OleDb returning System.Data.OleDb.OleDbException: 'No value given for one or more required parameters.' when...
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I keep getting System.Data.OleDb.OleDbException: 'No value given for one or more required parameters.' but i am giving it a value as you can see in my code:
private void PopWeapSel(string read)
{
string weapID = read;
string weapDam = "";
string weapPat = "";
string weapHeat = "";
string weapName = "";
OleDbConnection dbConn = new System.Data.OleDb.OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=BHShooterProjectDB.accdb");
string sql = "SELECT ItemWeaponType.WeaponID, ItemWeaponType.WeaponDamage, ItemWeaponType.WeaponPattern, ItemWeaponType.WeaponHeatValue, ItemWeaponType.WeaponCoolRate, ItemWeaponType.WeaponName FROM ItemWeaponType WHERE ItemWeaponTypeWeaponID = @PU;";
OleDbCommand cmd = new OleDbCommand(sql, dbConn);
foreach (string WeapID in weapID)
{
if (WeapID == "")
{
return;
}
cmd.Parameters.AddWithValue("@PU", WeapID); ///Problem Line
dbConn.Open();
OleDbDataReader reader = cmd.ExecuteReader();
if (reader.Read())
{
weapDam = reader[1].ToString();
weapPat = reader[2].ToString();
weapHeat = reader[3].ToString();
weapName = reader[4].ToString();
}
dbConn.Close();
this.DGV_WS.Rows.Add(weapDam, weapPat, weapHeat, weapName);
}
}
When i look at the locals in the locals in debug. WeapID has a value of "1" as it should. Have i missed something in terms of syntax?
Thanks!
c# sql oledb
|
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up vote
-1
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I keep getting System.Data.OleDb.OleDbException: 'No value given for one or more required parameters.' but i am giving it a value as you can see in my code:
private void PopWeapSel(string read)
{
string weapID = read;
string weapDam = "";
string weapPat = "";
string weapHeat = "";
string weapName = "";
OleDbConnection dbConn = new System.Data.OleDb.OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=BHShooterProjectDB.accdb");
string sql = "SELECT ItemWeaponType.WeaponID, ItemWeaponType.WeaponDamage, ItemWeaponType.WeaponPattern, ItemWeaponType.WeaponHeatValue, ItemWeaponType.WeaponCoolRate, ItemWeaponType.WeaponName FROM ItemWeaponType WHERE ItemWeaponTypeWeaponID = @PU;";
OleDbCommand cmd = new OleDbCommand(sql, dbConn);
foreach (string WeapID in weapID)
{
if (WeapID == "")
{
return;
}
cmd.Parameters.AddWithValue("@PU", WeapID); ///Problem Line
dbConn.Open();
OleDbDataReader reader = cmd.ExecuteReader();
if (reader.Read())
{
weapDam = reader[1].ToString();
weapPat = reader[2].ToString();
weapHeat = reader[3].ToString();
weapName = reader[4].ToString();
}
dbConn.Close();
this.DGV_WS.Rows.Add(weapDam, weapPat, weapHeat, weapName);
}
}
When i look at the locals in the locals in debug. WeapID has a value of "1" as it should. Have i missed something in terms of syntax?
Thanks!
c# sql oledb
I also suspect this code is going to have issues on the second iteration of theforeach- since you will have added two parameters (with the same name) to a singleOleDbCommand. Did you mean to instantiate theOleDbCommandinside the loop?
– mjwills
Nov 8 at 11:30
The most obvious cause of this error is thatWeapIDisnull. The behaviour you are seeing would be expected in that scenario.
– mjwills
Nov 8 at 11:31
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also movedOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each. Still get the same error.
– Blackclaw _
Nov 8 at 16:55
ItemWeaponTypeWeaponIDis missing a.. This is a typo. Voting to close.
– mjwills
Nov 8 at 20:13
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39
|
show 1 more comment
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I keep getting System.Data.OleDb.OleDbException: 'No value given for one or more required parameters.' but i am giving it a value as you can see in my code:
private void PopWeapSel(string read)
{
string weapID = read;
string weapDam = "";
string weapPat = "";
string weapHeat = "";
string weapName = "";
OleDbConnection dbConn = new System.Data.OleDb.OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=BHShooterProjectDB.accdb");
string sql = "SELECT ItemWeaponType.WeaponID, ItemWeaponType.WeaponDamage, ItemWeaponType.WeaponPattern, ItemWeaponType.WeaponHeatValue, ItemWeaponType.WeaponCoolRate, ItemWeaponType.WeaponName FROM ItemWeaponType WHERE ItemWeaponTypeWeaponID = @PU;";
OleDbCommand cmd = new OleDbCommand(sql, dbConn);
foreach (string WeapID in weapID)
{
if (WeapID == "")
{
return;
}
cmd.Parameters.AddWithValue("@PU", WeapID); ///Problem Line
dbConn.Open();
OleDbDataReader reader = cmd.ExecuteReader();
if (reader.Read())
{
weapDam = reader[1].ToString();
weapPat = reader[2].ToString();
weapHeat = reader[3].ToString();
weapName = reader[4].ToString();
}
dbConn.Close();
this.DGV_WS.Rows.Add(weapDam, weapPat, weapHeat, weapName);
}
}
When i look at the locals in the locals in debug. WeapID has a value of "1" as it should. Have i missed something in terms of syntax?
Thanks!
c# sql oledb
I keep getting System.Data.OleDb.OleDbException: 'No value given for one or more required parameters.' but i am giving it a value as you can see in my code:
private void PopWeapSel(string read)
{
string weapID = read;
string weapDam = "";
string weapPat = "";
string weapHeat = "";
string weapName = "";
OleDbConnection dbConn = new System.Data.OleDb.OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=BHShooterProjectDB.accdb");
string sql = "SELECT ItemWeaponType.WeaponID, ItemWeaponType.WeaponDamage, ItemWeaponType.WeaponPattern, ItemWeaponType.WeaponHeatValue, ItemWeaponType.WeaponCoolRate, ItemWeaponType.WeaponName FROM ItemWeaponType WHERE ItemWeaponTypeWeaponID = @PU;";
OleDbCommand cmd = new OleDbCommand(sql, dbConn);
foreach (string WeapID in weapID)
{
if (WeapID == "")
{
return;
}
cmd.Parameters.AddWithValue("@PU", WeapID); ///Problem Line
dbConn.Open();
OleDbDataReader reader = cmd.ExecuteReader();
if (reader.Read())
{
weapDam = reader[1].ToString();
weapPat = reader[2].ToString();
weapHeat = reader[3].ToString();
weapName = reader[4].ToString();
}
dbConn.Close();
this.DGV_WS.Rows.Add(weapDam, weapPat, weapHeat, weapName);
}
}
When i look at the locals in the locals in debug. WeapID has a value of "1" as it should. Have i missed something in terms of syntax?
Thanks!
c# sql oledb
c# sql oledb
edited Nov 8 at 12:07
Rob
9711021
9711021
asked Nov 8 at 11:25
Blackclaw _
43
43
I also suspect this code is going to have issues on the second iteration of theforeach- since you will have added two parameters (with the same name) to a singleOleDbCommand. Did you mean to instantiate theOleDbCommandinside the loop?
– mjwills
Nov 8 at 11:30
The most obvious cause of this error is thatWeapIDisnull. The behaviour you are seeing would be expected in that scenario.
– mjwills
Nov 8 at 11:31
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also movedOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each. Still get the same error.
– Blackclaw _
Nov 8 at 16:55
ItemWeaponTypeWeaponIDis missing a.. This is a typo. Voting to close.
– mjwills
Nov 8 at 20:13
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39
|
show 1 more comment
I also suspect this code is going to have issues on the second iteration of theforeach- since you will have added two parameters (with the same name) to a singleOleDbCommand. Did you mean to instantiate theOleDbCommandinside the loop?
– mjwills
Nov 8 at 11:30
The most obvious cause of this error is thatWeapIDisnull. The behaviour you are seeing would be expected in that scenario.
– mjwills
Nov 8 at 11:31
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also movedOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each. Still get the same error.
– Blackclaw _
Nov 8 at 16:55
ItemWeaponTypeWeaponIDis missing a.. This is a typo. Voting to close.
– mjwills
Nov 8 at 20:13
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39
I also suspect this code is going to have issues on the second iteration of the
foreach - since you will have added two parameters (with the same name) to a single OleDbCommand. Did you mean to instantiate the OleDbCommand inside the loop?– mjwills
Nov 8 at 11:30
I also suspect this code is going to have issues on the second iteration of the
foreach - since you will have added two parameters (with the same name) to a single OleDbCommand. Did you mean to instantiate the OleDbCommand inside the loop?– mjwills
Nov 8 at 11:30
The most obvious cause of this error is that
WeapID is null. The behaviour you are seeing would be expected in that scenario.– mjwills
Nov 8 at 11:31
The most obvious cause of this error is that
WeapID is null. The behaviour you are seeing would be expected in that scenario.– mjwills
Nov 8 at 11:31
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also moved
OleDbCommand cmd = new OleDbCommand(sql, dbConn); inside of the for each. Still get the same error.– Blackclaw _
Nov 8 at 16:55
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also moved
OleDbCommand cmd = new OleDbCommand(sql, dbConn); inside of the for each. Still get the same error.– Blackclaw _
Nov 8 at 16:55
ItemWeaponTypeWeaponID is missing a .. This is a typo. Voting to close.– mjwills
Nov 8 at 20:13
ItemWeaponTypeWeaponID is missing a .. This is a typo. Voting to close.– mjwills
Nov 8 at 20:13
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39
|
show 1 more comment
1 Answer
1
active
oldest
votes
up vote
0
down vote
Move your OleDbCommand cmd = new OleDbCommand(sql, dbConn); line inside the foreach statement.
You are using the same command over and over, and adding more parameters than the query has.
I tried movingOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each and the same error still occurs.
– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Move your OleDbCommand cmd = new OleDbCommand(sql, dbConn); line inside the foreach statement.
You are using the same command over and over, and adding more parameters than the query has.
I tried movingOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each and the same error still occurs.
– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
add a comment |
up vote
0
down vote
Move your OleDbCommand cmd = new OleDbCommand(sql, dbConn); line inside the foreach statement.
You are using the same command over and over, and adding more parameters than the query has.
I tried movingOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each and the same error still occurs.
– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
add a comment |
up vote
0
down vote
up vote
0
down vote
Move your OleDbCommand cmd = new OleDbCommand(sql, dbConn); line inside the foreach statement.
You are using the same command over and over, and adding more parameters than the query has.
Move your OleDbCommand cmd = new OleDbCommand(sql, dbConn); line inside the foreach statement.
You are using the same command over and over, and adding more parameters than the query has.
answered Nov 8 at 12:37
Gonzalo Lorieto
521212
521212
I tried movingOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each and the same error still occurs.
– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
add a comment |
I tried movingOleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each and the same error still occurs.
– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
I tried moving
OleDbCommand cmd = new OleDbCommand(sql, dbConn); inside of the for each and the same error still occurs.– Blackclaw _
Nov 8 at 16:57
I tried moving
OleDbCommand cmd = new OleDbCommand(sql, dbConn); inside of the for each and the same error still occurs.– Blackclaw _
Nov 8 at 16:57
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
Have you debugged all the way through? When does the exceptions is thrown?
– Gonzalo Lorieto
Nov 8 at 17:06
add a comment |
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I also suspect this code is going to have issues on the second iteration of the
foreach- since you will have added two parameters (with the same name) to a singleOleDbCommand. Did you mean to instantiate theOleDbCommandinside the loop?– mjwills
Nov 8 at 11:30
The most obvious cause of this error is that
WeapIDisnull. The behaviour you are seeing would be expected in that scenario.– mjwills
Nov 8 at 11:31
@mjwills if i type "?WeapID" in the immediate window it returns "1". Also moved
OleDbCommand cmd = new OleDbCommand(sql, dbConn);inside of the for each. Still get the same error.– Blackclaw _
Nov 8 at 16:55
ItemWeaponTypeWeaponIDis missing a.. This is a typo. Voting to close.– mjwills
Nov 8 at 20:13
@mjwills Ah thank you so much! Good spot! Looked all the way through my SQL about 10 times.......
– Blackclaw _
Nov 8 at 20:39