@IBInspectable property doesn't show up in Interface Builder
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1
I have a class like this, and this IB doesn't show the property foo1 in inspection pane.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0)
}
What's wrong?
(Xcode 10.1)
xcode interface-builder ibdesignable ibinspectable
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
add a comment |
1
I have a class like this, and this IB doesn't show the property foo1 in inspection pane.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0)
}
What's wrong?
(Xcode 10.1)
xcode interface-builder ibdesignable ibinspectable
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
add a comment |
1
1
1
I have a class like this, and this IB doesn't show the property foo1 in inspection pane.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0)
}
What's wrong?
(Xcode 10.1)
xcode interface-builder ibdesignable ibinspectable
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
I have a class like this, and this IB doesn't show the property foo1 in inspection pane.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0)
}
What's wrong?
(Xcode 10.1)
xcode interface-builder ibdesignable ibinspectable
xcode interface-builder ibdesignable ibinspectable
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
asked Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
40.5k60254449
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
I don't know why, but explicit property type expression fixes the problem.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0) // No work.
@IBInspectable var bar2: CGFloat = 0 // Works!
}
I really don't know why one form doesn't work while the other works.
I hope Apple to fix this ASAP.
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
A strange requirement that seems necessary at the moment,@IBInspectable var bar = UIColor.redwill not work where as@IBInspectable var bar: UIColor = .redwill. If anyone else is having issues I strongly recommend checking that you have denoted the type.
– Carl
Mar 12 at 20:52
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
I don't know why, but explicit property type expression fixes the problem.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0) // No work.
@IBInspectable var bar2: CGFloat = 0 // Works!
}
I really don't know why one form doesn't work while the other works.
I hope Apple to fix this ASAP.
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
A strange requirement that seems necessary at the moment,@IBInspectable var bar = UIColor.redwill not work where as@IBInspectable var bar: UIColor = .redwill. If anyone else is having issues I strongly recommend checking that you have denoted the type.
– Carl
Mar 12 at 20:52
add a comment |
2
I don't know why, but explicit property type expression fixes the problem.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0) // No work.
@IBInspectable var bar2: CGFloat = 0 // Works!
}
I really don't know why one form doesn't work while the other works.
I hope Apple to fix this ASAP.
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
A strange requirement that seems necessary at the moment,@IBInspectable var bar = UIColor.redwill not work where as@IBInspectable var bar: UIColor = .redwill. If anyone else is having issues I strongly recommend checking that you have denoted the type.
– Carl
Mar 12 at 20:52
add a comment |
2
2
2
I don't know why, but explicit property type expression fixes the problem.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0) // No work.
@IBInspectable var bar2: CGFloat = 0 // Works!
}
I really don't know why one form doesn't work while the other works.
I hope Apple to fix this ASAP.
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
I don't know why, but explicit property type expression fixes the problem.
@IBDesignable
final class Foo: UIView {
@IBInspectable var bar1 = CGFloat(0) // No work.
@IBInspectable var bar2: CGFloat = 0 // Works!
}
I really don't know why one form doesn't work while the other works.
I hope Apple to fix this ASAP.
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
edited Mar 17 at 19:53
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
answered Nov 25 '18 at 6:45
EonilEonil
40.5k60254449
40.5k60254449
A strange requirement that seems necessary at the moment,@IBInspectable var bar = UIColor.redwill not work where as@IBInspectable var bar: UIColor = .redwill. If anyone else is having issues I strongly recommend checking that you have denoted the type.
– Carl
Mar 12 at 20:52
add a comment |
A strange requirement that seems necessary at the moment,@IBInspectable var bar = UIColor.redwill not work where as@IBInspectable var bar: UIColor = .redwill. If anyone else is having issues I strongly recommend checking that you have denoted the type.
– Carl
Mar 12 at 20:52
A strange requirement that seems necessary at the moment,
@IBInspectable var bar = UIColor.red will not work where as @IBInspectable var bar: UIColor = .red will. If anyone else is having issues I strongly recommend checking that you have denoted the type.– Carl
Mar 12 at 20:52
A strange requirement that seems necessary at the moment,
@IBInspectable var bar = UIColor.red will not work where as @IBInspectable var bar: UIColor = .red will. If anyone else is having issues I strongly recommend checking that you have denoted the type.– Carl
Mar 12 at 20:52
add a comment |
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