SQL 3 IDs Change Over Time












0















I have a logic question which I've been stuck on for a while.



Suppose there is one customer that can be serviced in two separate places, for place A they receive A_ID and place B they receive B_ID. There is a 3rd ID which I will call C_ID which links the two customers together to give a holistic view if they are on both platforms. The customers can be buying from place A only, place B only, or place A and B at the same time.



I want to create a volatile table to back fill populating with A_ID, B_ID, C_ID, on all days if if they are not null.



Currently the data can look like any of the following in the same table:



EXAMPLE A 
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 145 , ,
02/01/17 , 145 , ,
03/01/17 , 145 , 201501 , 601888
04/01/17 , 145 , 201502 , 601888
05/01/17 , 145 , 201502 , 601888


OR



EXAMPLE B
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 198 , ,
02/01/17 , 198 , ,
03/01/17 , 198 , ,
04/01/17 , 198 , ,
05/01/17 , 198 , ,


OR



EXAMPLE C
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , , 567222 ,
02/01/17 , , 567222 ,
03/01/17 , , 567222 ,
04/01/17 , , 567222 ,
05/01/17 , , 567222 ,


I tried a window function:



SELECT 
calendar_date,
MAX(A_ID) OVER(PARTITION BY C_ID) A_ID,
MAX(B_ID) OVER(PARTITION BY C_ID) B_ID,
MAX(C_ID) OVER(PARTITION BY B_ID,A_ID) C_ID,
FROM TABLE A


However this removes all examples which have not yet used both platforms, i.e. example B and example C will not show.



Any ideas?










share|improve this question

























  • Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

    – Schwern
    Nov 16 '18 at 16:54











  • There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

    – flippinart
    Nov 16 '18 at 17:08











  • So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

    – flippinart
    Nov 16 '18 at 17:21











  • What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

    – dnoeth
    Nov 16 '18 at 20:14











  • Hi @dnoeth thanks for your input - I would expect NULL.

    – flippinart
    Nov 19 '18 at 10:23
















0















I have a logic question which I've been stuck on for a while.



Suppose there is one customer that can be serviced in two separate places, for place A they receive A_ID and place B they receive B_ID. There is a 3rd ID which I will call C_ID which links the two customers together to give a holistic view if they are on both platforms. The customers can be buying from place A only, place B only, or place A and B at the same time.



I want to create a volatile table to back fill populating with A_ID, B_ID, C_ID, on all days if if they are not null.



Currently the data can look like any of the following in the same table:



EXAMPLE A 
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 145 , ,
02/01/17 , 145 , ,
03/01/17 , 145 , 201501 , 601888
04/01/17 , 145 , 201502 , 601888
05/01/17 , 145 , 201502 , 601888


OR



EXAMPLE B
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 198 , ,
02/01/17 , 198 , ,
03/01/17 , 198 , ,
04/01/17 , 198 , ,
05/01/17 , 198 , ,


OR



EXAMPLE C
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , , 567222 ,
02/01/17 , , 567222 ,
03/01/17 , , 567222 ,
04/01/17 , , 567222 ,
05/01/17 , , 567222 ,


I tried a window function:



SELECT 
calendar_date,
MAX(A_ID) OVER(PARTITION BY C_ID) A_ID,
MAX(B_ID) OVER(PARTITION BY C_ID) B_ID,
MAX(C_ID) OVER(PARTITION BY B_ID,A_ID) C_ID,
FROM TABLE A


However this removes all examples which have not yet used both platforms, i.e. example B and example C will not show.



Any ideas?










share|improve this question

























  • Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

    – Schwern
    Nov 16 '18 at 16:54











  • There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

    – flippinart
    Nov 16 '18 at 17:08











  • So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

    – flippinart
    Nov 16 '18 at 17:21











  • What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

    – dnoeth
    Nov 16 '18 at 20:14











  • Hi @dnoeth thanks for your input - I would expect NULL.

    – flippinart
    Nov 19 '18 at 10:23














0












0








0








I have a logic question which I've been stuck on for a while.



Suppose there is one customer that can be serviced in two separate places, for place A they receive A_ID and place B they receive B_ID. There is a 3rd ID which I will call C_ID which links the two customers together to give a holistic view if they are on both platforms. The customers can be buying from place A only, place B only, or place A and B at the same time.



I want to create a volatile table to back fill populating with A_ID, B_ID, C_ID, on all days if if they are not null.



Currently the data can look like any of the following in the same table:



EXAMPLE A 
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 145 , ,
02/01/17 , 145 , ,
03/01/17 , 145 , 201501 , 601888
04/01/17 , 145 , 201502 , 601888
05/01/17 , 145 , 201502 , 601888


OR



EXAMPLE B
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 198 , ,
02/01/17 , 198 , ,
03/01/17 , 198 , ,
04/01/17 , 198 , ,
05/01/17 , 198 , ,


OR



EXAMPLE C
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , , 567222 ,
02/01/17 , , 567222 ,
03/01/17 , , 567222 ,
04/01/17 , , 567222 ,
05/01/17 , , 567222 ,


I tried a window function:



SELECT 
calendar_date,
MAX(A_ID) OVER(PARTITION BY C_ID) A_ID,
MAX(B_ID) OVER(PARTITION BY C_ID) B_ID,
MAX(C_ID) OVER(PARTITION BY B_ID,A_ID) C_ID,
FROM TABLE A


However this removes all examples which have not yet used both platforms, i.e. example B and example C will not show.



Any ideas?










share|improve this question
















I have a logic question which I've been stuck on for a while.



Suppose there is one customer that can be serviced in two separate places, for place A they receive A_ID and place B they receive B_ID. There is a 3rd ID which I will call C_ID which links the two customers together to give a holistic view if they are on both platforms. The customers can be buying from place A only, place B only, or place A and B at the same time.



I want to create a volatile table to back fill populating with A_ID, B_ID, C_ID, on all days if if they are not null.



Currently the data can look like any of the following in the same table:



EXAMPLE A 
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 145 , ,
02/01/17 , 145 , ,
03/01/17 , 145 , 201501 , 601888
04/01/17 , 145 , 201502 , 601888
05/01/17 , 145 , 201502 , 601888


OR



EXAMPLE B
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , 198 , ,
02/01/17 , 198 , ,
03/01/17 , 198 , ,
04/01/17 , 198 , ,
05/01/17 , 198 , ,


OR



EXAMPLE C
Date , A_ID , B_ID , C_ID
---------------------------------------------
01/01/17 , , 567222 ,
02/01/17 , , 567222 ,
03/01/17 , , 567222 ,
04/01/17 , , 567222 ,
05/01/17 , , 567222 ,


I tried a window function:



SELECT 
calendar_date,
MAX(A_ID) OVER(PARTITION BY C_ID) A_ID,
MAX(B_ID) OVER(PARTITION BY C_ID) B_ID,
MAX(C_ID) OVER(PARTITION BY B_ID,A_ID) C_ID,
FROM TABLE A


However this removes all examples which have not yet used both platforms, i.e. example B and example C will not show.



Any ideas?







sql teradata






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 16:54









Mihai Chelaru

2,180101122




2,180101122










asked Nov 16 '18 at 16:40









flippinartflippinart

1




1













  • Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

    – Schwern
    Nov 16 '18 at 16:54











  • There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

    – flippinart
    Nov 16 '18 at 17:08











  • So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

    – flippinart
    Nov 16 '18 at 17:21











  • What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

    – dnoeth
    Nov 16 '18 at 20:14











  • Hi @dnoeth thanks for your input - I would expect NULL.

    – flippinart
    Nov 19 '18 at 10:23



















  • Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

    – Schwern
    Nov 16 '18 at 16:54











  • There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

    – flippinart
    Nov 16 '18 at 17:08











  • So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

    – flippinart
    Nov 16 '18 at 17:21











  • What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

    – dnoeth
    Nov 16 '18 at 20:14











  • Hi @dnoeth thanks for your input - I would expect NULL.

    – flippinart
    Nov 19 '18 at 10:23

















Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

– Schwern
Nov 16 '18 at 16:54





Hi, and welcome to Stack Overflow. What is the purpose of back filling the data? Is it just to ensure you have all their IDs available in every row?

– Schwern
Nov 16 '18 at 16:54













There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

– flippinart
Nov 16 '18 at 17:08





There are scripts that run a lookback view at each customer later in the process for customer segmentation and analysis - without consistent IDs for each customer in all months previous erroneous results are produced

– flippinart
Nov 16 '18 at 17:08













So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

– flippinart
Nov 16 '18 at 17:21





So yes - just to be clear, I want all "their" IDs to show in everyone. I.E. if a customer has B_ID NOT NULL in the future but NULL in the past, I want that NOT NULL value to show in the past. And thank you!

– flippinart
Nov 16 '18 at 17:21













What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

– dnoeth
Nov 16 '18 at 20:14





What result do you expect when there's no id for a place, e.g. B_ID and C_ID in example B?

– dnoeth
Nov 16 '18 at 20:14













Hi @dnoeth thanks for your input - I would expect NULL.

– flippinart
Nov 19 '18 at 10:23





Hi @dnoeth thanks for your input - I would expect NULL.

– flippinart
Nov 19 '18 at 10:23












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