PostgreSQL declarative partitioning












0















i am trying to understand how can declarative partitioning used in my particular case.



i have a table that look like



CREATE TABLE test
(
created timestamp without time zone NOT NULL,
tx bigint NOT NULL unique

) PARTITION BY RANGE (created);

CREATE TABLE test_part PARTITION OF test
FOR VALUES FROM ('2017-01-01') TO ('2017-02-01');


and, if i try to create it i get



DETAIL:  UNIQUE constraint on table "test" lacks column "created" which is part of the partition key.


but, what i would like to do, it's to create a unique key on tx, and not on tx+created.



if i create a unique key (tx,created) then this it's valid, and it's not in my case



insert into test values('2017-01-02',1)
insert into test values('2017-01-01',1)


how can i create a unique index that doesn't contain the partition key?



in that case, i would like to store all the data partitioned based on created, but the txid should be unique on his own.










share|improve this question

























  • This is currently not possible.

    – a_horse_with_no_name
    Nov 13 '18 at 11:50
















0















i am trying to understand how can declarative partitioning used in my particular case.



i have a table that look like



CREATE TABLE test
(
created timestamp without time zone NOT NULL,
tx bigint NOT NULL unique

) PARTITION BY RANGE (created);

CREATE TABLE test_part PARTITION OF test
FOR VALUES FROM ('2017-01-01') TO ('2017-02-01');


and, if i try to create it i get



DETAIL:  UNIQUE constraint on table "test" lacks column "created" which is part of the partition key.


but, what i would like to do, it's to create a unique key on tx, and not on tx+created.



if i create a unique key (tx,created) then this it's valid, and it's not in my case



insert into test values('2017-01-02',1)
insert into test values('2017-01-01',1)


how can i create a unique index that doesn't contain the partition key?



in that case, i would like to store all the data partitioned based on created, but the txid should be unique on his own.










share|improve this question

























  • This is currently not possible.

    – a_horse_with_no_name
    Nov 13 '18 at 11:50














0












0








0








i am trying to understand how can declarative partitioning used in my particular case.



i have a table that look like



CREATE TABLE test
(
created timestamp without time zone NOT NULL,
tx bigint NOT NULL unique

) PARTITION BY RANGE (created);

CREATE TABLE test_part PARTITION OF test
FOR VALUES FROM ('2017-01-01') TO ('2017-02-01');


and, if i try to create it i get



DETAIL:  UNIQUE constraint on table "test" lacks column "created" which is part of the partition key.


but, what i would like to do, it's to create a unique key on tx, and not on tx+created.



if i create a unique key (tx,created) then this it's valid, and it's not in my case



insert into test values('2017-01-02',1)
insert into test values('2017-01-01',1)


how can i create a unique index that doesn't contain the partition key?



in that case, i would like to store all the data partitioned based on created, but the txid should be unique on his own.










share|improve this question
















i am trying to understand how can declarative partitioning used in my particular case.



i have a table that look like



CREATE TABLE test
(
created timestamp without time zone NOT NULL,
tx bigint NOT NULL unique

) PARTITION BY RANGE (created);

CREATE TABLE test_part PARTITION OF test
FOR VALUES FROM ('2017-01-01') TO ('2017-02-01');


and, if i try to create it i get



DETAIL:  UNIQUE constraint on table "test" lacks column "created" which is part of the partition key.


but, what i would like to do, it's to create a unique key on tx, and not on tx+created.



if i create a unique key (tx,created) then this it's valid, and it's not in my case



insert into test values('2017-01-02',1)
insert into test values('2017-01-01',1)


how can i create a unique index that doesn't contain the partition key?



in that case, i would like to store all the data partitioned based on created, but the txid should be unique on his own.







postgresql database-partitioning postgresql-11






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share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 11:51









a_horse_with_no_name

293k46447541




293k46447541










asked Nov 13 '18 at 11:48









user3804873user3804873

2516




2516













  • This is currently not possible.

    – a_horse_with_no_name
    Nov 13 '18 at 11:50



















  • This is currently not possible.

    – a_horse_with_no_name
    Nov 13 '18 at 11:50

















This is currently not possible.

– a_horse_with_no_name
Nov 13 '18 at 11:50





This is currently not possible.

– a_horse_with_no_name
Nov 13 '18 at 11:50












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