Am I interpreting this list comprehension correctly in python?
I am still fairly new to python and still have some fumbles when reading list comprehensions. I tried translating two list comprehensions I saw in a tutorial into its elongated form. Did I translate correctly?
list comprehension 1
mytokens = [ word.lemma_.lower().strip() if word.lemma_ != "-PRON-" else word.lower_ for word in mytokens ]
translation 1
for word in mytokens:
if word.lemma_ != "-PRON-":
word.lemma_.lower().strip()
else:
word.lower_
list comprehension 2
mytokens = [ word for word in mytokens if word not in stopwords and word not in punctuations ]
translation 2
for word in mytokens:
if word not in stopwords and not in punctuations:
yield word
for translation 2, I dont think "yield word" would be correct since its not a definition. I am guessing list comprehension 2 does the if statement and places the word back into the list mytokens so maybe it should be a .append?
python list-comprehension
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
add a comment |
I am still fairly new to python and still have some fumbles when reading list comprehensions. I tried translating two list comprehensions I saw in a tutorial into its elongated form. Did I translate correctly?
list comprehension 1
mytokens = [ word.lemma_.lower().strip() if word.lemma_ != "-PRON-" else word.lower_ for word in mytokens ]
translation 1
for word in mytokens:
if word.lemma_ != "-PRON-":
word.lemma_.lower().strip()
else:
word.lower_
list comprehension 2
mytokens = [ word for word in mytokens if word not in stopwords and word not in punctuations ]
translation 2
for word in mytokens:
if word not in stopwords and not in punctuations:
yield word
for translation 2, I dont think "yield word" would be correct since its not a definition. I am guessing list comprehension 2 does the if statement and places the word back into the list mytokens so maybe it should be a .append?
python list-comprehension
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
1
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56
add a comment |
I am still fairly new to python and still have some fumbles when reading list comprehensions. I tried translating two list comprehensions I saw in a tutorial into its elongated form. Did I translate correctly?
list comprehension 1
mytokens = [ word.lemma_.lower().strip() if word.lemma_ != "-PRON-" else word.lower_ for word in mytokens ]
translation 1
for word in mytokens:
if word.lemma_ != "-PRON-":
word.lemma_.lower().strip()
else:
word.lower_
list comprehension 2
mytokens = [ word for word in mytokens if word not in stopwords and word not in punctuations ]
translation 2
for word in mytokens:
if word not in stopwords and not in punctuations:
yield word
for translation 2, I dont think "yield word" would be correct since its not a definition. I am guessing list comprehension 2 does the if statement and places the word back into the list mytokens so maybe it should be a .append?
python list-comprehension
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
I am still fairly new to python and still have some fumbles when reading list comprehensions. I tried translating two list comprehensions I saw in a tutorial into its elongated form. Did I translate correctly?
list comprehension 1
mytokens = [ word.lemma_.lower().strip() if word.lemma_ != "-PRON-" else word.lower_ for word in mytokens ]
translation 1
for word in mytokens:
if word.lemma_ != "-PRON-":
word.lemma_.lower().strip()
else:
word.lower_
list comprehension 2
mytokens = [ word for word in mytokens if word not in stopwords and word not in punctuations ]
translation 2
for word in mytokens:
if word not in stopwords and not in punctuations:
yield word
for translation 2, I dont think "yield word" would be correct since its not a definition. I am guessing list comprehension 2 does the if statement and places the word back into the list mytokens so maybe it should be a .append?
python list-comprehension
python list-comprehension
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
edited Nov 14 '18 at 20:48
PaperRockBazooka
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
asked Nov 14 '18 at 20:46
PaperRockBazookaPaperRockBazooka
476
476
1
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56
add a comment |
1
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56
1
1
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56
add a comment |
2 Answers
2
active
oldest
votes
I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?
So for the first one you could use
my_list =
for word in mytokens:
if word.lemma_ != "-PRON-":
my_list.append(word.lemma_.lower().strip())
else:
my_list.append(word.lower_)
By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.
Also there is a small mistake in the second translation. It should be:
for word in mytokens:
if word not in stopwords and word not in punctuations:
yield word
You could also modify this second translation to add all your words to a list.
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
add a comment |
Let's simplify this:
coll = ["Gerry", "Mary", "Sue"]
comprehended = [ word.lower() for word in coll]
def comprehender(coll):
coll_out =
for word in coll:
coll_out.append(word.lower())
return coll_out
If you run this, you can be assured that the two are equivalent by using assert or just returning comprehended == comprehender(coll)
This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?
So for the first one you could use
my_list =
for word in mytokens:
if word.lemma_ != "-PRON-":
my_list.append(word.lemma_.lower().strip())
else:
my_list.append(word.lower_)
By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.
Also there is a small mistake in the second translation. It should be:
for word in mytokens:
if word not in stopwords and word not in punctuations:
yield word
You could also modify this second translation to add all your words to a list.
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
add a comment |
I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?
So for the first one you could use
my_list =
for word in mytokens:
if word.lemma_ != "-PRON-":
my_list.append(word.lemma_.lower().strip())
else:
my_list.append(word.lower_)
By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.
Also there is a small mistake in the second translation. It should be:
for word in mytokens:
if word not in stopwords and word not in punctuations:
yield word
You could also modify this second translation to add all your words to a list.
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
add a comment |
I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?
So for the first one you could use
my_list =
for word in mytokens:
if word.lemma_ != "-PRON-":
my_list.append(word.lemma_.lower().strip())
else:
my_list.append(word.lower_)
By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.
Also there is a small mistake in the second translation. It should be:
for word in mytokens:
if word not in stopwords and word not in punctuations:
yield word
You could also modify this second translation to add all your words to a list.
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?
So for the first one you could use
my_list =
for word in mytokens:
if word.lemma_ != "-PRON-":
my_list.append(word.lemma_.lower().strip())
else:
my_list.append(word.lower_)
By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.
Also there is a small mistake in the second translation. It should be:
for word in mytokens:
if word not in stopwords and word not in punctuations:
yield word
You could also modify this second translation to add all your words to a list.
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
edited Nov 14 '18 at 21:50
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
answered Nov 14 '18 at 20:55
James FultonJames Fulton
1825
1825
add a comment |
add a comment |
Let's simplify this:
coll = ["Gerry", "Mary", "Sue"]
comprehended = [ word.lower() for word in coll]
def comprehender(coll):
coll_out =
for word in coll:
coll_out.append(word.lower())
return coll_out
If you run this, you can be assured that the two are equivalent by using assert or just returning comprehended == comprehender(coll)
This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
add a comment |
Let's simplify this:
coll = ["Gerry", "Mary", "Sue"]
comprehended = [ word.lower() for word in coll]
def comprehender(coll):
coll_out =
for word in coll:
coll_out.append(word.lower())
return coll_out
If you run this, you can be assured that the two are equivalent by using assert or just returning comprehended == comprehender(coll)
This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
add a comment |
Let's simplify this:
coll = ["Gerry", "Mary", "Sue"]
comprehended = [ word.lower() for word in coll]
def comprehender(coll):
coll_out =
for word in coll:
coll_out.append(word.lower())
return coll_out
If you run this, you can be assured that the two are equivalent by using assert or just returning comprehended == comprehender(coll)
This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
Let's simplify this:
coll = ["Gerry", "Mary", "Sue"]
comprehended = [ word.lower() for word in coll]
def comprehender(coll):
coll_out =
for word in coll:
coll_out.append(word.lower())
return coll_out
If you run this, you can be assured that the two are equivalent by using assert or just returning comprehended == comprehender(coll)
This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
answered Nov 14 '18 at 20:57
Charles LandauCharles Landau
2,2281216
2,2281216
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
add a comment |
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
oh interesting! Thank you i will give this a shot
– PaperRockBazooka
Nov 14 '18 at 21:45
add a comment |
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1
Do your translations do the same thing? That should provide your answer.
– jonrsharpe
Nov 14 '18 at 20:48
I am not sure if they do the same thing hence the question!
– PaperRockBazooka
Nov 14 '18 at 20:51
So did you test them? What you've posted here isn't valid syntax on its own, and neither actually creates a list.
– jonrsharpe
Nov 14 '18 at 20:51
Oh i thought this would be simple for an experienced coder-- like reading a equation from a subject matter someone is familiar in. I didnt realize you need the variables in context to be able to figure out list comps. Sorry! p.s. if this isnt a list comprehension what is it?
– PaperRockBazooka
Nov 14 '18 at 20:56