Can I create a multidimensional array using single arrays to fill?
up vote
1
down vote
favorite
Say I had two randomly generated arrays (rows and columns) and I want them to be used to fill a multidimensional array. With the arrays being rows and columns, the multidimensional array would be matrix[rows][columns]. Just an example of how I generated rows:
int rows = new int[20];
for(int i = 0; i < rows.length; i++) {
rows[i] = (int)(Math.random()*1000 + 1);
}
System.out.println("Rows Generated: " + Arrays.toString(randomArrayN));
}
}
The columns array was also built this way. Is there an easy way to create a two-dimension array and use these arrays to fill them?
I know this syntax is wrong but basically I want to know if there is a way to do this:
int matrix = new int[rows][columns];
java arrays multidimensional-array
add a comment |
up vote
1
down vote
favorite
Say I had two randomly generated arrays (rows and columns) and I want them to be used to fill a multidimensional array. With the arrays being rows and columns, the multidimensional array would be matrix[rows][columns]. Just an example of how I generated rows:
int rows = new int[20];
for(int i = 0; i < rows.length; i++) {
rows[i] = (int)(Math.random()*1000 + 1);
}
System.out.println("Rows Generated: " + Arrays.toString(randomArrayN));
}
}
The columns array was also built this way. Is there an easy way to create a two-dimension array and use these arrays to fill them?
I know this syntax is wrong but basically I want to know if there is a way to do this:
int matrix = new int[rows][columns];
java arrays multidimensional-array
1
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
4
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
1
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
As explained above, consider you haverows = {1, 2, 3}
andcolumns = {3, 4, 6}
. If you gotmatrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?
– Glains
Nov 9 at 16:41
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Say I had two randomly generated arrays (rows and columns) and I want them to be used to fill a multidimensional array. With the arrays being rows and columns, the multidimensional array would be matrix[rows][columns]. Just an example of how I generated rows:
int rows = new int[20];
for(int i = 0; i < rows.length; i++) {
rows[i] = (int)(Math.random()*1000 + 1);
}
System.out.println("Rows Generated: " + Arrays.toString(randomArrayN));
}
}
The columns array was also built this way. Is there an easy way to create a two-dimension array and use these arrays to fill them?
I know this syntax is wrong but basically I want to know if there is a way to do this:
int matrix = new int[rows][columns];
java arrays multidimensional-array
Say I had two randomly generated arrays (rows and columns) and I want them to be used to fill a multidimensional array. With the arrays being rows and columns, the multidimensional array would be matrix[rows][columns]. Just an example of how I generated rows:
int rows = new int[20];
for(int i = 0; i < rows.length; i++) {
rows[i] = (int)(Math.random()*1000 + 1);
}
System.out.println("Rows Generated: " + Arrays.toString(randomArrayN));
}
}
The columns array was also built this way. Is there an easy way to create a two-dimension array and use these arrays to fill them?
I know this syntax is wrong but basically I want to know if there is a way to do this:
int matrix = new int[rows][columns];
java arrays multidimensional-array
java arrays multidimensional-array
asked Nov 9 at 15:59
Benjamin Dare Edwards
819
819
1
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
4
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
1
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
As explained above, consider you haverows = {1, 2, 3}
andcolumns = {3, 4, 6}
. If you gotmatrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?
– Glains
Nov 9 at 16:41
add a comment |
1
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
4
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
1
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
As explained above, consider you haverows = {1, 2, 3}
andcolumns = {3, 4, 6}
. If you gotmatrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?
– Glains
Nov 9 at 16:41
1
1
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
4
4
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
1
1
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
As explained above, consider you have
rows = {1, 2, 3}
and columns = {3, 4, 6}
. If you got matrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?– Glains
Nov 9 at 16:41
As explained above, consider you have
rows = {1, 2, 3}
and columns = {3, 4, 6}
. If you got matrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?– Glains
Nov 9 at 16:41
add a comment |
3 Answers
3
active
oldest
votes
up vote
1
down vote
If you need a 2d array filled with random ints, you can use a nested loop similar to what you used to genrate your rows above:
public static void main(String args) {
int matrix = new int[20][20];
for(int i = 0; i < matrix.length; i++){
for(int j = 0; j < matrix[i].length; j++){
matrix[i][j] = (int)(Math.random()*1000 + 1);
}
}
for(int row : matrix){
System.out.println(Arrays.toString(row));
}
}
add a comment |
up vote
0
down vote
Yea you definitely can, though it may be a bit more confusing.
You can initalize the 3d array with this:
// test is a 3d array
int test = {
{
{1, -2, 3},
{2, 3, 4}
},
{
{-4, -5, 6, 9},
{1},
{2, 3}
}
};
I like to think this in terms or 3d obects, like a regtangluar prism. Each row (height)on the prism hold 2 things Length and Width, or a x,y. in other worlds you have a 2d array, one value is the column, the other is the row, in an array making it 3d.
now what if you want to print out values of the 3d array?
simply do this :
for (int array2D: test) {
for (int array1D: array2D) {
for(int item: array1D) {
System.out.println(item);
}
}
}
add a comment |
up vote
0
down vote
Although it's convenient to think of a 2-dimensional array in terms of rows and columns, a 2-dimensional array is just an array of arrays.
For example,
int values1 = {1, 2 ,3};
int matrix1 = {values1, values1, values1};
matrix1[1][1] = 42;
System.out.println(matrix1[0][1]);
System.out.println(matrix1[1][1]);
System.out.println(matrix1[2][1]);
or
int values2 = {1, 2 ,3};
int matrix2 = new int[3][3];
matrix2[0] = values2;
matrix2[1] = values2;
matrix2[2] = values2;
matrix2[1][1] = 42;
System.out.println(matrix2[0][1]);
System.out.println(matrix2[1][1]);
System.out.println(matrix2[2][1]);
Note that in both cases a values array is used multiple times to initialize each row of the matrix. So any change to any matrix element is reflected in the other rows (since each row is actually the same array). There may be cases where this is useful. If the elements need to be independent then use something like this:
int values3 = {1, 2 ,3};
int matrix3 = new int[3][3];
System.arraycopy(values3, 0, matrix3[0], 0, values3.length);
System.arraycopy(values3, 0, matrix3[1], 0, values3.length);
System.arraycopy(values3, 0, matrix3[2], 0, values3.length);
matrix3[1][1] = 42;
System.out.println(matrix3[0][1]);
System.out.println(matrix3[1][1]);
System.out.println(matrix3[2][1]);
Each row of the matrix is initialized with a copy of the same value, but making changes to any element is independent of any other element (since it's a different array).
Also see this other question if the matrix needs to be initialized element by element.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
If you need a 2d array filled with random ints, you can use a nested loop similar to what you used to genrate your rows above:
public static void main(String args) {
int matrix = new int[20][20];
for(int i = 0; i < matrix.length; i++){
for(int j = 0; j < matrix[i].length; j++){
matrix[i][j] = (int)(Math.random()*1000 + 1);
}
}
for(int row : matrix){
System.out.println(Arrays.toString(row));
}
}
add a comment |
up vote
1
down vote
If you need a 2d array filled with random ints, you can use a nested loop similar to what you used to genrate your rows above:
public static void main(String args) {
int matrix = new int[20][20];
for(int i = 0; i < matrix.length; i++){
for(int j = 0; j < matrix[i].length; j++){
matrix[i][j] = (int)(Math.random()*1000 + 1);
}
}
for(int row : matrix){
System.out.println(Arrays.toString(row));
}
}
add a comment |
up vote
1
down vote
up vote
1
down vote
If you need a 2d array filled with random ints, you can use a nested loop similar to what you used to genrate your rows above:
public static void main(String args) {
int matrix = new int[20][20];
for(int i = 0; i < matrix.length; i++){
for(int j = 0; j < matrix[i].length; j++){
matrix[i][j] = (int)(Math.random()*1000 + 1);
}
}
for(int row : matrix){
System.out.println(Arrays.toString(row));
}
}
If you need a 2d array filled with random ints, you can use a nested loop similar to what you used to genrate your rows above:
public static void main(String args) {
int matrix = new int[20][20];
for(int i = 0; i < matrix.length; i++){
for(int j = 0; j < matrix[i].length; j++){
matrix[i][j] = (int)(Math.random()*1000 + 1);
}
}
for(int row : matrix){
System.out.println(Arrays.toString(row));
}
}
answered Nov 9 at 16:39
Eritrean
3,2091814
3,2091814
add a comment |
add a comment |
up vote
0
down vote
Yea you definitely can, though it may be a bit more confusing.
You can initalize the 3d array with this:
// test is a 3d array
int test = {
{
{1, -2, 3},
{2, 3, 4}
},
{
{-4, -5, 6, 9},
{1},
{2, 3}
}
};
I like to think this in terms or 3d obects, like a regtangluar prism. Each row (height)on the prism hold 2 things Length and Width, or a x,y. in other worlds you have a 2d array, one value is the column, the other is the row, in an array making it 3d.
now what if you want to print out values of the 3d array?
simply do this :
for (int array2D: test) {
for (int array1D: array2D) {
for(int item: array1D) {
System.out.println(item);
}
}
}
add a comment |
up vote
0
down vote
Yea you definitely can, though it may be a bit more confusing.
You can initalize the 3d array with this:
// test is a 3d array
int test = {
{
{1, -2, 3},
{2, 3, 4}
},
{
{-4, -5, 6, 9},
{1},
{2, 3}
}
};
I like to think this in terms or 3d obects, like a regtangluar prism. Each row (height)on the prism hold 2 things Length and Width, or a x,y. in other worlds you have a 2d array, one value is the column, the other is the row, in an array making it 3d.
now what if you want to print out values of the 3d array?
simply do this :
for (int array2D: test) {
for (int array1D: array2D) {
for(int item: array1D) {
System.out.println(item);
}
}
}
add a comment |
up vote
0
down vote
up vote
0
down vote
Yea you definitely can, though it may be a bit more confusing.
You can initalize the 3d array with this:
// test is a 3d array
int test = {
{
{1, -2, 3},
{2, 3, 4}
},
{
{-4, -5, 6, 9},
{1},
{2, 3}
}
};
I like to think this in terms or 3d obects, like a regtangluar prism. Each row (height)on the prism hold 2 things Length and Width, or a x,y. in other worlds you have a 2d array, one value is the column, the other is the row, in an array making it 3d.
now what if you want to print out values of the 3d array?
simply do this :
for (int array2D: test) {
for (int array1D: array2D) {
for(int item: array1D) {
System.out.println(item);
}
}
}
Yea you definitely can, though it may be a bit more confusing.
You can initalize the 3d array with this:
// test is a 3d array
int test = {
{
{1, -2, 3},
{2, 3, 4}
},
{
{-4, -5, 6, 9},
{1},
{2, 3}
}
};
I like to think this in terms or 3d obects, like a regtangluar prism. Each row (height)on the prism hold 2 things Length and Width, or a x,y. in other worlds you have a 2d array, one value is the column, the other is the row, in an array making it 3d.
now what if you want to print out values of the 3d array?
simply do this :
for (int array2D: test) {
for (int array1D: array2D) {
for(int item: array1D) {
System.out.println(item);
}
}
}
answered Nov 9 at 16:08
joshau
748
748
add a comment |
add a comment |
up vote
0
down vote
Although it's convenient to think of a 2-dimensional array in terms of rows and columns, a 2-dimensional array is just an array of arrays.
For example,
int values1 = {1, 2 ,3};
int matrix1 = {values1, values1, values1};
matrix1[1][1] = 42;
System.out.println(matrix1[0][1]);
System.out.println(matrix1[1][1]);
System.out.println(matrix1[2][1]);
or
int values2 = {1, 2 ,3};
int matrix2 = new int[3][3];
matrix2[0] = values2;
matrix2[1] = values2;
matrix2[2] = values2;
matrix2[1][1] = 42;
System.out.println(matrix2[0][1]);
System.out.println(matrix2[1][1]);
System.out.println(matrix2[2][1]);
Note that in both cases a values array is used multiple times to initialize each row of the matrix. So any change to any matrix element is reflected in the other rows (since each row is actually the same array). There may be cases where this is useful. If the elements need to be independent then use something like this:
int values3 = {1, 2 ,3};
int matrix3 = new int[3][3];
System.arraycopy(values3, 0, matrix3[0], 0, values3.length);
System.arraycopy(values3, 0, matrix3[1], 0, values3.length);
System.arraycopy(values3, 0, matrix3[2], 0, values3.length);
matrix3[1][1] = 42;
System.out.println(matrix3[0][1]);
System.out.println(matrix3[1][1]);
System.out.println(matrix3[2][1]);
Each row of the matrix is initialized with a copy of the same value, but making changes to any element is independent of any other element (since it's a different array).
Also see this other question if the matrix needs to be initialized element by element.
add a comment |
up vote
0
down vote
Although it's convenient to think of a 2-dimensional array in terms of rows and columns, a 2-dimensional array is just an array of arrays.
For example,
int values1 = {1, 2 ,3};
int matrix1 = {values1, values1, values1};
matrix1[1][1] = 42;
System.out.println(matrix1[0][1]);
System.out.println(matrix1[1][1]);
System.out.println(matrix1[2][1]);
or
int values2 = {1, 2 ,3};
int matrix2 = new int[3][3];
matrix2[0] = values2;
matrix2[1] = values2;
matrix2[2] = values2;
matrix2[1][1] = 42;
System.out.println(matrix2[0][1]);
System.out.println(matrix2[1][1]);
System.out.println(matrix2[2][1]);
Note that in both cases a values array is used multiple times to initialize each row of the matrix. So any change to any matrix element is reflected in the other rows (since each row is actually the same array). There may be cases where this is useful. If the elements need to be independent then use something like this:
int values3 = {1, 2 ,3};
int matrix3 = new int[3][3];
System.arraycopy(values3, 0, matrix3[0], 0, values3.length);
System.arraycopy(values3, 0, matrix3[1], 0, values3.length);
System.arraycopy(values3, 0, matrix3[2], 0, values3.length);
matrix3[1][1] = 42;
System.out.println(matrix3[0][1]);
System.out.println(matrix3[1][1]);
System.out.println(matrix3[2][1]);
Each row of the matrix is initialized with a copy of the same value, but making changes to any element is independent of any other element (since it's a different array).
Also see this other question if the matrix needs to be initialized element by element.
add a comment |
up vote
0
down vote
up vote
0
down vote
Although it's convenient to think of a 2-dimensional array in terms of rows and columns, a 2-dimensional array is just an array of arrays.
For example,
int values1 = {1, 2 ,3};
int matrix1 = {values1, values1, values1};
matrix1[1][1] = 42;
System.out.println(matrix1[0][1]);
System.out.println(matrix1[1][1]);
System.out.println(matrix1[2][1]);
or
int values2 = {1, 2 ,3};
int matrix2 = new int[3][3];
matrix2[0] = values2;
matrix2[1] = values2;
matrix2[2] = values2;
matrix2[1][1] = 42;
System.out.println(matrix2[0][1]);
System.out.println(matrix2[1][1]);
System.out.println(matrix2[2][1]);
Note that in both cases a values array is used multiple times to initialize each row of the matrix. So any change to any matrix element is reflected in the other rows (since each row is actually the same array). There may be cases where this is useful. If the elements need to be independent then use something like this:
int values3 = {1, 2 ,3};
int matrix3 = new int[3][3];
System.arraycopy(values3, 0, matrix3[0], 0, values3.length);
System.arraycopy(values3, 0, matrix3[1], 0, values3.length);
System.arraycopy(values3, 0, matrix3[2], 0, values3.length);
matrix3[1][1] = 42;
System.out.println(matrix3[0][1]);
System.out.println(matrix3[1][1]);
System.out.println(matrix3[2][1]);
Each row of the matrix is initialized with a copy of the same value, but making changes to any element is independent of any other element (since it's a different array).
Also see this other question if the matrix needs to be initialized element by element.
Although it's convenient to think of a 2-dimensional array in terms of rows and columns, a 2-dimensional array is just an array of arrays.
For example,
int values1 = {1, 2 ,3};
int matrix1 = {values1, values1, values1};
matrix1[1][1] = 42;
System.out.println(matrix1[0][1]);
System.out.println(matrix1[1][1]);
System.out.println(matrix1[2][1]);
or
int values2 = {1, 2 ,3};
int matrix2 = new int[3][3];
matrix2[0] = values2;
matrix2[1] = values2;
matrix2[2] = values2;
matrix2[1][1] = 42;
System.out.println(matrix2[0][1]);
System.out.println(matrix2[1][1]);
System.out.println(matrix2[2][1]);
Note that in both cases a values array is used multiple times to initialize each row of the matrix. So any change to any matrix element is reflected in the other rows (since each row is actually the same array). There may be cases where this is useful. If the elements need to be independent then use something like this:
int values3 = {1, 2 ,3};
int matrix3 = new int[3][3];
System.arraycopy(values3, 0, matrix3[0], 0, values3.length);
System.arraycopy(values3, 0, matrix3[1], 0, values3.length);
System.arraycopy(values3, 0, matrix3[2], 0, values3.length);
matrix3[1][1] = 42;
System.out.println(matrix3[0][1]);
System.out.println(matrix3[1][1]);
System.out.println(matrix3[2][1]);
Each row of the matrix is initialized with a copy of the same value, but making changes to any element is independent of any other element (since it's a different array).
Also see this other question if the matrix needs to be initialized element by element.
answered Nov 9 at 16:35
Andrew S
1,4721510
1,4721510
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1
What is the randomArrayN in your first snippet?
– mettleap
Nov 9 at 16:04
4
How exactly should the matrix be filled from your rows and columns array? Considering you would have n rows and m columns you have n + m values, but the matrix size is n * m.
– Glains
Nov 9 at 16:06
1
If you try and add rows and columns at the same time to a 2d array, it would result in many conflicts ... so it depends on how you want to construct the multi-dimensional array as @Glains has pointed out
– mettleap
Nov 9 at 16:11
whoops, dont mind the randomArrayN, it was meant to be rows. I had changed the name of the array from that to rows. As for @Glains , the reality likely is that it is just more simple to create the values of rows and columns within the two-dimensional array rather than try to fill it with arrays already made, then?
– Benjamin Dare Edwards
Nov 9 at 16:32
As explained above, consider you have
rows = {1, 2, 3}
andcolumns = {3, 4, 6}
. If you gotmatrix = [rows.length][columns.length]
you have only 6 values, but the matrix has a size of 3 * 3 = 9. How do you want to calculate the values from your rows and column?– Glains
Nov 9 at 16:41