Changing a column value in pandas dataframe excluding the tail in group by












2














Let's take an example of a python dataframe.



ID Age Bp



1 22 1



1 22 1



1 22 0



1 22 1



2 21 0



2 21 1



2 21 0



In the above code, the last n series for column BP (lets consider n to be 2) with group by ID should be excluded and the rest of the BP should be changed to 0. I have tried it with tail but it does not work.



It should look like this.



ID Age BP



1 22 0



1 22 0



1 22 0



1 22 1



2 21 0



2 21 1



2 21 0










share|improve this question



























    2














    Let's take an example of a python dataframe.



    ID Age Bp



    1 22 1



    1 22 1



    1 22 0



    1 22 1



    2 21 0



    2 21 1



    2 21 0



    In the above code, the last n series for column BP (lets consider n to be 2) with group by ID should be excluded and the rest of the BP should be changed to 0. I have tried it with tail but it does not work.



    It should look like this.



    ID Age BP



    1 22 0



    1 22 0



    1 22 0



    1 22 1



    2 21 0



    2 21 1



    2 21 0










    share|improve this question

























      2












      2








      2







      Let's take an example of a python dataframe.



      ID Age Bp



      1 22 1



      1 22 1



      1 22 0



      1 22 1



      2 21 0



      2 21 1



      2 21 0



      In the above code, the last n series for column BP (lets consider n to be 2) with group by ID should be excluded and the rest of the BP should be changed to 0. I have tried it with tail but it does not work.



      It should look like this.



      ID Age BP



      1 22 0



      1 22 0



      1 22 0



      1 22 1



      2 21 0



      2 21 1



      2 21 0










      share|improve this question













      Let's take an example of a python dataframe.



      ID Age Bp



      1 22 1



      1 22 1



      1 22 0



      1 22 1



      2 21 0



      2 21 1



      2 21 0



      In the above code, the last n series for column BP (lets consider n to be 2) with group by ID should be excluded and the rest of the BP should be changed to 0. I have tried it with tail but it does not work.



      It should look like this.



      ID Age BP



      1 22 0



      1 22 0



      1 22 0



      1 22 1



      2 21 0



      2 21 1



      2 21 0







      python pandas






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 at 17:57









      user123

      185




      185
























          1 Answer
          1






          active

          oldest

          votes


















          2














          Use cumcount with ascending=False for counter from back per groups and assign 0 with numpy.where:



          n = 2
          mask = df.groupby('ID').cumcount(ascending=False) < n
          df['Bp'] = np.where(mask, df['Bp'], 0)


          Alternatives:



          df.loc[~mask, 'Bp'] = 0
          df['Bp'] = df['Bp'].where(mask, 0)




          print (df)
          ID Age Bp
          0 1 22 0
          1 1 22 0
          2 1 22 0
          3 1 22 1
          4 2 21 0
          5 2 21 1
          6 2 21 0


          Details:



          print (df.groupby('ID').cumcount(ascending=False))
          0 3
          1 2
          2 1
          3 0
          4 2
          5 1
          6 0
          dtype: int64

          print (mask)
          0 False
          1 False
          2 True
          3 True
          4 False
          5 True
          6 True
          dtype: bool





          share|improve this answer





















          • Thanks for the help it worked
            – user123
            Nov 10 at 19:30










          • @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
            – jezrael
            Nov 10 at 19:30











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          Use cumcount with ascending=False for counter from back per groups and assign 0 with numpy.where:



          n = 2
          mask = df.groupby('ID').cumcount(ascending=False) < n
          df['Bp'] = np.where(mask, df['Bp'], 0)


          Alternatives:



          df.loc[~mask, 'Bp'] = 0
          df['Bp'] = df['Bp'].where(mask, 0)




          print (df)
          ID Age Bp
          0 1 22 0
          1 1 22 0
          2 1 22 0
          3 1 22 1
          4 2 21 0
          5 2 21 1
          6 2 21 0


          Details:



          print (df.groupby('ID').cumcount(ascending=False))
          0 3
          1 2
          2 1
          3 0
          4 2
          5 1
          6 0
          dtype: int64

          print (mask)
          0 False
          1 False
          2 True
          3 True
          4 False
          5 True
          6 True
          dtype: bool





          share|improve this answer





















          • Thanks for the help it worked
            – user123
            Nov 10 at 19:30










          • @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
            – jezrael
            Nov 10 at 19:30
















          2














          Use cumcount with ascending=False for counter from back per groups and assign 0 with numpy.where:



          n = 2
          mask = df.groupby('ID').cumcount(ascending=False) < n
          df['Bp'] = np.where(mask, df['Bp'], 0)


          Alternatives:



          df.loc[~mask, 'Bp'] = 0
          df['Bp'] = df['Bp'].where(mask, 0)




          print (df)
          ID Age Bp
          0 1 22 0
          1 1 22 0
          2 1 22 0
          3 1 22 1
          4 2 21 0
          5 2 21 1
          6 2 21 0


          Details:



          print (df.groupby('ID').cumcount(ascending=False))
          0 3
          1 2
          2 1
          3 0
          4 2
          5 1
          6 0
          dtype: int64

          print (mask)
          0 False
          1 False
          2 True
          3 True
          4 False
          5 True
          6 True
          dtype: bool





          share|improve this answer





















          • Thanks for the help it worked
            – user123
            Nov 10 at 19:30










          • @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
            – jezrael
            Nov 10 at 19:30














          2












          2








          2






          Use cumcount with ascending=False for counter from back per groups and assign 0 with numpy.where:



          n = 2
          mask = df.groupby('ID').cumcount(ascending=False) < n
          df['Bp'] = np.where(mask, df['Bp'], 0)


          Alternatives:



          df.loc[~mask, 'Bp'] = 0
          df['Bp'] = df['Bp'].where(mask, 0)




          print (df)
          ID Age Bp
          0 1 22 0
          1 1 22 0
          2 1 22 0
          3 1 22 1
          4 2 21 0
          5 2 21 1
          6 2 21 0


          Details:



          print (df.groupby('ID').cumcount(ascending=False))
          0 3
          1 2
          2 1
          3 0
          4 2
          5 1
          6 0
          dtype: int64

          print (mask)
          0 False
          1 False
          2 True
          3 True
          4 False
          5 True
          6 True
          dtype: bool





          share|improve this answer












          Use cumcount with ascending=False for counter from back per groups and assign 0 with numpy.where:



          n = 2
          mask = df.groupby('ID').cumcount(ascending=False) < n
          df['Bp'] = np.where(mask, df['Bp'], 0)


          Alternatives:



          df.loc[~mask, 'Bp'] = 0
          df['Bp'] = df['Bp'].where(mask, 0)




          print (df)
          ID Age Bp
          0 1 22 0
          1 1 22 0
          2 1 22 0
          3 1 22 1
          4 2 21 0
          5 2 21 1
          6 2 21 0


          Details:



          print (df.groupby('ID').cumcount(ascending=False))
          0 3
          1 2
          2 1
          3 0
          4 2
          5 1
          6 0
          dtype: int64

          print (mask)
          0 False
          1 False
          2 True
          3 True
          4 False
          5 True
          6 True
          dtype: bool






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 10 at 18:36









          jezrael

          318k22257336




          318k22257336












          • Thanks for the help it worked
            – user123
            Nov 10 at 19:30










          • @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
            – jezrael
            Nov 10 at 19:30


















          • Thanks for the help it worked
            – user123
            Nov 10 at 19:30










          • @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
            – jezrael
            Nov 10 at 19:30
















          Thanks for the help it worked
          – user123
          Nov 10 at 19:30




          Thanks for the help it worked
          – user123
          Nov 10 at 19:30












          @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
          – jezrael
          Nov 10 at 19:30




          @user123 - You are welcome! If my answer was helpful, don't forget accept it. To mark an answer as accepted, click on the check mark beside the answer to toggle it from hollow to green (see screenshot). Thank you.
          – jezrael
          Nov 10 at 19:30


















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