Recursive table formulating function that waits for page to load before each step





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I am trying to find out how to have all of these things in the same function:




  1. An array of objects where sections of it are generated through a time-consuming function

  2. The DOM loading before each attempt at loading the next section of array objects


I have tried Promise, recursive functions to my best ability, to no prevail.
Here is the code I am manipulating:



showLoader();

var preArray = new Array();
var subjects = scrapeSubjects();

function next(subject, prearray) {
if (subject.length) {
//Writes an element specifying the current section being loaded for the user on a loading page
writeToLoader(subject[0]);
$( document ).ready( function() { next(subject); });
prearray = prearray.concat(pullData(subject.shift()));
}
};
preArray = next(subjects, preArray);

var array = stripNonRooms(preArray, roomsArray);
localStorage.setItem('data', JSON.stringify(array));
//hides the loader when it is complete
var loader = document.getElementById("loader");
loader.style.display = "none";


Is there anything I can do to show the user the section that is currently being loaded, while it is being loaded?










share|improve this question























  • Where are the promises in your code? Which part is actually asynchronous?

    – Bergi
    Nov 25 '18 at 12:13











  • @Bergi can I not just use some sort of wait function before continuing my code?

    – tincopper2
    Nov 27 '18 at 1:22











  • No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

    – Bergi
    Nov 27 '18 at 8:00











  • @Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

    – tincopper2
    Nov 28 '18 at 14:25











  • The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

    – Bergi
    Nov 28 '18 at 14:40


















0















I am trying to find out how to have all of these things in the same function:




  1. An array of objects where sections of it are generated through a time-consuming function

  2. The DOM loading before each attempt at loading the next section of array objects


I have tried Promise, recursive functions to my best ability, to no prevail.
Here is the code I am manipulating:



showLoader();

var preArray = new Array();
var subjects = scrapeSubjects();

function next(subject, prearray) {
if (subject.length) {
//Writes an element specifying the current section being loaded for the user on a loading page
writeToLoader(subject[0]);
$( document ).ready( function() { next(subject); });
prearray = prearray.concat(pullData(subject.shift()));
}
};
preArray = next(subjects, preArray);

var array = stripNonRooms(preArray, roomsArray);
localStorage.setItem('data', JSON.stringify(array));
//hides the loader when it is complete
var loader = document.getElementById("loader");
loader.style.display = "none";


Is there anything I can do to show the user the section that is currently being loaded, while it is being loaded?










share|improve this question























  • Where are the promises in your code? Which part is actually asynchronous?

    – Bergi
    Nov 25 '18 at 12:13











  • @Bergi can I not just use some sort of wait function before continuing my code?

    – tincopper2
    Nov 27 '18 at 1:22











  • No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

    – Bergi
    Nov 27 '18 at 8:00











  • @Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

    – tincopper2
    Nov 28 '18 at 14:25











  • The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

    – Bergi
    Nov 28 '18 at 14:40














0












0








0








I am trying to find out how to have all of these things in the same function:




  1. An array of objects where sections of it are generated through a time-consuming function

  2. The DOM loading before each attempt at loading the next section of array objects


I have tried Promise, recursive functions to my best ability, to no prevail.
Here is the code I am manipulating:



showLoader();

var preArray = new Array();
var subjects = scrapeSubjects();

function next(subject, prearray) {
if (subject.length) {
//Writes an element specifying the current section being loaded for the user on a loading page
writeToLoader(subject[0]);
$( document ).ready( function() { next(subject); });
prearray = prearray.concat(pullData(subject.shift()));
}
};
preArray = next(subjects, preArray);

var array = stripNonRooms(preArray, roomsArray);
localStorage.setItem('data', JSON.stringify(array));
//hides the loader when it is complete
var loader = document.getElementById("loader");
loader.style.display = "none";


Is there anything I can do to show the user the section that is currently being loaded, while it is being loaded?










share|improve this question














I am trying to find out how to have all of these things in the same function:




  1. An array of objects where sections of it are generated through a time-consuming function

  2. The DOM loading before each attempt at loading the next section of array objects


I have tried Promise, recursive functions to my best ability, to no prevail.
Here is the code I am manipulating:



showLoader();

var preArray = new Array();
var subjects = scrapeSubjects();

function next(subject, prearray) {
if (subject.length) {
//Writes an element specifying the current section being loaded for the user on a loading page
writeToLoader(subject[0]);
$( document ).ready( function() { next(subject); });
prearray = prearray.concat(pullData(subject.shift()));
}
};
preArray = next(subjects, preArray);

var array = stripNonRooms(preArray, roomsArray);
localStorage.setItem('data', JSON.stringify(array));
//hides the loader when it is complete
var loader = document.getElementById("loader");
loader.style.display = "none";


Is there anything I can do to show the user the section that is currently being loaded, while it is being loaded?







javascript jquery arrays async-await






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 25 '18 at 7:24









tincopper2tincopper2

449




449













  • Where are the promises in your code? Which part is actually asynchronous?

    – Bergi
    Nov 25 '18 at 12:13











  • @Bergi can I not just use some sort of wait function before continuing my code?

    – tincopper2
    Nov 27 '18 at 1:22











  • No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

    – Bergi
    Nov 27 '18 at 8:00











  • @Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

    – tincopper2
    Nov 28 '18 at 14:25











  • The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

    – Bergi
    Nov 28 '18 at 14:40



















  • Where are the promises in your code? Which part is actually asynchronous?

    – Bergi
    Nov 25 '18 at 12:13











  • @Bergi can I not just use some sort of wait function before continuing my code?

    – tincopper2
    Nov 27 '18 at 1:22











  • No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

    – Bergi
    Nov 27 '18 at 8:00











  • @Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

    – tincopper2
    Nov 28 '18 at 14:25











  • The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

    – Bergi
    Nov 28 '18 at 14:40

















Where are the promises in your code? Which part is actually asynchronous?

– Bergi
Nov 25 '18 at 12:13





Where are the promises in your code? Which part is actually asynchronous?

– Bergi
Nov 25 '18 at 12:13













@Bergi can I not just use some sort of wait function before continuing my code?

– tincopper2
Nov 27 '18 at 1:22





@Bergi can I not just use some sort of wait function before continuing my code?

– tincopper2
Nov 27 '18 at 1:22













No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

– Bergi
Nov 27 '18 at 8:00





No, you will need to use a specific wait function, and if you want to wait for something it'll be asychronous. But what in your code snippet above do you want to wait for?

– Bergi
Nov 27 '18 at 8:00













@Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

– tincopper2
Nov 28 '18 at 14:25





@Bergi page ready, I have it specified, I only want to update a doc as I am running my code, so the user can see the div update as the code is running

– tincopper2
Nov 28 '18 at 14:25













The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

– Bergi
Nov 28 '18 at 14:40





The document does get ready only once. If you change something, that doesn't "un-ready" the page. If your problem is long-running code and the browser doesn't render your change soon enough, the only thing you can do is to make it asynchronous with a little timeout.

– Bergi
Nov 28 '18 at 14:40












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