[Bokeh]Getting `TypeError: Object of type Polygon is not JSON serializable`












0















First time posting in stackoverflow. Hope you guys are doing well.
Recently, I am trying to create a filterable Bokeh graph to graph a US map base on the filter an user select. However, when I try to fit a geometry to ColumnDataSource. It is giving me an error: TypeError: Object of type Polygon is not JSON serializable when I run show(figure)



The code below shows how I want to update geometry to ColumnDataSource and I get an error



# <------- This is where the graph starts------->

# reset the graph
reset_output()

# import data
data = gpd.read_file("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", encoding="utf-8")
data1 = data[~data.STUSPS.isin(['AK','AS', 'GU', 'HI', 'PR','MP', 'VI'])]
data2 = data[data.STUSPS.isin(['TX', 'UT'])]

# get a list of unique value
unique_state = sorted(list(data2.NAME.unique()))
select = Select(title="State", options=unique_state)

# get data into ColumnDataSource
source=ColumnDataSource(ColumnDataSource.from_df(data2.loc[:]))

# crate filtered dataframe
filteredSource = ColumnDataSource(data=dict(STUSPS=,NAME=,ALAND=))

columns = [TableColumn(field="NAME",title="NAME",sortable=True),
TableColumn(field="STUSPS",title="STUSPS",sortable=True),
TableColumn(field="ALAND",title="ALAND",sortable=True),
TableColumn(field="geometry",title="geometry",sortable=True)]

data_table=DataTable(source=filteredSource,columns=columns, width=800 )

# <---- Call back starts ---->
callback = CustomJS(args=dict(source=source,
filteredSource=filteredSource,
data_table=data_table), code="""
var data = source.data;
var f = cb_obj.value;
var d2 = filteredSource.data;
d2['STUSPS']=
d2['NAME']=
d2['ALAND']=
d2['geometry']=


for(i = 0; i < data['NAME'].length;i++){

if(data['NAME'][i]==f){

d2['STUSPS'].push(data['STUSPS'][i])
d2['NAME'].push(data['NAME'][i])
d2['ALAND'].push(data['ALAND'][i])
d2['geometry'].push(data['geometry'][i])
}

}

filteredSource.change.emit()
// trigger change on datatable
data_table.change.emit()

""")

select.js_on_change('value',callback)

layout = column(widgetbox(select, data_table))

# output_file("filter.html", title="filter example")

show(layout)


Afterwards, I saw an example directly fitting shape file to dictionary or dataframe which may solve the problem. Here is the link:
Bokeh Mapping Counties
However, when I using the code to graph it. it is giving me



ValueError: Out of range float values are not JSON compliant


This is the code I run:



import shapefile
import itertools

shp = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", "rb")
dbf = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.dbf", "rb")
sf = shapefile.Reader(shp=shp, dbf=dbf)

lats =
lons =
ct_name =
st_id =
ct_state_name =
for shprec in sf.shapeRecords():
st_id.append(int(shprec.record[0]))
ct_name.append(shprec.record[5])
ct_state_name.append(shprec.record[4])
lat, lon = map(list, zip(*shprec.shape.points))
indices = shprec.shape.parts.tolist()
lat = [lat[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lon = [lon[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lat = list(itertools.chain.from_iterable(lat))
lon = list(itertools.chain.from_iterable(lon))
lats.append(lat)
lons.append(lon)

map_data = pd.DataFrame({'x': lats, 'y': lons, 'state': st_id, 'county_name': ct_name, 'ct_state_name': ct_state_name})
map_data_m = map_data[map_data.ct_state_name.isin(['NJ'])]

source = ColumnDataSource(map_data_m)

TOOLS="pan,wheel_zoom,box_zoom,reset,hover,save"

p = figure(title="Title", tools=TOOLS,
x_axis_location=None, y_axis_location=None)
p.grid.grid_line_color = None

p.patches('x', 'y', source=source,
fill_color='color', fill_alpha=0.7,
line_color="white", line_width=0.5)

show(p)


anyone who is able to help me to resolve either of the question? I have been stuck for few days. Thanks a lot!










share|improve this question























  • Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

    – user2908623
    Nov 14 '18 at 21:29











  • hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

    – David Pu
    Nov 14 '18 at 22:01


















0















First time posting in stackoverflow. Hope you guys are doing well.
Recently, I am trying to create a filterable Bokeh graph to graph a US map base on the filter an user select. However, when I try to fit a geometry to ColumnDataSource. It is giving me an error: TypeError: Object of type Polygon is not JSON serializable when I run show(figure)



The code below shows how I want to update geometry to ColumnDataSource and I get an error



# <------- This is where the graph starts------->

# reset the graph
reset_output()

# import data
data = gpd.read_file("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", encoding="utf-8")
data1 = data[~data.STUSPS.isin(['AK','AS', 'GU', 'HI', 'PR','MP', 'VI'])]
data2 = data[data.STUSPS.isin(['TX', 'UT'])]

# get a list of unique value
unique_state = sorted(list(data2.NAME.unique()))
select = Select(title="State", options=unique_state)

# get data into ColumnDataSource
source=ColumnDataSource(ColumnDataSource.from_df(data2.loc[:]))

# crate filtered dataframe
filteredSource = ColumnDataSource(data=dict(STUSPS=,NAME=,ALAND=))

columns = [TableColumn(field="NAME",title="NAME",sortable=True),
TableColumn(field="STUSPS",title="STUSPS",sortable=True),
TableColumn(field="ALAND",title="ALAND",sortable=True),
TableColumn(field="geometry",title="geometry",sortable=True)]

data_table=DataTable(source=filteredSource,columns=columns, width=800 )

# <---- Call back starts ---->
callback = CustomJS(args=dict(source=source,
filteredSource=filteredSource,
data_table=data_table), code="""
var data = source.data;
var f = cb_obj.value;
var d2 = filteredSource.data;
d2['STUSPS']=
d2['NAME']=
d2['ALAND']=
d2['geometry']=


for(i = 0; i < data['NAME'].length;i++){

if(data['NAME'][i]==f){

d2['STUSPS'].push(data['STUSPS'][i])
d2['NAME'].push(data['NAME'][i])
d2['ALAND'].push(data['ALAND'][i])
d2['geometry'].push(data['geometry'][i])
}

}

filteredSource.change.emit()
// trigger change on datatable
data_table.change.emit()

""")

select.js_on_change('value',callback)

layout = column(widgetbox(select, data_table))

# output_file("filter.html", title="filter example")

show(layout)


Afterwards, I saw an example directly fitting shape file to dictionary or dataframe which may solve the problem. Here is the link:
Bokeh Mapping Counties
However, when I using the code to graph it. it is giving me



ValueError: Out of range float values are not JSON compliant


This is the code I run:



import shapefile
import itertools

shp = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", "rb")
dbf = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.dbf", "rb")
sf = shapefile.Reader(shp=shp, dbf=dbf)

lats =
lons =
ct_name =
st_id =
ct_state_name =
for shprec in sf.shapeRecords():
st_id.append(int(shprec.record[0]))
ct_name.append(shprec.record[5])
ct_state_name.append(shprec.record[4])
lat, lon = map(list, zip(*shprec.shape.points))
indices = shprec.shape.parts.tolist()
lat = [lat[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lon = [lon[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lat = list(itertools.chain.from_iterable(lat))
lon = list(itertools.chain.from_iterable(lon))
lats.append(lat)
lons.append(lon)

map_data = pd.DataFrame({'x': lats, 'y': lons, 'state': st_id, 'county_name': ct_name, 'ct_state_name': ct_state_name})
map_data_m = map_data[map_data.ct_state_name.isin(['NJ'])]

source = ColumnDataSource(map_data_m)

TOOLS="pan,wheel_zoom,box_zoom,reset,hover,save"

p = figure(title="Title", tools=TOOLS,
x_axis_location=None, y_axis_location=None)
p.grid.grid_line_color = None

p.patches('x', 'y', source=source,
fill_color='color', fill_alpha=0.7,
line_color="white", line_width=0.5)

show(p)


anyone who is able to help me to resolve either of the question? I have been stuck for few days. Thanks a lot!










share|improve this question























  • Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

    – user2908623
    Nov 14 '18 at 21:29











  • hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

    – David Pu
    Nov 14 '18 at 22:01
















0












0








0








First time posting in stackoverflow. Hope you guys are doing well.
Recently, I am trying to create a filterable Bokeh graph to graph a US map base on the filter an user select. However, when I try to fit a geometry to ColumnDataSource. It is giving me an error: TypeError: Object of type Polygon is not JSON serializable when I run show(figure)



The code below shows how I want to update geometry to ColumnDataSource and I get an error



# <------- This is where the graph starts------->

# reset the graph
reset_output()

# import data
data = gpd.read_file("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", encoding="utf-8")
data1 = data[~data.STUSPS.isin(['AK','AS', 'GU', 'HI', 'PR','MP', 'VI'])]
data2 = data[data.STUSPS.isin(['TX', 'UT'])]

# get a list of unique value
unique_state = sorted(list(data2.NAME.unique()))
select = Select(title="State", options=unique_state)

# get data into ColumnDataSource
source=ColumnDataSource(ColumnDataSource.from_df(data2.loc[:]))

# crate filtered dataframe
filteredSource = ColumnDataSource(data=dict(STUSPS=,NAME=,ALAND=))

columns = [TableColumn(field="NAME",title="NAME",sortable=True),
TableColumn(field="STUSPS",title="STUSPS",sortable=True),
TableColumn(field="ALAND",title="ALAND",sortable=True),
TableColumn(field="geometry",title="geometry",sortable=True)]

data_table=DataTable(source=filteredSource,columns=columns, width=800 )

# <---- Call back starts ---->
callback = CustomJS(args=dict(source=source,
filteredSource=filteredSource,
data_table=data_table), code="""
var data = source.data;
var f = cb_obj.value;
var d2 = filteredSource.data;
d2['STUSPS']=
d2['NAME']=
d2['ALAND']=
d2['geometry']=


for(i = 0; i < data['NAME'].length;i++){

if(data['NAME'][i]==f){

d2['STUSPS'].push(data['STUSPS'][i])
d2['NAME'].push(data['NAME'][i])
d2['ALAND'].push(data['ALAND'][i])
d2['geometry'].push(data['geometry'][i])
}

}

filteredSource.change.emit()
// trigger change on datatable
data_table.change.emit()

""")

select.js_on_change('value',callback)

layout = column(widgetbox(select, data_table))

# output_file("filter.html", title="filter example")

show(layout)


Afterwards, I saw an example directly fitting shape file to dictionary or dataframe which may solve the problem. Here is the link:
Bokeh Mapping Counties
However, when I using the code to graph it. it is giving me



ValueError: Out of range float values are not JSON compliant


This is the code I run:



import shapefile
import itertools

shp = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", "rb")
dbf = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.dbf", "rb")
sf = shapefile.Reader(shp=shp, dbf=dbf)

lats =
lons =
ct_name =
st_id =
ct_state_name =
for shprec in sf.shapeRecords():
st_id.append(int(shprec.record[0]))
ct_name.append(shprec.record[5])
ct_state_name.append(shprec.record[4])
lat, lon = map(list, zip(*shprec.shape.points))
indices = shprec.shape.parts.tolist()
lat = [lat[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lon = [lon[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lat = list(itertools.chain.from_iterable(lat))
lon = list(itertools.chain.from_iterable(lon))
lats.append(lat)
lons.append(lon)

map_data = pd.DataFrame({'x': lats, 'y': lons, 'state': st_id, 'county_name': ct_name, 'ct_state_name': ct_state_name})
map_data_m = map_data[map_data.ct_state_name.isin(['NJ'])]

source = ColumnDataSource(map_data_m)

TOOLS="pan,wheel_zoom,box_zoom,reset,hover,save"

p = figure(title="Title", tools=TOOLS,
x_axis_location=None, y_axis_location=None)
p.grid.grid_line_color = None

p.patches('x', 'y', source=source,
fill_color='color', fill_alpha=0.7,
line_color="white", line_width=0.5)

show(p)


anyone who is able to help me to resolve either of the question? I have been stuck for few days. Thanks a lot!










share|improve this question














First time posting in stackoverflow. Hope you guys are doing well.
Recently, I am trying to create a filterable Bokeh graph to graph a US map base on the filter an user select. However, when I try to fit a geometry to ColumnDataSource. It is giving me an error: TypeError: Object of type Polygon is not JSON serializable when I run show(figure)



The code below shows how I want to update geometry to ColumnDataSource and I get an error



# <------- This is where the graph starts------->

# reset the graph
reset_output()

# import data
data = gpd.read_file("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", encoding="utf-8")
data1 = data[~data.STUSPS.isin(['AK','AS', 'GU', 'HI', 'PR','MP', 'VI'])]
data2 = data[data.STUSPS.isin(['TX', 'UT'])]

# get a list of unique value
unique_state = sorted(list(data2.NAME.unique()))
select = Select(title="State", options=unique_state)

# get data into ColumnDataSource
source=ColumnDataSource(ColumnDataSource.from_df(data2.loc[:]))

# crate filtered dataframe
filteredSource = ColumnDataSource(data=dict(STUSPS=,NAME=,ALAND=))

columns = [TableColumn(field="NAME",title="NAME",sortable=True),
TableColumn(field="STUSPS",title="STUSPS",sortable=True),
TableColumn(field="ALAND",title="ALAND",sortable=True),
TableColumn(field="geometry",title="geometry",sortable=True)]

data_table=DataTable(source=filteredSource,columns=columns, width=800 )

# <---- Call back starts ---->
callback = CustomJS(args=dict(source=source,
filteredSource=filteredSource,
data_table=data_table), code="""
var data = source.data;
var f = cb_obj.value;
var d2 = filteredSource.data;
d2['STUSPS']=
d2['NAME']=
d2['ALAND']=
d2['geometry']=


for(i = 0; i < data['NAME'].length;i++){

if(data['NAME'][i]==f){

d2['STUSPS'].push(data['STUSPS'][i])
d2['NAME'].push(data['NAME'][i])
d2['ALAND'].push(data['ALAND'][i])
d2['geometry'].push(data['geometry'][i])
}

}

filteredSource.change.emit()
// trigger change on datatable
data_table.change.emit()

""")

select.js_on_change('value',callback)

layout = column(widgetbox(select, data_table))

# output_file("filter.html", title="filter example")

show(layout)


Afterwards, I saw an example directly fitting shape file to dictionary or dataframe which may solve the problem. Here is the link:
Bokeh Mapping Counties
However, when I using the code to graph it. it is giving me



ValueError: Out of range float values are not JSON compliant


This is the code I run:



import shapefile
import itertools

shp = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.shp", "rb")
dbf = open("/Users/xxxx/Desktop/cb_2015_us_state_500k/cb_2015_us_state_500k.dbf", "rb")
sf = shapefile.Reader(shp=shp, dbf=dbf)

lats =
lons =
ct_name =
st_id =
ct_state_name =
for shprec in sf.shapeRecords():
st_id.append(int(shprec.record[0]))
ct_name.append(shprec.record[5])
ct_state_name.append(shprec.record[4])
lat, lon = map(list, zip(*shprec.shape.points))
indices = shprec.shape.parts.tolist()
lat = [lat[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lon = [lon[i:j] + [float('NaN')] for i, j in zip(indices, indices[1:]+[None])]
lat = list(itertools.chain.from_iterable(lat))
lon = list(itertools.chain.from_iterable(lon))
lats.append(lat)
lons.append(lon)

map_data = pd.DataFrame({'x': lats, 'y': lons, 'state': st_id, 'county_name': ct_name, 'ct_state_name': ct_state_name})
map_data_m = map_data[map_data.ct_state_name.isin(['NJ'])]

source = ColumnDataSource(map_data_m)

TOOLS="pan,wheel_zoom,box_zoom,reset,hover,save"

p = figure(title="Title", tools=TOOLS,
x_axis_location=None, y_axis_location=None)
p.grid.grid_line_color = None

p.patches('x', 'y', source=source,
fill_color='color', fill_alpha=0.7,
line_color="white", line_width=0.5)

show(p)


anyone who is able to help me to resolve either of the question? I have been stuck for few days. Thanks a lot!







python-3.x bokeh






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 14 '18 at 21:10









David PuDavid Pu

11




11













  • Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

    – user2908623
    Nov 14 '18 at 21:29











  • hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

    – David Pu
    Nov 14 '18 at 22:01





















  • Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

    – user2908623
    Nov 14 '18 at 21:29











  • hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

    – David Pu
    Nov 14 '18 at 22:01



















Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

– user2908623
Nov 14 '18 at 21:29





Are there any NaN or inf values in your dataset? Reference: stackoverflow.com/questions/38821132/…

– user2908623
Nov 14 '18 at 21:29













hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

– David Pu
Nov 14 '18 at 22:01







hello @user2908623. thank you os much for replying back. I checked and there is no NaN in both my x and y...>_<

– David Pu
Nov 14 '18 at 22:01














1 Answer
1






active

oldest

votes


















0














Could you check if there are no infinite numbers in the dataset?
Reference: https://stackoverflow.com/a/47085304/2908623






share|improve this answer
























  • Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

    – David Pu
    Nov 19 '18 at 19:19











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Could you check if there are no infinite numbers in the dataset?
Reference: https://stackoverflow.com/a/47085304/2908623






share|improve this answer
























  • Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

    – David Pu
    Nov 19 '18 at 19:19
















0














Could you check if there are no infinite numbers in the dataset?
Reference: https://stackoverflow.com/a/47085304/2908623






share|improve this answer
























  • Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

    – David Pu
    Nov 19 '18 at 19:19














0












0








0







Could you check if there are no infinite numbers in the dataset?
Reference: https://stackoverflow.com/a/47085304/2908623






share|improve this answer













Could you check if there are no infinite numbers in the dataset?
Reference: https://stackoverflow.com/a/47085304/2908623







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 22:31









user2908623user2908623

416




416













  • Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

    – David Pu
    Nov 19 '18 at 19:19



















  • Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

    – David Pu
    Nov 19 '18 at 19:19

















Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

– David Pu
Nov 19 '18 at 19:19





Hello @user2908623 thanks for replying back again. I have seen that reference and tried all the solutions. Somehow after I upgraded my Bokeh to the newest version. it is working now. Really thank you for your help! :D

– David Pu
Nov 19 '18 at 19:19


















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