Select record with max value from each group with Query DSL
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0
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I have a score table where I have players scores, and I want select unique records for each player with the biggest score.
Here is the table:
id | player_id | score | ...
1 | 1 | 10 | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
5 | 3 | 2 | ...
Expected result:
id | player_id | score | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
I can achieve that with pure SQL like this:
SELECT *
FROM player_score ps
WHERE ps.score =
(
SELECT max(ps2.score)
FROM player_score ps2
WHERE ps2.player_id = ps.player_id
)
Can you tell me how to achieve the same query with query dsl? I found some solutions with JPASubQuery but this class doesn't work for me (my IDE cannot resolve this class). I am using querydsl 4.x. Thank you in advance.
sql jpa spring-data-jpa querydsl
edited Nov 9 at 13:58
octano
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
add a comment |
up vote
0
down vote
favorite
I have a score table where I have players scores, and I want select unique records for each player with the biggest score.
Here is the table:
id | player_id | score | ...
1 | 1 | 10 | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
5 | 3 | 2 | ...
Expected result:
id | player_id | score | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
I can achieve that with pure SQL like this:
SELECT *
FROM player_score ps
WHERE ps.score =
(
SELECT max(ps2.score)
FROM player_score ps2
WHERE ps2.player_id = ps.player_id
)
Can you tell me how to achieve the same query with query dsl? I found some solutions with JPASubQuery but this class doesn't work for me (my IDE cannot resolve this class). I am using querydsl 4.x. Thank you in advance.
sql jpa spring-data-jpa querydsl
edited Nov 9 at 13:58
octano
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a score table where I have players scores, and I want select unique records for each player with the biggest score.
Here is the table:
id | player_id | score | ...
1 | 1 | 10 | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
5 | 3 | 2 | ...
Expected result:
id | player_id | score | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
I can achieve that with pure SQL like this:
SELECT *
FROM player_score ps
WHERE ps.score =
(
SELECT max(ps2.score)
FROM player_score ps2
WHERE ps2.player_id = ps.player_id
)
Can you tell me how to achieve the same query with query dsl? I found some solutions with JPASubQuery but this class doesn't work for me (my IDE cannot resolve this class). I am using querydsl 4.x. Thank you in advance.
sql jpa spring-data-jpa querydsl
edited Nov 9 at 13:58
octano
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
I have a score table where I have players scores, and I want select unique records for each player with the biggest score.
Here is the table:
id | player_id | score | ...
1 | 1 | 10 | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
5 | 3 | 2 | ...
Expected result:
id | player_id | score | ...
2 | 2 | 21 | ...
3 | 3 | 9 | ...
4 | 1 | 30 | ...
I can achieve that with pure SQL like this:
SELECT *
FROM player_score ps
WHERE ps.score =
(
SELECT max(ps2.score)
FROM player_score ps2
WHERE ps2.player_id = ps.player_id
)
Can you tell me how to achieve the same query with query dsl? I found some solutions with JPASubQuery but this class doesn't work for me (my IDE cannot resolve this class). I am using querydsl 4.x. Thank you in advance.
sql jpa spring-data-jpa querydsl
sql jpa spring-data-jpa querydsl
edited Nov 9 at 13:58
octano
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
edited Nov 9 at 13:58
octano
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
edited Nov 9 at 13:58
octano
208415
edited Nov 9 at 13:58
octano
208415
edited Nov 9 at 13:58
octano
208415
208415
asked Nov 9 at 12:51
Denis Stephanov
34121140
asked Nov 9 at 12:51
Denis Stephanov
34121140
asked Nov 9 at 12:51
Denis Stephanov
34121140
34121140
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
JPASubQuery has been removed in querydsl 4. Instead use JPAExpressions.select. Your WHERE clause should look something like this:
.where(playerScore.score.eq(JPAExpressions.select(playerScore2.score.max())
.from(playerScore2))
.where(playerScore2.playerId.eq(playerScore.playerId)))
answered Nov 15 at 20:29
Robert Bain
3,58842039
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
JPASubQuery has been removed in querydsl 4. Instead use JPAExpressions.select. Your WHERE clause should look something like this:
.where(playerScore.score.eq(JPAExpressions.select(playerScore2.score.max())
.from(playerScore2))
.where(playerScore2.playerId.eq(playerScore.playerId)))
answered Nov 15 at 20:29
Robert Bain
3,58842039
add a comment |
up vote
0
down vote
accepted
JPASubQuery has been removed in querydsl 4. Instead use JPAExpressions.select. Your WHERE clause should look something like this:
.where(playerScore.score.eq(JPAExpressions.select(playerScore2.score.max())
.from(playerScore2))
.where(playerScore2.playerId.eq(playerScore.playerId)))
answered Nov 15 at 20:29
Robert Bain
3,58842039
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
JPASubQuery has been removed in querydsl 4. Instead use JPAExpressions.select. Your WHERE clause should look something like this:
.where(playerScore.score.eq(JPAExpressions.select(playerScore2.score.max())
.from(playerScore2))
.where(playerScore2.playerId.eq(playerScore.playerId)))
answered Nov 15 at 20:29
Robert Bain
3,58842039
JPASubQuery has been removed in querydsl 4. Instead use JPAExpressions.select. Your WHERE clause should look something like this:
.where(playerScore.score.eq(JPAExpressions.select(playerScore2.score.max())
.from(playerScore2))
.where(playerScore2.playerId.eq(playerScore.playerId)))
answered Nov 15 at 20:29
Robert Bain
3,58842039
answered Nov 15 at 20:29
Robert Bain
3,58842039
answered Nov 15 at 20:29
Robert Bain
3,58842039
answered Nov 15 at 20:29
Robert Bain
3,58842039
3,58842039
add a comment |
add a comment |
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