Python - load an in-memory ZipFile object as bytes
1
I have a script which creates a closed in-memory ZipFile object that I need to post as a bytestring (using requests); how do I do that? I have tried opening the file, which fails with "TypeError: expected str, bytes or os.PathLike object, not ZipFile"
The script works just fine if I write the ZipFile to a file and then open that file for the post data. However it will probably iterate over a couple million files, and that seems like a lot of temp files, and disk activity.
import io
import zipfile
from PIL import Image
z = io.BytesIO()
zfile = zipfile.ZipFile(z,"a")
zipdict = {}
img_loc = "D:/Images/seasons-3.jpg"
im_original = Image.open(img_loc)
imfmt = im_original.format
im = im_original.copy()
im_original.close()
im_out = io.BytesIO()
im.save(im_out,imfmt)
zfile.writestr("seasons-3.jpg",im_out.getvalue())
im_out.close()
zipdict['seasons-3']=zfile
zfile.close()
running with error:
Python 3.6.3 (v3.6.3:2c5fed8, Oct 3 2017, 18:11:49) [MSC v.1900 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
>>> zipdict['seasons-3']
<zipfile.ZipFile [closed]>
>>> pl_data = open(zipdict['seasons-3'])
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
pl_data = open(zipdict['seasons-3'])
TypeError: expected str, bytes or os.PathLike object, not ZipFile
>>>
python python-requests zipfile bytesio
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
|
show 4 more comments
1
I have a script which creates a closed in-memory ZipFile object that I need to post as a bytestring (using requests); how do I do that? I have tried opening the file, which fails with "TypeError: expected str, bytes or os.PathLike object, not ZipFile"
The script works just fine if I write the ZipFile to a file and then open that file for the post data. However it will probably iterate over a couple million files, and that seems like a lot of temp files, and disk activity.
import io
import zipfile
from PIL import Image
z = io.BytesIO()
zfile = zipfile.ZipFile(z,"a")
zipdict = {}
img_loc = "D:/Images/seasons-3.jpg"
im_original = Image.open(img_loc)
imfmt = im_original.format
im = im_original.copy()
im_original.close()
im_out = io.BytesIO()
im.save(im_out,imfmt)
zfile.writestr("seasons-3.jpg",im_out.getvalue())
im_out.close()
zipdict['seasons-3']=zfile
zfile.close()
running with error:
Python 3.6.3 (v3.6.3:2c5fed8, Oct 3 2017, 18:11:49) [MSC v.1900 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
>>> zipdict['seasons-3']
<zipfile.ZipFile [closed]>
>>> pl_data = open(zipdict['seasons-3'])
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
pl_data = open(zipdict['seasons-3'])
TypeError: expected str, bytes or os.PathLike object, not ZipFile
>>>
python python-requests zipfile bytesio
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
1
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
2
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33
|
show 4 more comments
1
1
1
I have a script which creates a closed in-memory ZipFile object that I need to post as a bytestring (using requests); how do I do that? I have tried opening the file, which fails with "TypeError: expected str, bytes or os.PathLike object, not ZipFile"
The script works just fine if I write the ZipFile to a file and then open that file for the post data. However it will probably iterate over a couple million files, and that seems like a lot of temp files, and disk activity.
import io
import zipfile
from PIL import Image
z = io.BytesIO()
zfile = zipfile.ZipFile(z,"a")
zipdict = {}
img_loc = "D:/Images/seasons-3.jpg"
im_original = Image.open(img_loc)
imfmt = im_original.format
im = im_original.copy()
im_original.close()
im_out = io.BytesIO()
im.save(im_out,imfmt)
zfile.writestr("seasons-3.jpg",im_out.getvalue())
im_out.close()
zipdict['seasons-3']=zfile
zfile.close()
running with error:
Python 3.6.3 (v3.6.3:2c5fed8, Oct 3 2017, 18:11:49) [MSC v.1900 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
>>> zipdict['seasons-3']
<zipfile.ZipFile [closed]>
>>> pl_data = open(zipdict['seasons-3'])
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
pl_data = open(zipdict['seasons-3'])
TypeError: expected str, bytes or os.PathLike object, not ZipFile
>>>
python python-requests zipfile bytesio
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
I have a script which creates a closed in-memory ZipFile object that I need to post as a bytestring (using requests); how do I do that? I have tried opening the file, which fails with "TypeError: expected str, bytes or os.PathLike object, not ZipFile"
The script works just fine if I write the ZipFile to a file and then open that file for the post data. However it will probably iterate over a couple million files, and that seems like a lot of temp files, and disk activity.
import io
import zipfile
from PIL import Image
z = io.BytesIO()
zfile = zipfile.ZipFile(z,"a")
zipdict = {}
img_loc = "D:/Images/seasons-3.jpg"
im_original = Image.open(img_loc)
imfmt = im_original.format
im = im_original.copy()
im_original.close()
im_out = io.BytesIO()
im.save(im_out,imfmt)
zfile.writestr("seasons-3.jpg",im_out.getvalue())
im_out.close()
zipdict['seasons-3']=zfile
zfile.close()
running with error:
Python 3.6.3 (v3.6.3:2c5fed8, Oct 3 2017, 18:11:49) [MSC v.1900 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
>>> zipdict['seasons-3']
<zipfile.ZipFile [closed]>
>>> pl_data = open(zipdict['seasons-3'])
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
pl_data = open(zipdict['seasons-3'])
TypeError: expected str, bytes or os.PathLike object, not ZipFile
>>>
python python-requests zipfile bytesio
python python-requests zipfile bytesio
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
edited Nov 21 '18 at 8:19
Tim Achee
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
asked Nov 20 '18 at 16:47
Tim AcheeTim Achee
122
122
1
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
2
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33
|
show 4 more comments
1
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
2
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33
1
1
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
2
2
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33
|
show 4 more comments
1 Answer
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zfile is closed. It's useless to you. The thing you need to use now is z, the file-like object that was managing the underlying binary storage for the ZipFile.
You can use z.getvalue() to get a bytestring representing the contents of z, just like you did with im_out, or you can seek back to the beginning with z.seek(0) and use it with the parts of requests that take file-like objects.
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else intozbesides the zip contents. It's hard to tell from here.
– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
|
show 4 more comments
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zfile is closed. It's useless to you. The thing you need to use now is z, the file-like object that was managing the underlying binary storage for the ZipFile.
You can use z.getvalue() to get a bytestring representing the contents of z, just like you did with im_out, or you can seek back to the beginning with z.seek(0) and use it with the parts of requests that take file-like objects.
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else intozbesides the zip contents. It's hard to tell from here.
– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
|
show 4 more comments
0
zfile is closed. It's useless to you. The thing you need to use now is z, the file-like object that was managing the underlying binary storage for the ZipFile.
You can use z.getvalue() to get a bytestring representing the contents of z, just like you did with im_out, or you can seek back to the beginning with z.seek(0) and use it with the parts of requests that take file-like objects.
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else intozbesides the zip contents. It's hard to tell from here.
– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
|
show 4 more comments
0
0
0
zfile is closed. It's useless to you. The thing you need to use now is z, the file-like object that was managing the underlying binary storage for the ZipFile.
You can use z.getvalue() to get a bytestring representing the contents of z, just like you did with im_out, or you can seek back to the beginning with z.seek(0) and use it with the parts of requests that take file-like objects.
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
zfile is closed. It's useless to you. The thing you need to use now is z, the file-like object that was managing the underlying binary storage for the ZipFile.
You can use z.getvalue() to get a bytestring representing the contents of z, just like you did with im_out, or you can seek back to the beginning with z.seek(0) and use it with the parts of requests that take file-like objects.
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
answered Nov 21 '18 at 8:57
user2357112user2357112
156k12168263
156k12168263
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else intozbesides the zip contents. It's hard to tell from here.
– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
|
show 4 more comments
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else intozbesides the zip contents. It's hard to tell from here.
– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
thank you user2357112, but I need to post the data as a bytestring of a zipped file so I'm not sure this solution would work out.
– Tim Achee
Nov 21 '18 at 9:20
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
@TimAchee: What makes you think this wouldn't work? It sounds like you're misunderstanding the role of the ZipFile object.
– user2357112
Nov 21 '18 at 19:21
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
thank you again and sorry for the delay in responding. I second guessed myself yesterday morning and came to pretty much the same conclusion. So I tried uploading z.getvalue() as my data. While the file uploaded to the server, the system I was trying to ingest into rejected it with "Error (archive is not a ZIP archive) occurred while unzipping file"
– Tim Achee
Nov 22 '18 at 7:35
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else into
z besides the zip contents. It's hard to tell from here.– user2357112
Nov 22 '18 at 7:52
@TimAchee: Could be a problem with how you're interacting with the web API, or perhaps you accidentally put something else into
z besides the zip contents. It's hard to tell from here.– user2357112
Nov 22 '18 at 7:52
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
yeah, when I run the script saving the zip to disk and using open(path_to_saved_zip) instead of z.getvalue(), everything works. If I understand you correctly, z.getvalue() should be equivalent to open(saved_zip), right?
– Tim Achee
Nov 22 '18 at 8:46
|
show 4 more comments
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1
Can you paste your code and error traceback?
– Cheche
Nov 20 '18 at 16:51
2
"closed in-memory ZipFile" - you're going to have to explain that some more. Did you wrap a ZipFile around a BytesIO or something?
– user2357112
Nov 20 '18 at 16:51
I'm not sure if it helps with an in-memory zip-file (never encountered one in the wild), but you can unzip a single file from an archive: stackoverflow.com/a/46423414/962190
– Arne
Nov 20 '18 at 16:56
@user2357112 that's pretty much exactly what I did. I created a ZipFile and used writestr to add a couple of BytesIO to the ZipFile. Then I added the ZipFile as value to a dict, with key as filename, and closed the ZipFile.
– Tim Achee
Nov 21 '18 at 7:13
@TimAchee: Nope, that still doesn't explain things. What, if anything, did you do to put the ZipFile itself in memory? What arguments did you pass to the ZipFile constructor?
– user2357112
Nov 21 '18 at 7:33