“TypeError: 'int' object is not iterable” When making a small words list
I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.
def shortWords(aList):
total = 0
aList = 0
for index in aList:
index = str(index)
if len(aList([index])) <= 3:
total = aList.append([index])
return total
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
python
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
add a comment |
I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.
def shortWords(aList):
total = 0
aList = 0
for index in aList:
index = str(index)
if len(aList([index])) <= 3:
total = aList.append([index])
return total
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
python
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
1
aList = 0seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28
add a comment |
I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.
def shortWords(aList):
total = 0
aList = 0
for index in aList:
index = str(index)
if len(aList([index])) <= 3:
total = aList.append([index])
return total
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
python
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
I need to make a function using iteration to make a list of all words that are shorter than 3 letters. I keep getting some int error.
def shortWords(aList):
total = 0
aList = 0
for index in aList:
index = str(index)
if len(aList([index])) <= 3:
total = aList.append([index])
return total
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
python
python
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
edited Nov 13 '18 at 23:30
Terry Jan Reedy
11.9k12140
11.9k12140
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
asked Nov 13 '18 at 0:47
APCSPAPCSP
12
12
1
aList = 0seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28
add a comment |
1
aList = 0seems to destroy your list, it looks like irrelevant statement.
– muradm
Nov 13 '18 at 2:28
1
1
aList = 0 seems to destroy your list, it looks like irrelevant statement.– muradm
Nov 13 '18 at 2:28
aList = 0 seems to destroy your list, it looks like irrelevant statement.– muradm
Nov 13 '18 at 2:28
add a comment |
2 Answers
2
active
oldest
votes
You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.
It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.
def shortWords(aList):
words = # Declared to store any short words found
for word in aList:
if len(word) <= 3:
words.append(word) # Short word found, appending to list
return words # Return results
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
# ['my', 'is']
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to bewords. The empty brackets (words =) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
add a comment |
Because you have a:
aList = 0
In the second line of the code!
Which overwrites the actual list.
So should remove it, then it will work, so would be:
def shortWords(aList):
words =
for i in aList:
if len(i) <= 3:
words.append(i)
return words
Note that it aList doesn't contain the indexes, but the values already, remove few steps
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.
It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.
def shortWords(aList):
words = # Declared to store any short words found
for word in aList:
if len(word) <= 3:
words.append(word) # Short word found, appending to list
return words # Return results
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
# ['my', 'is']
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to bewords. The empty brackets (words =) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
add a comment |
You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.
It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.
def shortWords(aList):
words = # Declared to store any short words found
for word in aList:
if len(word) <= 3:
words.append(word) # Short word found, appending to list
return words # Return results
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
# ['my', 'is']
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to bewords. The empty brackets (words =) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
add a comment |
You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.
It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.
def shortWords(aList):
words = # Declared to store any short words found
for word in aList:
if len(word) <= 3:
words.append(word) # Short word found, appending to list
return words # Return results
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
# ['my', 'is']
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
You got TypeError: 'int' object is not iterable because you have declared aList = 0 in your function, which overwrites the parameter that is passed into it.
It seems there is some confusion on how python loops work. When iterating through a list, it will return the value and not the index. So you can use it directly.
def shortWords(aList):
words = # Declared to store any short words found
for word in aList:
if len(word) <= 3:
words.append(word) # Short word found, appending to list
return words # Return results
print(shortWords(['Hello', 'my', 'name', 'is', 'Inigo', 'Montoya']))
# ['my', 'is']
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
edited Nov 13 '18 at 1:33
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
answered Nov 13 '18 at 0:51
boonwjboonwj
2169
2169
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to bewords. The empty brackets (words =) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
add a comment |
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to bewords. The empty brackets (words =) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.
– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
Thank you! Why did you assign the words to the empty brackets? Also, why did you add the underscore between the short words?
– APCSP
Nov 13 '18 at 1:02
whoops sorry, that was a mistake. That was just supposed to be
words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.– boonwj
Nov 13 '18 at 1:06
whoops sorry, that was a mistake. That was just supposed to be
words. The empty brackets (words = ) indicates a declaration of an empty list data type. Since the output was for a list of short words, the correct data type should be declared to contain it.– boonwj
Nov 13 '18 at 1:06
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
How do we know that "words" is assigned to the new list that needs to be appended?
– APCSP
Nov 13 '18 at 1:15
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
I have modified the code snippet with comments to explain the flow
– boonwj
Nov 13 '18 at 1:34
add a comment |
Because you have a:
aList = 0
In the second line of the code!
Which overwrites the actual list.
So should remove it, then it will work, so would be:
def shortWords(aList):
words =
for i in aList:
if len(i) <= 3:
words.append(i)
return words
Note that it aList doesn't contain the indexes, but the values already, remove few steps
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
add a comment |
Because you have a:
aList = 0
In the second line of the code!
Which overwrites the actual list.
So should remove it, then it will work, so would be:
def shortWords(aList):
words =
for i in aList:
if len(i) <= 3:
words.append(i)
return words
Note that it aList doesn't contain the indexes, but the values already, remove few steps
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
add a comment |
Because you have a:
aList = 0
In the second line of the code!
Which overwrites the actual list.
So should remove it, then it will work, so would be:
def shortWords(aList):
words =
for i in aList:
if len(i) <= 3:
words.append(i)
return words
Note that it aList doesn't contain the indexes, but the values already, remove few steps
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
Because you have a:
aList = 0
In the second line of the code!
Which overwrites the actual list.
So should remove it, then it will work, so would be:
def shortWords(aList):
words =
for i in aList:
if len(i) <= 3:
words.append(i)
return words
Note that it aList doesn't contain the indexes, but the values already, remove few steps
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
answered Nov 13 '18 at 1:10
U9-ForwardU9-Forward
13.6k21337
13.6k21337
add a comment |
add a comment |
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aList = 0seems to destroy your list, it looks like irrelevant statement.– muradm
Nov 13 '18 at 2:28