How do I detect duplicates subnodes with several nodes with XQuery
up vote
1
down vote
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How can I find duplicate subnodes with XQuery and/or XPath, my XML structure looks like this:
<register>
<operator referenceid="1">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="2">
<operationpart>
<type>Category_code</type>
<name>202020</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Development</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>2</name>
</operationpart>
</operator>
<operator referenceid="3">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="4">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
<operator referenceid="5">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
</register>
Two should get listed in a result as duplicates, that is 4 and 5, also 1 and 3.
XQuery/Xpath should also ignore the attribute referenceid which always must be unique in the XML-list.
xpath xquery
add a comment |
up vote
1
down vote
favorite
How can I find duplicate subnodes with XQuery and/or XPath, my XML structure looks like this:
<register>
<operator referenceid="1">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="2">
<operationpart>
<type>Category_code</type>
<name>202020</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Development</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>2</name>
</operationpart>
</operator>
<operator referenceid="3">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="4">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
<operator referenceid="5">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
</register>
Two should get listed in a result as duplicates, that is 4 and 5, also 1 and 3.
XQuery/Xpath should also ignore the attribute referenceid which always must be unique in the XML-list.
xpath xquery
it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
How can I find duplicate subnodes with XQuery and/or XPath, my XML structure looks like this:
<register>
<operator referenceid="1">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="2">
<operationpart>
<type>Category_code</type>
<name>202020</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Development</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>2</name>
</operationpart>
</operator>
<operator referenceid="3">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="4">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
<operator referenceid="5">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
</register>
Two should get listed in a result as duplicates, that is 4 and 5, also 1 and 3.
XQuery/Xpath should also ignore the attribute referenceid which always must be unique in the XML-list.
xpath xquery
How can I find duplicate subnodes with XQuery and/or XPath, my XML structure looks like this:
<register>
<operator referenceid="1">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="2">
<operationpart>
<type>Category_code</type>
<name>202020</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Development</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>2</name>
</operationpart>
</operator>
<operator referenceid="3">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
<operationpart>
<type>Big_code</type>
<name>1</name>
</operationpart>
</operator>
<operator referenceid="4">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
<operator referenceid="5">
<operationpart>
<type>Category_code</type>
<name>101010</name>
</operationpart>
<operationpart>
<type>Category_text</type>
<name>Accounting</name>
</operationpart>
</operator>
</register>
Two should get listed in a result as duplicates, that is 4 and 5, also 1 and 3.
XQuery/Xpath should also ignore the attribute referenceid which always must be unique in the XML-list.
xpath xquery
xpath xquery
asked Nov 9 at 15:42
Roxpace
61
61
it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48
add a comment |
it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48
it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Kinda hard to put this in a list; how about showing the duplicate nodes:
/register/*
[normalize-space(.) = preceding-sibling::*/normalize-space(.)
and
not(normalize-space(.) = following-sibling::*/normalize-space(.))
]
Demo, which returns the node with referenceid
3 and 5.
or the opposite, to return 1 and 4:
/register/*
[normalize-space(.) = following-sibling::*/normalize-space(.)
and
not(normalize-space(.) = preceding-sibling::*/normalize-space(.))
]
If needed, you can combine both with an |
operator.
It's up to you. Obviously, this case can be further simplified.
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
up vote
0
down vote
Kinda hard to put this in a list; how about showing the duplicate nodes:
/register/*
[normalize-space(.) = preceding-sibling::*/normalize-space(.)
and
not(normalize-space(.) = following-sibling::*/normalize-space(.))
]
Demo, which returns the node with referenceid
3 and 5.
or the opposite, to return 1 and 4:
/register/*
[normalize-space(.) = following-sibling::*/normalize-space(.)
and
not(normalize-space(.) = preceding-sibling::*/normalize-space(.))
]
If needed, you can combine both with an |
operator.
It's up to you. Obviously, this case can be further simplified.
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
add a comment |
up vote
0
down vote
Kinda hard to put this in a list; how about showing the duplicate nodes:
/register/*
[normalize-space(.) = preceding-sibling::*/normalize-space(.)
and
not(normalize-space(.) = following-sibling::*/normalize-space(.))
]
Demo, which returns the node with referenceid
3 and 5.
or the opposite, to return 1 and 4:
/register/*
[normalize-space(.) = following-sibling::*/normalize-space(.)
and
not(normalize-space(.) = preceding-sibling::*/normalize-space(.))
]
If needed, you can combine both with an |
operator.
It's up to you. Obviously, this case can be further simplified.
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
add a comment |
up vote
0
down vote
up vote
0
down vote
Kinda hard to put this in a list; how about showing the duplicate nodes:
/register/*
[normalize-space(.) = preceding-sibling::*/normalize-space(.)
and
not(normalize-space(.) = following-sibling::*/normalize-space(.))
]
Demo, which returns the node with referenceid
3 and 5.
or the opposite, to return 1 and 4:
/register/*
[normalize-space(.) = following-sibling::*/normalize-space(.)
and
not(normalize-space(.) = preceding-sibling::*/normalize-space(.))
]
If needed, you can combine both with an |
operator.
It's up to you. Obviously, this case can be further simplified.
Kinda hard to put this in a list; how about showing the duplicate nodes:
/register/*
[normalize-space(.) = preceding-sibling::*/normalize-space(.)
and
not(normalize-space(.) = following-sibling::*/normalize-space(.))
]
Demo, which returns the node with referenceid
3 and 5.
or the opposite, to return 1 and 4:
/register/*
[normalize-space(.) = following-sibling::*/normalize-space(.)
and
not(normalize-space(.) = preceding-sibling::*/normalize-space(.))
]
If needed, you can combine both with an |
operator.
It's up to you. Obviously, this case can be further simplified.
answered Nov 9 at 19:49
wp78de
9,77951738
9,77951738
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
add a comment |
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
Thanks a lot @wp78de, looks promising, is it possible to show all duplicates lines in the result? Like not only referenceid 3 and 5 but also which they duplicates like 1,3 and 4,5 so I get a complete list what duplicates? Also is it possible also to make this with XQuery?
– Roxpace
Nov 11 at 16:44
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
I also tried to add more duplicates with same values and this only shows the last duplicate, little tough to detect all duplicates if I always only see the last duplicates and not everyone
– Roxpace
Nov 11 at 16:57
add a comment |
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it is not quite clear what counts as a duplicate subnode from your question. Could you add a sample of the output that you wish to generate. You can probably remove elements with referenceid 4 and 5 from your input sample, to make things more readable.
– duncdrum
Nov 9 at 15:58
Thanks for the comment @duncdrum, the example should be clear, but I can result I wanna get produced after looking for duplicates. referenceid 4, referenceid 5 referenceid 1, referenceid 3 I wanna detect a combination of elements which are duplicates, wanna compare in the level <operator> and detect if other <operator> content are the same except for the attribute which always are unique.
– Roxpace
Nov 9 at 16:42
I do not wanna remove, I wanna see what is duplicates.
– Roxpace
Nov 9 at 16:48