with each other. How could I avoid this without changing arg characters?



      I checked that the first two lines(source command) and the parse_args can both work well separately.



      Any help would be appreciated.







      bash






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 6:55









      lionellionel

      10319




      10319
























          1 Answer
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          0














          This is something that happens with bash but not other shells. The arguments of your script are passed to any sourced script.



          A simple example showing this:



          test.sh



          #!/bin/bash

          source source.sh
          echo Original Script: $# : $@


          source.sh



          #!/bin/bash

          echo Sourced Script $# : $@


          When you run test.sh, you see that even if no arguments are passed to the sourced script, it actually receives the original script arguments:



          # ./test.sh a b
          Sourced Script 2 : a b
          Original script: 2 : a b


          If you're attempting to pass no arguments to the sourced script, you might try to force it like:



          source $ICS_START/icssetup.sh ""





          share|improve this answer























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            0














            This is something that happens with bash but not other shells. The arguments of your script are passed to any sourced script.



            A simple example showing this:



            test.sh



            #!/bin/bash

            source source.sh
            echo Original Script: $# : $@


            source.sh



            #!/bin/bash

            echo Sourced Script $# : $@


            When you run test.sh, you see that even if no arguments are passed to the sourced script, it actually receives the original script arguments:



            # ./test.sh a b
            Sourced Script 2 : a b
            Original script: 2 : a b


            If you're attempting to pass no arguments to the sourced script, you might try to force it like:



            source $ICS_START/icssetup.sh ""





            share|improve this answer




























              0














              This is something that happens with bash but not other shells. The arguments of your script are passed to any sourced script.



              A simple example showing this:



              test.sh



              #!/bin/bash

              source source.sh
              echo Original Script: $# : $@


              source.sh



              #!/bin/bash

              echo Sourced Script $# : $@


              When you run test.sh, you see that even if no arguments are passed to the sourced script, it actually receives the original script arguments:



              # ./test.sh a b
              Sourced Script 2 : a b
              Original script: 2 : a b


              If you're attempting to pass no arguments to the sourced script, you might try to force it like:



              source $ICS_START/icssetup.sh ""





              share|improve this answer


























                0












                0








                0







                This is something that happens with bash but not other shells. The arguments of your script are passed to any sourced script.



                A simple example showing this:



                test.sh



                #!/bin/bash

                source source.sh
                echo Original Script: $# : $@


                source.sh



                #!/bin/bash

                echo Sourced Script $# : $@


                When you run test.sh, you see that even if no arguments are passed to the sourced script, it actually receives the original script arguments:



                # ./test.sh a b
                Sourced Script 2 : a b
                Original script: 2 : a b


                If you're attempting to pass no arguments to the sourced script, you might try to force it like:



                source $ICS_START/icssetup.sh ""





                share|improve this answer













                This is something that happens with bash but not other shells. The arguments of your script are passed to any sourced script.



                A simple example showing this:



                test.sh



                #!/bin/bash

                source source.sh
                echo Original Script: $# : $@


                source.sh



                #!/bin/bash

                echo Sourced Script $# : $@


                When you run test.sh, you see that even if no arguments are passed to the sourced script, it actually receives the original script arguments:



                # ./test.sh a b
                Sourced Script 2 : a b
                Original script: 2 : a b


                If you're attempting to pass no arguments to the sourced script, you might try to force it like:



                source $ICS_START/icssetup.sh ""






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 23 '18 at 19:22









                Alexandre JumaAlexandre Juma

                542315




                542315
































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