“TypeError: 'int' object is not iterable” When making a small words list

I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.

def shortWords(aList):

    total = 0

    aList = 0

    for index in aList:

        index = str(index)

        if len(aList([index])) <= 3:

           total = aList.append([index]) 

    return total



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

1

aList = 0 seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28

add a comment |

I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.

def shortWords(aList):

    total = 0

    aList = 0

    for index in aList:

        index = str(index)

        if len(aList([index])) <= 3:

           total = aList.append([index]) 

    return total



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

1

aList = 0 seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28

add a comment |

I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.

def shortWords(aList):

    total = 0

    aList = 0

    for index in aList:

        index = str(index)

        if len(aList([index])) <= 3:

           total = aList.append([index]) 

    return total



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.

def shortWords(aList):

    total = 0

    aList = 0

    for index in aList:

        index = str(index)

        if len(aList([index])) <= 3:

           total = aList.append([index]) 

    return total



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

python

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

edited Nov 13 '18 at 23:30

Terry Jan Reedy

11.9k12140

asked Nov 13 '18 at 0:47

APCSP

asked Nov 13 '18 at 0:47

APCSP

asked Nov 13 '18 at 0:47

APCSP

1

aList = 0 seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28

add a comment |

1

aList = 0 seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28

aList = 0 seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28

add a comment |

2 Answers
2

active

oldest

votes

You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.

It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.

def shortWords(aList):

    words =  # Declared to store any short words found

    for word in aList:

        if len(word) <= 3:

           words.append(word) # Short word found, appending to list

    return words # Return results



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

# ['my', 'is']

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

add a comment |

Because you have a:

aList = 0

In the second line of the code!

Which overwrites the actual list.

So should remove it, then it will work, so would be:

def shortWords(aList):

    words = 

    for i in aList:

        if len(i) <= 3:

           words.append(i) 

    return words

Note that it aList doesn't contain the indexes, but the values already, remove few steps

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.

It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.

def shortWords(aList):

    words =  # Declared to store any short words found

    for word in aList:

        if len(word) <= 3:

           words.append(word) # Short word found, appending to list

    return words # Return results



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

# ['my', 'is']

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

add a comment |

You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.

It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.

def shortWords(aList):

    words =  # Declared to store any short words found

    for word in aList:

        if len(word) <= 3:

           words.append(word) # Short word found, appending to list

    return words # Return results



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

# ['my', 'is']

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

add a comment |

You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.

It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.

def shortWords(aList):

    words =  # Declared to store any short words found

    for word in aList:

        if len(word) <= 3:

           words.append(word) # Short word found, appending to list

    return words # Return results



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

# ['my', 'is']

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.

It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.

def shortWords(aList):

    words =  # Declared to store any short words found

    for word in aList:

        if len(word) <= 3:

           words.append(word) # Short word found, appending to list

    return words # Return results



print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))

# ['my', 'is']

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

edited Nov 13 '18 at 1:33

answered Nov 13 '18 at 0:51

boonwj

2169

answered Nov 13 '18 at 0:51

boonwj

2169

answered Nov 13 '18 at 0:51

boonwj

2169

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

add a comment |

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02

whoops sorry, that was a mistake. That was just supposed to be words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06

How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15

I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34

add a comment |

Because you have a:

aList = 0

In the second line of the code!

Which overwrites the actual list.

So should remove it, then it will work, so would be:

def shortWords(aList):

    words = 

    for i in aList:

        if len(i) <= 3:

           words.append(i) 

    return words

Note that it aList doesn't contain the indexes, but the values already, remove few steps

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

add a comment |

Because you have a:

aList = 0

In the second line of the code!

Which overwrites the actual list.

So should remove it, then it will work, so would be:

def shortWords(aList):

    words = 

    for i in aList:

        if len(i) <= 3:

           words.append(i) 

    return words

Note that it aList doesn't contain the indexes, but the values already, remove few steps

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

add a comment |

Because you have a:

aList = 0

In the second line of the code!

Which overwrites the actual list.

So should remove it, then it will work, so would be:

def shortWords(aList):

    words = 

    for i in aList:

        if len(i) <= 3:

           words.append(i) 

    return words

Note that it aList doesn't contain the indexes, but the values already, remove few steps

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

Because you have a:

aList = 0

In the second line of the code!

Which overwrites the actual list.

So should remove it, then it will work, so would be:

def shortWords(aList):

    words = 

    for i in aList:

        if len(i) <= 3:

           words.append(i) 

    return words

Note that it aList doesn't contain the indexes, but the values already, remove few steps

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

answered Nov 13 '18 at 1:10

U9-Forward

13.6k21337

add a comment |

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