how to detect logical and string index in sub-list and delete it












1














I have a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]


and I want as output a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]


I just want to delete or remove a any list. it have member of string or logical.
how i can do it.






python python-3.x algorithm list types







share|improve this question
























  • So you want to remove any lists that have False in them?
    – Ayxan
    Nov 10 at 18:16










  • yeap, I want to remove any type is not int or float from list.
    – lyca
    Nov 10 at 18:18


















1














I have a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]


and I want as output a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]


I just want to delete or remove a any list. it have member of string or logical.
how i can do it.






python python-3.x algorithm list types







share|improve this question
























  • So you want to remove any lists that have False in them?
    – Ayxan
    Nov 10 at 18:16










  • yeap, I want to remove any type is not int or float from list.
    – lyca
    Nov 10 at 18:18
















1












1








1







I have a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]


and I want as output a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]


I just want to delete or remove a any list. it have member of string or logical.
how i can do it.






python python-3.x algorithm list types







share|improve this question















I have a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]


and I want as output a list like this:



A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]


I just want to delete or remove a any list. it have member of string or logical.
how i can do it.






python python-3.x algorithm list types




python python-3.x algorithm list types






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 18:20









Daniel Mesejo

11.5k1924




11.5k1924










asked Nov 10 at 18:12









lyca

215




215












  • So you want to remove any lists that have False in them?
    – Ayxan
    Nov 10 at 18:16










  • yeap, I want to remove any type is not int or float from list.
    – lyca
    Nov 10 at 18:18




















  • So you want to remove any lists that have False in them?
    – Ayxan
    Nov 10 at 18:16










  • yeap, I want to remove any type is not int or float from list.
    – lyca
    Nov 10 at 18:18


















So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16




So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16












yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18






yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18














1 Answer
1






active

oldest

votes


















5














We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:



[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]


this then yields:



>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]





share|improve this answer





















  • what is meaning of e ?
    – lyca
    Nov 10 at 18:21










  • @lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
    – Willem Van Onsem
    Nov 10 at 18:22











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:



[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]


this then yields:



>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]





share|improve this answer





















  • what is meaning of e ?
    – lyca
    Nov 10 at 18:21










  • @lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
    – Willem Van Onsem
    Nov 10 at 18:22
















5














We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:



[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]


this then yields:



>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]





share|improve this answer





















  • what is meaning of e ?
    – lyca
    Nov 10 at 18:21










  • @lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
    – Willem Van Onsem
    Nov 10 at 18:22














5












5








5






We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:



[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]


this then yields:



>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]





share|improve this answer












We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:



[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]


this then yields:



>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 10 at 18:16









Willem Van Onsem

143k16135227




143k16135227












  • what is meaning of e ?
    – lyca
    Nov 10 at 18:21










  • @lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
    – Willem Van Onsem
    Nov 10 at 18:22


















  • what is meaning of e ?
    – lyca
    Nov 10 at 18:21










  • @lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
    – Willem Van Onsem
    Nov 10 at 18:22
















what is meaning of e ?
– lyca
Nov 10 at 18:21




what is meaning of e ?
– lyca
Nov 10 at 18:21












@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22




@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22


















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