Sending AJAX post request to PHP
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0
So here is my AJAX code using JQuery:
$('#button-upload').on('click', function(){
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
}
});
}
});
The request isn't registered in the network.
Secondly, I'm not sure how can I collect this data with PHP using $_POST.
javascript php jquery ajax
edited Nov 23 '18 at 17:29
halfer
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
add a comment |
0
So here is my AJAX code using JQuery:
$('#button-upload').on('click', function(){
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
}
});
}
});
The request isn't registered in the network.
Secondly, I'm not sure how can I collect this data with PHP using $_POST.
javascript php jquery ajax
edited Nov 23 '18 at 17:29
halfer
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
1
Are you sure theif()is true?
– charlietfl
Nov 18 '18 at 14:47
add a comment |
0
0
0
So here is my AJAX code using JQuery:
$('#button-upload').on('click', function(){
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
}
});
}
});
The request isn't registered in the network.
Secondly, I'm not sure how can I collect this data with PHP using $_POST.
javascript php jquery ajax
edited Nov 23 '18 at 17:29
halfer
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
So here is my AJAX code using JQuery:
$('#button-upload').on('click', function(){
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
}
});
}
});
The request isn't registered in the network.
Secondly, I'm not sure how can I collect this data with PHP using $_POST.
javascript php jquery ajax
javascript php jquery ajax
edited Nov 23 '18 at 17:29
halfer
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
edited Nov 23 '18 at 17:29
halfer
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
edited Nov 23 '18 at 17:29
halfer
14.8k759117
edited Nov 23 '18 at 17:29
halfer
14.8k759117
edited Nov 23 '18 at 17:29
halfer
14.8k759117
14.8k759117
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
asked Nov 18 '18 at 13:35
TheProphetTheProphet
196
196
1
Are you sure theif()is true?
– charlietfl
Nov 18 '18 at 14:47
add a comment |
1
Are you sure theif()is true?
– charlietfl
Nov 18 '18 at 14:47
1
1
Are you sure the
if() is true?– charlietfl
Nov 18 '18 at 14:47
Are you sure the
if() is true?– charlietfl
Nov 18 '18 at 14:47
add a comment |
1 Answer
1
active
oldest
votes
2
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome toolchrome://net-internals/#events
– user9741470
Nov 18 '18 at 15:18
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome toolchrome://net-internals/#events
– user9741470
Nov 18 '18 at 15:18
add a comment |
2
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome toolchrome://net-internals/#events
– user9741470
Nov 18 '18 at 15:18
add a comment |
2
2
2
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>
edited Nov 18 '18 at 14:49
answered Nov 18 '18 at 13:43
user9741470
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome toolchrome://net-internals/#events
– user9741470
Nov 18 '18 at 15:18
add a comment |
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome toolchrome://net-internals/#events
– user9741470
Nov 18 '18 at 15:18
1
1
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
thank you, but still my biggest problem right now is that the AJAX request isn't registered in the network (inside the devTool)
– TheProphet
Nov 18 '18 at 14:36
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
Have you tried to send an echo as response from the script?Is your php console log any error?
– user9741470
Nov 18 '18 at 14:46
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
This request is fired after pressing the "send" button, hence the $('#button-upload')
– TheProphet
Nov 18 '18 at 15:02
Try to inspect your app code using this chrome tool
chrome://net-internals/#events– user9741470
Nov 18 '18 at 15:18
Try to inspect your app code using this chrome tool
chrome://net-internals/#events– user9741470
Nov 18 '18 at 15:18
add a comment |
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1
Are you sure the
if()is true?– charlietfl
Nov 18 '18 at 14:47