How to get the xml element as a string with namespace using ElementTree in python?
I need to get the elements from xml as a string. I am trying with below xml format.
<xml>
<prot:data xmlns:prot="prot">
<product-id-template>
<prot:ProductId>PRODUCT_ID</prot:ProductId>
</product-id-template>
<product-name-template>
<prot:ProductName>PRODUCT_NAME</prot:ProductName>
</product-name-template>
<dealer-template>
<xsi:Dealer xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">DEALER</xsi:Dealer>
</dealer-template>
</prot:data>
</xml>
And I tried with below code:
from xml.etree import ElementTree as ET
def get_template(xpath, namespaces):
tree = ET.parse('cdata.xml')
elements = tree.getroot()
for element in elements.findall(xpath, namespaces=namespaces):
return element
namespace = {"prot" : "prot"}
aa = get_template(".//prot:ProductId", namespace)
print(ET.tostring(aa).decode())
Actual output:
<ns0:ProductId xmlns:ns0="prot">PRODUCT_ID</ns0:ProductId>
Expected output:
<prot:ProductId>PRODUCT_ID</prot:ProductId>
I should not remove the xmlns from the document where it presents in the document. And It has to be removed where it not presents. Example product-id-template is not containing the xmlns so it needs to be retrieved without xmlns. And dealer-template contains the xmlns so it needs to be retrieved with xmlns.
How to achieve this?
python xml elementtree
asked Nov 21 '18 at 5:25
SathishSathish
1166
add a comment |
I need to get the elements from xml as a string. I am trying with below xml format.
<xml>
<prot:data xmlns:prot="prot">
<product-id-template>
<prot:ProductId>PRODUCT_ID</prot:ProductId>
</product-id-template>
<product-name-template>
<prot:ProductName>PRODUCT_NAME</prot:ProductName>
</product-name-template>
<dealer-template>
<xsi:Dealer xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">DEALER</xsi:Dealer>
</dealer-template>
</prot:data>
</xml>
And I tried with below code:
from xml.etree import ElementTree as ET
def get_template(xpath, namespaces):
tree = ET.parse('cdata.xml')
elements = tree.getroot()
for element in elements.findall(xpath, namespaces=namespaces):
return element
namespace = {"prot" : "prot"}
aa = get_template(".//prot:ProductId", namespace)
print(ET.tostring(aa).decode())
Actual output:
<ns0:ProductId xmlns:ns0="prot">PRODUCT_ID</ns0:ProductId>
Expected output:
<prot:ProductId>PRODUCT_ID</prot:ProductId>
I should not remove the xmlns from the document where it presents in the document. And It has to be removed where it not presents. Example product-id-template is not containing the xmlns so it needs to be retrieved without xmlns. And dealer-template contains the xmlns so it needs to be retrieved with xmlns.
How to achieve this?
python xml elementtree
asked Nov 21 '18 at 5:25
SathishSathish
1166
add a comment |
I need to get the elements from xml as a string. I am trying with below xml format.
<xml>
<prot:data xmlns:prot="prot">
<product-id-template>
<prot:ProductId>PRODUCT_ID</prot:ProductId>
</product-id-template>
<product-name-template>
<prot:ProductName>PRODUCT_NAME</prot:ProductName>
</product-name-template>
<dealer-template>
<xsi:Dealer xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">DEALER</xsi:Dealer>
</dealer-template>
</prot:data>
</xml>
And I tried with below code:
from xml.etree import ElementTree as ET
def get_template(xpath, namespaces):
tree = ET.parse('cdata.xml')
elements = tree.getroot()
for element in elements.findall(xpath, namespaces=namespaces):
return element
namespace = {"prot" : "prot"}
aa = get_template(".//prot:ProductId", namespace)
print(ET.tostring(aa).decode())
Actual output:
<ns0:ProductId xmlns:ns0="prot">PRODUCT_ID</ns0:ProductId>
Expected output:
<prot:ProductId>PRODUCT_ID</prot:ProductId>
I should not remove the xmlns from the document where it presents in the document. And It has to be removed where it not presents. Example product-id-template is not containing the xmlns so it needs to be retrieved without xmlns. And dealer-template contains the xmlns so it needs to be retrieved with xmlns.
How to achieve this?
python xml elementtree
asked Nov 21 '18 at 5:25
SathishSathish
1166
I need to get the elements from xml as a string. I am trying with below xml format.
<xml>
<prot:data xmlns:prot="prot">
<product-id-template>
<prot:ProductId>PRODUCT_ID</prot:ProductId>
</product-id-template>
<product-name-template>
<prot:ProductName>PRODUCT_NAME</prot:ProductName>
</product-name-template>
<dealer-template>
<xsi:Dealer xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">DEALER</xsi:Dealer>
</dealer-template>
</prot:data>
</xml>
And I tried with below code:
from xml.etree import ElementTree as ET
def get_template(xpath, namespaces):
tree = ET.parse('cdata.xml')
elements = tree.getroot()
for element in elements.findall(xpath, namespaces=namespaces):
return element
namespace = {"prot" : "prot"}
aa = get_template(".//prot:ProductId", namespace)
print(ET.tostring(aa).decode())
Actual output:
<ns0:ProductId xmlns:ns0="prot">PRODUCT_ID</ns0:ProductId>
Expected output:
<prot:ProductId>PRODUCT_ID</prot:ProductId>
I should not remove the xmlns from the document where it presents in the document. And It has to be removed where it not presents. Example product-id-template is not containing the xmlns so it needs to be retrieved without xmlns. And dealer-template contains the xmlns so it needs to be retrieved with xmlns.
How to achieve this?
python xml elementtree
python xml elementtree
asked Nov 21 '18 at 5:25
SathishSathish
1166
asked Nov 21 '18 at 5:25
SathishSathish
1166
edited Nov 21 '18 at 11:56
Sathish
asked Nov 21 '18 at 5:25
SathishSathish
1166
asked Nov 21 '18 at 5:25
SathishSathish
1166
asked Nov 21 '18 at 5:25
SathishSathish
1166
1166
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can remove xmlns with regex.
import re
# ...
with_ns = ET.tostring(aa).decode()
no_ns = re.sub(' xmlns(:w+)?="[^"]+"', '', with_ns)
print(no_ns)
UPDATE: You can do a very wild thing. Although I can't recommend it, because I'm not a Python expert.
I just checked the source code and found that I can do this hack:
def my_serialize_xml(write, elem, qnames, namespaces,
short_empty_elements, **kwargs):
ET._serialize_xml(write, elem, qnames,
None, short_empty_elements, **kwargs)
ET._serialize["xml"] = my_serialize_xml
I just defined my_serialize_xml, which calls ElementTree._serialize_xml with namespaces=None. And then, in dictionary ElementTree._serialize, I changed value for key "xml" to my_serialize_xml. So when you call ElementTree.tostring, it will use my_serialize_xml.
If you want to try it, just place the code(above) after from xml.etree import ElementTree as ET (but before using the ET).
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it withElementTree.tostring(), but seems it is not possible. Maybelxmlcan do it. I'll let you know if I find better solution.
– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways withxml.etree. If you can uselxml, you can find similar q&a how to do it.
– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
add a comment |
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1 Answer
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1 Answer
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You can remove xmlns with regex.
import re
# ...
with_ns = ET.tostring(aa).decode()
no_ns = re.sub(' xmlns(:w+)?="[^"]+"', '', with_ns)
print(no_ns)
UPDATE: You can do a very wild thing. Although I can't recommend it, because I'm not a Python expert.
I just checked the source code and found that I can do this hack:
def my_serialize_xml(write, elem, qnames, namespaces,
short_empty_elements, **kwargs):
ET._serialize_xml(write, elem, qnames,
None, short_empty_elements, **kwargs)
ET._serialize["xml"] = my_serialize_xml
I just defined my_serialize_xml, which calls ElementTree._serialize_xml with namespaces=None. And then, in dictionary ElementTree._serialize, I changed value for key "xml" to my_serialize_xml. So when you call ElementTree.tostring, it will use my_serialize_xml.
If you want to try it, just place the code(above) after from xml.etree import ElementTree as ET (but before using the ET).
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it withElementTree.tostring(), but seems it is not possible. Maybelxmlcan do it. I'll let you know if I find better solution.
– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways withxml.etree. If you can uselxml, you can find similar q&a how to do it.
– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
add a comment |
You can remove xmlns with regex.
import re
# ...
with_ns = ET.tostring(aa).decode()
no_ns = re.sub(' xmlns(:w+)?="[^"]+"', '', with_ns)
print(no_ns)
UPDATE: You can do a very wild thing. Although I can't recommend it, because I'm not a Python expert.
I just checked the source code and found that I can do this hack:
def my_serialize_xml(write, elem, qnames, namespaces,
short_empty_elements, **kwargs):
ET._serialize_xml(write, elem, qnames,
None, short_empty_elements, **kwargs)
ET._serialize["xml"] = my_serialize_xml
I just defined my_serialize_xml, which calls ElementTree._serialize_xml with namespaces=None. And then, in dictionary ElementTree._serialize, I changed value for key "xml" to my_serialize_xml. So when you call ElementTree.tostring, it will use my_serialize_xml.
If you want to try it, just place the code(above) after from xml.etree import ElementTree as ET (but before using the ET).
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it withElementTree.tostring(), but seems it is not possible. Maybelxmlcan do it. I'll let you know if I find better solution.
– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways withxml.etree. If you can uselxml, you can find similar q&a how to do it.
– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
add a comment |
You can remove xmlns with regex.
import re
# ...
with_ns = ET.tostring(aa).decode()
no_ns = re.sub(' xmlns(:w+)?="[^"]+"', '', with_ns)
print(no_ns)
UPDATE: You can do a very wild thing. Although I can't recommend it, because I'm not a Python expert.
I just checked the source code and found that I can do this hack:
def my_serialize_xml(write, elem, qnames, namespaces,
short_empty_elements, **kwargs):
ET._serialize_xml(write, elem, qnames,
None, short_empty_elements, **kwargs)
ET._serialize["xml"] = my_serialize_xml
I just defined my_serialize_xml, which calls ElementTree._serialize_xml with namespaces=None. And then, in dictionary ElementTree._serialize, I changed value for key "xml" to my_serialize_xml. So when you call ElementTree.tostring, it will use my_serialize_xml.
If you want to try it, just place the code(above) after from xml.etree import ElementTree as ET (but before using the ET).
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
You can remove xmlns with regex.
import re
# ...
with_ns = ET.tostring(aa).decode()
no_ns = re.sub(' xmlns(:w+)?="[^"]+"', '', with_ns)
print(no_ns)
UPDATE: You can do a very wild thing. Although I can't recommend it, because I'm not a Python expert.
I just checked the source code and found that I can do this hack:
def my_serialize_xml(write, elem, qnames, namespaces,
short_empty_elements, **kwargs):
ET._serialize_xml(write, elem, qnames,
None, short_empty_elements, **kwargs)
ET._serialize["xml"] = my_serialize_xml
I just defined my_serialize_xml, which calls ElementTree._serialize_xml with namespaces=None. And then, in dictionary ElementTree._serialize, I changed value for key "xml" to my_serialize_xml. So when you call ElementTree.tostring, it will use my_serialize_xml.
If you want to try it, just place the code(above) after from xml.etree import ElementTree as ET (but before using the ET).
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
edited Nov 21 '18 at 10:29
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
answered Nov 21 '18 at 8:34
Mike KaskunMike Kaskun
8122517
8122517
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it withElementTree.tostring(), but seems it is not possible. Maybelxmlcan do it. I'll let you know if I find better solution.
– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways withxml.etree. If you can uselxml, you can find similar q&a how to do it.
– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
add a comment |
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it withElementTree.tostring(), but seems it is not possible. Maybelxmlcan do it. I'll let you know if I find better solution.
– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways withxml.etree. If you can uselxml, you can find similar q&a how to do it.
– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
Can we achieve this without using regex? Because in some case element may have different xmlns in that time also it will remove right. I need to retrieve as such how the xml document contains the data @Mike Kaskun
– Sathish
Nov 21 '18 at 8:57
I tried to do it with
ElementTree.tostring(), but seems it is not possible. Maybe lxml can do it. I'll let you know if I find better solution.– Mike Kaskun
Nov 21 '18 at 9:19
I tried to do it with
ElementTree.tostring(), but seems it is not possible. Maybe lxml can do it. I'll let you know if I find better solution.– Mike Kaskun
Nov 21 '18 at 9:19
I've updated the answer, can't find other ways with
xml.etree. If you can use lxml, you can find similar q&a how to do it.– Mike Kaskun
Nov 21 '18 at 10:39
I've updated the answer, can't find other ways with
xml.etree. If you can use lxml, you can find similar q&a how to do it.– Mike Kaskun
Nov 21 '18 at 10:39
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
Thanks @Mike Kaskun. But it removes the xmlns in all the place. I should not remove the xmlns from the document where it presents in the document. Above question I added the dealer-template block. There I need the xmlns and it should not be removed from there. And It has to be removed where it not presents
– Sathish
Nov 21 '18 at 11:02
1
1
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
Ok, I understand. I'll try something else later. Also, add your explanation to question, maybe someone else will help.
– Mike Kaskun
Nov 21 '18 at 11:44
add a comment |
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