Plotting a parabola in two segments
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I'd like to know how to plot the following function, defined by the red lines:
I've previously plotted a rectangle, which is easier because I just draw lines between the different points and that's it, but in this one I don't know how to join the extreme points (1, 1) and (5, 1) with the function y = sqrt(x) instead of a straight line.
Thanks.
matlab plot matlab-figure
edited Nov 24 '18 at 23:19
EBH
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
add a comment |
I'd like to know how to plot the following function, defined by the red lines:
I've previously plotted a rectangle, which is easier because I just draw lines between the different points and that's it, but in this one I don't know how to join the extreme points (1, 1) and (5, 1) with the function y = sqrt(x) instead of a straight line.
Thanks.
matlab plot matlab-figure
edited Nov 24 '18 at 23:19
EBH
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51
add a comment |
I'd like to know how to plot the following function, defined by the red lines:
I've previously plotted a rectangle, which is easier because I just draw lines between the different points and that's it, but in this one I don't know how to join the extreme points (1, 1) and (5, 1) with the function y = sqrt(x) instead of a straight line.
Thanks.
matlab plot matlab-figure
edited Nov 24 '18 at 23:19
EBH
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
I'd like to know how to plot the following function, defined by the red lines:
I've previously plotted a rectangle, which is easier because I just draw lines between the different points and that's it, but in this one I don't know how to join the extreme points (1, 1) and (5, 1) with the function y = sqrt(x) instead of a straight line.
Thanks.
matlab plot matlab-figure
matlab plot matlab-figure
edited Nov 24 '18 at 23:19
EBH
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
edited Nov 24 '18 at 23:19
EBH
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
edited Nov 24 '18 at 23:19
EBH
9,50832351
edited Nov 24 '18 at 23:19
EBH
9,50832351
edited Nov 24 '18 at 23:19
EBH
9,50832351
9,50832351
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
asked Nov 23 '18 at 16:36
Nicolás UlmeteNicolás Ulmete
132
132
Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51
add a comment |
Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51
Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51
add a comment |
2 Answers
2
active
oldest
votes
I think, this is what you want to achieve. The keypoint being I guess, you were not sure that how to calculate the y-coordinate value. That is, when I plote the vertical red line, for the y coordinate, I input sqrt(5). This you see in the 9th line in the code snippet below.
clear;
clc;
figure(1);
clf;
x=0:0.01:6;
y=sqrt(x);
plot(x,y, 'LineWidth',2);
hold on;
plot([1 5], [1 1], 'r', 'LineWidth',2);
plot([5 5], [sqrt(5) 1], 'r', 'LineWidth',2);
grid on;
xlim([-2 6]);
ylim([-1 3]);
xlabel('x');
ylabel('y');
title('y=sqrt(x)');
text(1.01, 0.85,'(1; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(5.01, 0.85,'(5; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(2,0.5+sqrt(2),'downarrow y=surd x', 'HorizontalAlignment','left' ...
, 'FontSize', 12, 'FontWeight', 'bold')
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
add a comment |
You can do it with this short piece of code:
y = @(x) sqrt(x);
fplot(y,[0 6])% draw the function between x=0 to x=6
hold on
fplot(y,[1 5],'r') % draw the red part of the function
plot([1 5;5 5],[1 1;1 y(5)],'r') % draw the straight lines
hold off
grid on
xlim([-2 6])
ylim([-1 3])
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think, this is what you want to achieve. The keypoint being I guess, you were not sure that how to calculate the y-coordinate value. That is, when I plote the vertical red line, for the y coordinate, I input sqrt(5). This you see in the 9th line in the code snippet below.
clear;
clc;
figure(1);
clf;
x=0:0.01:6;
y=sqrt(x);
plot(x,y, 'LineWidth',2);
hold on;
plot([1 5], [1 1], 'r', 'LineWidth',2);
plot([5 5], [sqrt(5) 1], 'r', 'LineWidth',2);
grid on;
xlim([-2 6]);
ylim([-1 3]);
xlabel('x');
ylabel('y');
title('y=sqrt(x)');
text(1.01, 0.85,'(1; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(5.01, 0.85,'(5; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(2,0.5+sqrt(2),'downarrow y=surd x', 'HorizontalAlignment','left' ...
, 'FontSize', 12, 'FontWeight', 'bold')
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
add a comment |
I think, this is what you want to achieve. The keypoint being I guess, you were not sure that how to calculate the y-coordinate value. That is, when I plote the vertical red line, for the y coordinate, I input sqrt(5). This you see in the 9th line in the code snippet below.
clear;
clc;
figure(1);
clf;
x=0:0.01:6;
y=sqrt(x);
plot(x,y, 'LineWidth',2);
hold on;
plot([1 5], [1 1], 'r', 'LineWidth',2);
plot([5 5], [sqrt(5) 1], 'r', 'LineWidth',2);
grid on;
xlim([-2 6]);
ylim([-1 3]);
xlabel('x');
ylabel('y');
title('y=sqrt(x)');
text(1.01, 0.85,'(1; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(5.01, 0.85,'(5; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(2,0.5+sqrt(2),'downarrow y=surd x', 'HorizontalAlignment','left' ...
, 'FontSize', 12, 'FontWeight', 'bold')
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
add a comment |
I think, this is what you want to achieve. The keypoint being I guess, you were not sure that how to calculate the y-coordinate value. That is, when I plote the vertical red line, for the y coordinate, I input sqrt(5). This you see in the 9th line in the code snippet below.
clear;
clc;
figure(1);
clf;
x=0:0.01:6;
y=sqrt(x);
plot(x,y, 'LineWidth',2);
hold on;
plot([1 5], [1 1], 'r', 'LineWidth',2);
plot([5 5], [sqrt(5) 1], 'r', 'LineWidth',2);
grid on;
xlim([-2 6]);
ylim([-1 3]);
xlabel('x');
ylabel('y');
title('y=sqrt(x)');
text(1.01, 0.85,'(1; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(5.01, 0.85,'(5; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(2,0.5+sqrt(2),'downarrow y=surd x', 'HorizontalAlignment','left' ...
, 'FontSize', 12, 'FontWeight', 'bold')
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
I think, this is what you want to achieve. The keypoint being I guess, you were not sure that how to calculate the y-coordinate value. That is, when I plote the vertical red line, for the y coordinate, I input sqrt(5). This you see in the 9th line in the code snippet below.
clear;
clc;
figure(1);
clf;
x=0:0.01:6;
y=sqrt(x);
plot(x,y, 'LineWidth',2);
hold on;
plot([1 5], [1 1], 'r', 'LineWidth',2);
plot([5 5], [sqrt(5) 1], 'r', 'LineWidth',2);
grid on;
xlim([-2 6]);
ylim([-1 3]);
xlabel('x');
ylabel('y');
title('y=sqrt(x)');
text(1.01, 0.85,'(1; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(5.01, 0.85,'(5; 1)', 'HorizontalAlignment','left', 'FontSize', 12, ...
'FontWeight', 'bold')
text(2,0.5+sqrt(2),'downarrow y=surd x', 'HorizontalAlignment','left' ...
, 'FontSize', 12, 'FontWeight', 'bold')
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
edited Nov 23 '18 at 18:30
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
answered Nov 23 '18 at 18:18
Joey MalloneJoey Mallone
2,31861933
2,31861933
add a comment |
add a comment |
You can do it with this short piece of code:
y = @(x) sqrt(x);
fplot(y,[0 6])% draw the function between x=0 to x=6
hold on
fplot(y,[1 5],'r') % draw the red part of the function
plot([1 5;5 5],[1 1;1 y(5)],'r') % draw the straight lines
hold off
grid on
xlim([-2 6])
ylim([-1 3])
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
add a comment |
You can do it with this short piece of code:
y = @(x) sqrt(x);
fplot(y,[0 6])% draw the function between x=0 to x=6
hold on
fplot(y,[1 5],'r') % draw the red part of the function
plot([1 5;5 5],[1 1;1 y(5)],'r') % draw the straight lines
hold off
grid on
xlim([-2 6])
ylim([-1 3])
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
add a comment |
You can do it with this short piece of code:
y = @(x) sqrt(x);
fplot(y,[0 6])% draw the function between x=0 to x=6
hold on
fplot(y,[1 5],'r') % draw the red part of the function
plot([1 5;5 5],[1 1;1 y(5)],'r') % draw the straight lines
hold off
grid on
xlim([-2 6])
ylim([-1 3])
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
You can do it with this short piece of code:
y = @(x) sqrt(x);
fplot(y,[0 6])% draw the function between x=0 to x=6
hold on
fplot(y,[1 5],'r') % draw the red part of the function
plot([1 5;5 5],[1 1;1 y(5)],'r') % draw the straight lines
hold off
grid on
xlim([-2 6])
ylim([-1 3])
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
edited Nov 24 '18 at 23:11
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
answered Nov 24 '18 at 23:06
EBHEBH
9,50832351
9,50832351
add a comment |
add a comment |
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Hint: you can draw any curve by approximating it with short bits of straight line.
– Cris Luengo
Nov 24 '18 at 14:09
Did none of the answers below solve your problem?
– EBH
Dec 2 '18 at 6:51