PHP How to give block of code a parent node
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I have this html structure;
and I need to remove everything after
<span class="Title_Blue">
or, at least, put the block inside a div. (Then I can manipulate it.)
Is there anyway I can do it with xpath?
I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.
Thanks!!
<body>
<div class="article_text">
<div id="text">
<p class="paragraph">
<strong> [text] </strong>
</p>
<div>
<strong> [text] </strong>
</div>
<strong>
<br> [Title] <br>
</strong>
<div style="text-align: justify;">
<br> [text]
</div>
<div style="text-align: justify;">
<br> [text]
</div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
</div>
</div>
</body>
EDITED
I tried this:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"]');
foreach ($contents as $content) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'DELETE_ME');
$content->parentNode->replaceChild($div, $content);
$div->appendChild($content);
}
EDITED 2
Was able to solve using this code:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');
foreach ($contents as $content) {
$content->parentNode->removeChild($content);
}
Thanks to Andersson!
php xpath
add a comment |
I have this html structure;
and I need to remove everything after
<span class="Title_Blue">
or, at least, put the block inside a div. (Then I can manipulate it.)
Is there anyway I can do it with xpath?
I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.
Thanks!!
<body>
<div class="article_text">
<div id="text">
<p class="paragraph">
<strong> [text] </strong>
</p>
<div>
<strong> [text] </strong>
</div>
<strong>
<br> [Title] <br>
</strong>
<div style="text-align: justify;">
<br> [text]
</div>
<div style="text-align: justify;">
<br> [text]
</div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
</div>
</div>
</body>
EDITED
I tried this:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"]');
foreach ($contents as $content) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'DELETE_ME');
$content->parentNode->replaceChild($div, $content);
$div->appendChild($content);
}
EDITED 2
Was able to solve using this code:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');
foreach ($contents as $content) {
$content->parentNode->removeChild($content);
}
Thanks to Andersson!
php xpath
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
1
You cannot use XPath to remove everything after, but you can use it to select everything after://span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18
add a comment |
I have this html structure;
and I need to remove everything after
<span class="Title_Blue">
or, at least, put the block inside a div. (Then I can manipulate it.)
Is there anyway I can do it with xpath?
I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.
Thanks!!
<body>
<div class="article_text">
<div id="text">
<p class="paragraph">
<strong> [text] </strong>
</p>
<div>
<strong> [text] </strong>
</div>
<strong>
<br> [Title] <br>
</strong>
<div style="text-align: justify;">
<br> [text]
</div>
<div style="text-align: justify;">
<br> [text]
</div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
</div>
</div>
</body>
EDITED
I tried this:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"]');
foreach ($contents as $content) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'DELETE_ME');
$content->parentNode->replaceChild($div, $content);
$div->appendChild($content);
}
EDITED 2
Was able to solve using this code:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');
foreach ($contents as $content) {
$content->parentNode->removeChild($content);
}
Thanks to Andersson!
php xpath
I have this html structure;
and I need to remove everything after
<span class="Title_Blue">
or, at least, put the block inside a div. (Then I can manipulate it.)
Is there anyway I can do it with xpath?
I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.
Thanks!!
<body>
<div class="article_text">
<div id="text">
<p class="paragraph">
<strong> [text] </strong>
</p>
<div>
<strong> [text] </strong>
</div>
<strong>
<br> [Title] <br>
</strong>
<div style="text-align: justify;">
<br> [text]
</div>
<div style="text-align: justify;">
<br> [text]
</div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<span class="Title_Blue"> [text] </span>
<br>
<p> ... </p>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
<div style="text-align: justify;"> [text] </div>
</div>
</div>
</body>
EDITED
I tried this:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"]');
foreach ($contents as $content) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'DELETE_ME');
$content->parentNode->replaceChild($div, $content);
$div->appendChild($content);
}
EDITED 2
Was able to solve using this code:
$html = $data
$doc = new DOMDocument();
@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');
foreach ($contents as $content) {
$content->parentNode->removeChild($content);
}
Thanks to Andersson!
php xpath
php xpath
edited Nov 23 '18 at 17:27
Migu3litto
asked Nov 23 '18 at 17:02
Migu3littoMigu3litto
346
346
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
1
You cannot use XPath to remove everything after, but you can use it to select everything after://span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18
add a comment |
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
1
You cannot use XPath to remove everything after, but you can use it to select everything after://span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
1
1
You cannot use XPath to remove everything after, but you can use it to select everything after:
//span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
You cannot use XPath to remove everything after, but you can use it to select everything after:
//span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18
add a comment |
1 Answer
1
active
oldest
votes
If you need to select everything after span
including that span
, try
//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450558%2fphp-how-to-give-block-of-code-a-parent-node%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you need to select everything after span
including that span
, try
//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*
add a comment |
If you need to select everything after span
including that span
, try
//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*
add a comment |
If you need to select everything after span
including that span
, try
//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*
If you need to select everything after span
including that span
, try
//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*
answered Nov 23 '18 at 17:35
AnderssonAndersson
39.1k113669
39.1k113669
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450558%2fphp-how-to-give-block-of-code-a-parent-node%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
did you try anyting?
– Madhur Sharma
Nov 23 '18 at 17:03
1
You cannot use XPath to remove everything after, but you can use it to select everything after:
//span[@class="Title_Blue"]/following-sibling::*
– Andersson
Nov 23 '18 at 17:11
Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"
– Migu3litto
Nov 23 '18 at 17:18