PHP How to give block of code a parent node





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







1















I have this html structure;
and I need to remove everything after



<span class="Title_Blue">


or, at least, put the block inside a div. (Then I can manipulate it.)



Is there anyway I can do it with xpath?



I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.



Thanks!!



<body>

<div class="article_text">

    <div id="text">



        <p class="paragraph">

            <strong> [text] </strong>

        </p>

        <div>

            <strong> [text] </strong>

        </div>

        <strong>

            <br> [Title] <br>

        </strong>

        <div style="text-align: justify;">

            <br> [text]

        </div>

        <div style="text-align: justify;">

            <br> [text]

        </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



    </div>

</div>

</body>


EDITED



I tried this:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"]');

foreach ($contents as $content) {

    $div = $doc->createElement('div');

    $div->setAttribute('class', 'DELETE_ME');

    $content->parentNode->replaceChild($div, $content);

    $div->appendChild($content);

}


EDITED 2



Was able to solve using this code:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');

foreach ($contents as $content) {

    $content->parentNode->removeChild($content);

}


Thanks to Andersson!






php xpath







share|improve this question

























  • did you try anyting?

    – Madhur Sharma
    Nov 23 '18 at 17:03






  • 1





    You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

    – Andersson
    Nov 23 '18 at 17:11











  • Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

    – Migu3litto
    Nov 23 '18 at 17:18




















1















I have this html structure;
and I need to remove everything after



<span class="Title_Blue">


or, at least, put the block inside a div. (Then I can manipulate it.)



Is there anyway I can do it with xpath?



I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.



Thanks!!



<body>

<div class="article_text">

    <div id="text">



        <p class="paragraph">

            <strong> [text] </strong>

        </p>

        <div>

            <strong> [text] </strong>

        </div>

        <strong>

            <br> [Title] <br>

        </strong>

        <div style="text-align: justify;">

            <br> [text]

        </div>

        <div style="text-align: justify;">

            <br> [text]

        </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



    </div>

</div>

</body>


EDITED



I tried this:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"]');

foreach ($contents as $content) {

    $div = $doc->createElement('div');

    $div->setAttribute('class', 'DELETE_ME');

    $content->parentNode->replaceChild($div, $content);

    $div->appendChild($content);

}


EDITED 2



Was able to solve using this code:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');

foreach ($contents as $content) {

    $content->parentNode->removeChild($content);

}


Thanks to Andersson!






php xpath







share|improve this question

























  • did you try anyting?

    – Madhur Sharma
    Nov 23 '18 at 17:03






  • 1





    You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

    – Andersson
    Nov 23 '18 at 17:11











  • Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

    – Migu3litto
    Nov 23 '18 at 17:18
















1












1








1








I have this html structure;
and I need to remove everything after



<span class="Title_Blue">


or, at least, put the block inside a div. (Then I can manipulate it.)



Is there anyway I can do it with xpath?



I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.



Thanks!!



<body>

<div class="article_text">

    <div id="text">



        <p class="paragraph">

            <strong> [text] </strong>

        </p>

        <div>

            <strong> [text] </strong>

        </div>

        <strong>

            <br> [Title] <br>

        </strong>

        <div style="text-align: justify;">

            <br> [text]

        </div>

        <div style="text-align: justify;">

            <br> [text]

        </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



    </div>

</div>

</body>


EDITED



I tried this:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"]');

foreach ($contents as $content) {

    $div = $doc->createElement('div');

    $div->setAttribute('class', 'DELETE_ME');

    $content->parentNode->replaceChild($div, $content);

    $div->appendChild($content);

}


EDITED 2



Was able to solve using this code:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');

foreach ($contents as $content) {

    $content->parentNode->removeChild($content);

}


Thanks to Andersson!






php xpath







share|improve this question
















I have this html structure;
and I need to remove everything after



<span class="Title_Blue">


or, at least, put the block inside a div. (Then I can manipulate it.)



Is there anyway I can do it with xpath?



I can easily put a tag inside a div, but the problem here is that the code I want to embrace into a div is all at the same level.



Thanks!!



<body>

<div class="article_text">

    <div id="text">



        <p class="paragraph">

            <strong> [text] </strong>

        </p>

        <div>

            <strong> [text] </strong>

        </div>

        <strong>

            <br> [Title] <br>

        </strong>

        <div style="text-align: justify;">

            <br> [text]

        </div>

        <div style="text-align: justify;">

            <br> [text]

        </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



        <span class="Title_Blue"> [text] </span>

        <br>

        <p> ... </p>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>

        <div style="text-align: justify;"> [text] </div>



    </div>

</div>

</body>


EDITED



I tried this:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"]');

foreach ($contents as $content) {

    $div = $doc->createElement('div');

    $div->setAttribute('class', 'DELETE_ME');

    $content->parentNode->replaceChild($div, $content);

    $div->appendChild($content);

}


EDITED 2



Was able to solve using this code:



$html = $data

$doc = new DOMDocument();

@$doc->loadHTML('<?xml encoding="UTF-8">' . $html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$contents = $xpath->query('//*[@class="Title_Blue"] | //*[@class="Title_Blue"]/following-sibling::*');

foreach ($contents as $content) {

    $content->parentNode->removeChild($content);

}


Thanks to Andersson!






php xpath




php xpath






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 17:27







Migu3litto

















asked Nov 23 '18 at 17:02









Migu3littoMigu3litto

346




346













  • did you try anyting?

    – Madhur Sharma
    Nov 23 '18 at 17:03






  • 1





    You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

    – Andersson
    Nov 23 '18 at 17:11











  • Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

    – Migu3litto
    Nov 23 '18 at 17:18





















  • did you try anyting?

    – Madhur Sharma
    Nov 23 '18 at 17:03






  • 1





    You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

    – Andersson
    Nov 23 '18 at 17:11











  • Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

    – Migu3litto
    Nov 23 '18 at 17:18



















did you try anyting?

– Madhur Sharma
Nov 23 '18 at 17:03





did you try anyting?

– Madhur Sharma
Nov 23 '18 at 17:03




1




1





You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

– Andersson
Nov 23 '18 at 17:11





You cannot use XPath to remove everything after, but you can use it to select everything after: //span[@class="Title_Blue"]/following-sibling::*

– Andersson
Nov 23 '18 at 17:11













Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

– Migu3litto
Nov 23 '18 at 17:18







Yes, it works! Thank you! Anyway I can include the original tag? Because it deletes everything "after". //*[@class="Title_Blue"]/following-sibling::* Maybe "and"

– Migu3litto
Nov 23 '18 at 17:18














1 Answer
1






active

oldest

votes


















1














If you need to select everything after span including that span, try



//span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*





share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450558%2fphp-how-to-give-block-of-code-a-parent-node%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    If you need to select everything after span including that span, try



    //span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*





    share|improve this answer




























      1














      If you need to select everything after span including that span, try



      //span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*





      share|improve this answer


























        1












        1








        1







        If you need to select everything after span including that span, try



        //span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*





        share|improve this answer













        If you need to select everything after span including that span, try



        //span[@class="Title_Blue"]/preceding-sibling::*[1]/following-sibling::*






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 '18 at 17:35









        AnderssonAndersson

        39.1k113669




        39.1k113669
































            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450558%2fphp-how-to-give-block-of-code-a-parent-node%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            這個網誌中的熱門文章

            Tangent Lines Diagram Along Smooth Curve

            圖片
            7 1 I am trying to replicate a diagram and have a minimal example. I don't know how to add additional tangents between the specified points and preserve smoothness. documentclass{article} usepackage{tikz} usetikzlibrary{calc,intersections} begin{document} begin{tikzpicture} % Axes draw [->, name path=x] (-1,0) -- (11,0) node [right] {$x$}; draw [->] (0,-1) -- (0,6) node [above] {$y$}; % Origin node at (0,0) [below left] {$0$}; % Points coordinate (start) at (1,-0.8); coordinate (c1) at (3,3); coordinate (c2) at (5.5,1.5); coordinate (c3) at (8,4); coordinate (end) at (10.5,-0.8); % show the points foreach n in {start,c1,c2,c3,end} fill [black] (n) circle (2pt) node [below] {}; % join the coordinates draw [thick,name path=curve] (start) to[out=70,in=180] (c1) to[out=0,in=180]
            閱讀完整內容

            Yusuf al-Mu'taman ibn Hud

            圖片
            Main article: Taifa of Zaragoza Al-Mu'taman Ruler of Zaragoza Reign 1081–1085 Predecessor Ahmad al-Muqtadir Successor Al-Mustain II Born Zaragoza Died 1085 Full name Yusuf ibn Ahmad al-Mu'taman ibn Hūd House Banu Hud Yusuf ibn Ahmad al-Mu'taman ibn Hūd (Arabic: المؤتمن بالله يوسف إبن أحمد إبن هود ‎, al-Mutaman bi l-Lah , died c. 1085) was the third king of the Banu Hud dynasty who ruled over the Taifa of Zaragoza from 1081 to 1085. Yusuf al-Mutaman reigned during the height of power of Muslim Zaragoza , following the thriving period of his father Ahmad al-Muqtadir. He continued his father's efforts and created around him a court of intellectuals, living in the beautiful palace of Aljafería, nicknamed as "the palace of joy". Al-Mu'taman was also a scholarly king and a patron of science, philosophy and arts. As an example of a wise king, he knew astrology, philosophy, and especially mathematics, a discipline in which
            閱讀完整內容

            Zucchini

            圖片
            This article is about the vegetable. For other uses, see Zucchini (disambiguation). Zucchini (courgette) A striped and a uniform color zucchini Genus Cucurbita Species Cucurbita pepo Origin 19th century northern Italy The zucchini ( / z uː ˈ k iː n i / , American English) or courgette ( / k ʊər ˈ ʒ ɛ t / , British English) is a summer squash which can reach nearly 1 metre (100 cm; 39 in) in length, but is usually harvested when still immature at about 15 to 25 cm (6 to 10 in). [1] A zucchini is a thin-skinned cultivar of what in Britain and Ireland is referred to as a marrow. [2] [3] In South Africa, a zucchini is known as a baby marrow. Along with certain other squashes and pumpkins, the zucchini belongs to the species Cucurbita pepo . It can be dark or light green. A related hybrid, the golden zucchini, is a deep yellow or orange color. [4] In a culinary context, the zucchini is treated as a vegetable; it is usually cooked and presented as a savory dish o
            閱讀完整內容