Do interpreted languages use a symbol table at runtime?
I understand that a symbol table is used only at compile-time for semantic analysis in statically typed languages, but how are they used for interpreted languages that execute byte code? Is the symbol table ever used during runtime for interpreted languages such as Python or JavaScript?
compiler-construction programming-languages interpreter
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
add a comment |
I understand that a symbol table is used only at compile-time for semantic analysis in statically typed languages, but how are they used for interpreted languages that execute byte code? Is the symbol table ever used during runtime for interpreted languages such as Python or JavaScript?
compiler-construction programming-languages interpreter
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
add a comment |
I understand that a symbol table is used only at compile-time for semantic analysis in statically typed languages, but how are they used for interpreted languages that execute byte code? Is the symbol table ever used during runtime for interpreted languages such as Python or JavaScript?
compiler-construction programming-languages interpreter
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
I understand that a symbol table is used only at compile-time for semantic analysis in statically typed languages, but how are they used for interpreted languages that execute byte code? Is the symbol table ever used during runtime for interpreted languages such as Python or JavaScript?
compiler-construction programming-languages interpreter
compiler-construction programming-languages interpreter
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
asked Nov 21 '18 at 5:13
N. ParikhN. Parikh
505
505
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Well, and identifier must be mapped to a place where the variable is stored. If it doesn't exist an entry is created. At least simple interpreters work that way.
You could call that a symbol table, but it is dynamic and one of the byproducts of the interpretation, not a compilation process.
More complex scripting languages like you name have to integrate this with their garbage collection.
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53405625%2fdo-interpreted-languages-use-a-symbol-table-at-runtime%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Well, and identifier must be mapped to a place where the variable is stored. If it doesn't exist an entry is created. At least simple interpreters work that way.
You could call that a symbol table, but it is dynamic and one of the byproducts of the interpretation, not a compilation process.
More complex scripting languages like you name have to integrate this with their garbage collection.
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
add a comment |
Well, and identifier must be mapped to a place where the variable is stored. If it doesn't exist an entry is created. At least simple interpreters work that way.
You could call that a symbol table, but it is dynamic and one of the byproducts of the interpretation, not a compilation process.
More complex scripting languages like you name have to integrate this with their garbage collection.
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
add a comment |
Well, and identifier must be mapped to a place where the variable is stored. If it doesn't exist an entry is created. At least simple interpreters work that way.
You could call that a symbol table, but it is dynamic and one of the byproducts of the interpretation, not a compilation process.
More complex scripting languages like you name have to integrate this with their garbage collection.
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
Well, and identifier must be mapped to a place where the variable is stored. If it doesn't exist an entry is created. At least simple interpreters work that way.
You could call that a symbol table, but it is dynamic and one of the byproducts of the interpretation, not a compilation process.
More complex scripting languages like you name have to integrate this with their garbage collection.
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
answered Nov 21 '18 at 9:23
Marco van de VoortMarco van de Voort
22.2k54180
22.2k54180
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53405625%2fdo-interpreted-languages-use-a-symbol-table-at-runtime%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
