how to generate combination of number length 2 in asp.net c#












0














I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.



int array = {1, 2, 3, 4};


I need the output to be like this:



{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}









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  • Do you want {4,1}{4,2}{4,3} as well?
    – Joseph Wood
    Nov 12 '18 at 11:00


















0














I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.



int array = {1, 2, 3, 4};


I need the output to be like this:



{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}









share|improve this question
























  • Do you want {4,1}{4,2}{4,3} as well?
    – Joseph Wood
    Nov 12 '18 at 11:00
















0












0








0







I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.



int array = {1, 2, 3, 4};


I need the output to be like this:



{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}









share|improve this question















I have 1-9 digit number and want to generate probability (combination) of number without duplicate and with duplicate.



int array = {1, 2, 3, 4};


I need the output to be like this:



{1,2}{1,3}{1,4}{2,1}{2,3}{2,4}{3,1}{3,2}{3,4}{1,1}{2,2}{3,3}{4,4}






combinations permutation probability






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edited Nov 12 '18 at 10:44









Rahul Agarwal

2,19141027




2,19141027










asked Nov 12 '18 at 10:01









Vinay Maurya

14




14












  • Do you want {4,1}{4,2}{4,3} as well?
    – Joseph Wood
    Nov 12 '18 at 11:00




















  • Do you want {4,1}{4,2}{4,3} as well?
    – Joseph Wood
    Nov 12 '18 at 11:00


















Do you want {4,1}{4,2}{4,3} as well?
– Joseph Wood
Nov 12 '18 at 11:00






Do you want {4,1}{4,2}{4,3} as well?
– Joseph Wood
Nov 12 '18 at 11:00














1 Answer
1






active

oldest

votes


















0














Do something like this.



for(int i = 0 ; i < array.size() ; i ++){
for(int j = i + 1; j < array.size() ;j++)
{
int first = array[i];
int second = array[j];
//Do someting.
}
}





share|improve this answer





















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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Do something like this.



    for(int i = 0 ; i < array.size() ; i ++){
    for(int j = i + 1; j < array.size() ;j++)
    {
    int first = array[i];
    int second = array[j];
    //Do someting.
    }
    }





    share|improve this answer


























      0














      Do something like this.



      for(int i = 0 ; i < array.size() ; i ++){
      for(int j = i + 1; j < array.size() ;j++)
      {
      int first = array[i];
      int second = array[j];
      //Do someting.
      }
      }





      share|improve this answer
























        0












        0








        0






        Do something like this.



        for(int i = 0 ; i < array.size() ; i ++){
        for(int j = i + 1; j < array.size() ;j++)
        {
        int first = array[i];
        int second = array[j];
        //Do someting.
        }
        }





        share|improve this answer












        Do something like this.



        for(int i = 0 ; i < array.size() ; i ++){
        for(int j = i + 1; j < array.size() ;j++)
        {
        int first = array[i];
        int second = array[j];
        //Do someting.
        }
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 10:50









        Bruce Chen

        944




        944






























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