how to generate combination of number length 2 in asp.net c#
I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.
int array = {1, 2, 3, 4};
I need the output to be like this:
{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}
combinations permutation probability
add a comment |
I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.
int array = {1, 2, 3, 4};
I need the output to be like this:
{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}
combinations permutation probability
Do you want{4,1}{4,2}{4,3}
as well?
– Joseph Wood
Nov 12 '18 at 11:00
add a comment |
I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.
int array = {1, 2, 3, 4};
I need the output to be like this:
{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}
combinations permutation probability
I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.
int array = {1, 2, 3, 4};
I need the output to be like this:
{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}
combinations permutation probability
combinations permutation probability
edited Nov 12 '18 at 10:44
Rahul Agarwal
2,19141027
2,19141027
asked Nov 12 '18 at 10:01
Vinay Maurya
14
14
Do you want{4,1}{4,2}{4,3}
as well?
– Joseph Wood
Nov 12 '18 at 11:00
add a comment |
Do you want{4,1}{4,2}{4,3}
as well?
– Joseph Wood
Nov 12 '18 at 11:00
Do you want
{4,1}{4,2}{4,3}
as well?– Joseph Wood
Nov 12 '18 at 11:00
Do you want
{4,1}{4,2}{4,3}
as well?– Joseph Wood
Nov 12 '18 at 11:00
add a comment |
1 Answer
1
active
oldest
votes
Do something like this.
for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Do something like this.
for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}
add a comment |
Do something like this.
for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}
add a comment |
Do something like this.
for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}
Do something like this.
for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}
answered Nov 12 '18 at 10:50
Bruce Chen
944
944
add a comment |
add a comment |
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Do you want
{4,1}{4,2}{4,3}
as well?– Joseph Wood
Nov 12 '18 at 11:00