Reaching to the effective performance level of the query





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I have this below oracle query Please advise me how can I make it more efficient so that it performance will improve , let me know please if i i have miss anything in it as I am a new one ,any early help would be much appreciated



below is the Plan for the query , Please advise how can i improve it



Plan hash value: 44516869

---------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1099 | 39564 | 3770 (1)| 00:00:46 |
|* 1 | HASH JOIN | | 1099 | 39564 | 3770 (1)| 00:00:46 |
| 2 | NESTED LOOPS | | | | | |
| 3 | NESTED LOOPS | | 1095 | 32850 | 3345 (1)| 00:00:41 |
| 4 | TABLE ACCESS FULL | BUSINESS_CONTACTS | 1666 | 14994 | 11 (0)| 00:00:01 |
|* 5 | INDEX UNIQUE SCAN | PERSON_PK | 1 | |









share|improve this question




















  • 1





    Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

    – Clockwork-Muse
    Nov 23 '18 at 18:23











  • @Clockwork-Muse i agree

    – nikhil sugandh
    Nov 23 '18 at 18:24











  • Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

    – eaolson
    Nov 23 '18 at 21:09











  • What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

    – William Robertson
    Nov 24 '18 at 10:09


















0















I have this below oracle query Please advise me how can I make it more efficient so that it performance will improve , let me know please if i i have miss anything in it as I am a new one ,any early help would be much appreciated



below is the Plan for the query , Please advise how can i improve it



Plan hash value: 44516869

---------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1099 | 39564 | 3770 (1)| 00:00:46 |
|* 1 | HASH JOIN | | 1099 | 39564 | 3770 (1)| 00:00:46 |
| 2 | NESTED LOOPS | | | | | |
| 3 | NESTED LOOPS | | 1095 | 32850 | 3345 (1)| 00:00:41 |
| 4 | TABLE ACCESS FULL | BUSINESS_CONTACTS | 1666 | 14994 | 11 (0)| 00:00:01 |
|* 5 | INDEX UNIQUE SCAN | PERSON_PK | 1 | |









share|improve this question




















  • 1





    Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

    – Clockwork-Muse
    Nov 23 '18 at 18:23











  • @Clockwork-Muse i agree

    – nikhil sugandh
    Nov 23 '18 at 18:24











  • Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

    – eaolson
    Nov 23 '18 at 21:09











  • What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

    – William Robertson
    Nov 24 '18 at 10:09














0












0








0








I have this below oracle query Please advise me how can I make it more efficient so that it performance will improve , let me know please if i i have miss anything in it as I am a new one ,any early help would be much appreciated



below is the Plan for the query , Please advise how can i improve it



Plan hash value: 44516869

---------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1099 | 39564 | 3770 (1)| 00:00:46 |
|* 1 | HASH JOIN | | 1099 | 39564 | 3770 (1)| 00:00:46 |
| 2 | NESTED LOOPS | | | | | |
| 3 | NESTED LOOPS | | 1095 | 32850 | 3345 (1)| 00:00:41 |
| 4 | TABLE ACCESS FULL | BUSINESS_CONTACTS | 1666 | 14994 | 11 (0)| 00:00:01 |
|* 5 | INDEX UNIQUE SCAN | PERSON_PK | 1 | |









share|improve this question
















I have this below oracle query Please advise me how can I make it more efficient so that it performance will improve , let me know please if i i have miss anything in it as I am a new one ,any early help would be much appreciated



below is the Plan for the query , Please advise how can i improve it



Plan hash value: 44516869

---------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1099 | 39564 | 3770 (1)| 00:00:46 |
|* 1 | HASH JOIN | | 1099 | 39564 | 3770 (1)| 00:00:46 |
| 2 | NESTED LOOPS | | | | | |
| 3 | NESTED LOOPS | | 1095 | 32850 | 3345 (1)| 00:00:41 |
| 4 | TABLE ACCESS FULL | BUSINESS_CONTACTS | 1666 | 14994 | 11 (0)| 00:00:01 |
|* 5 | INDEX UNIQUE SCAN | PERSON_PK | 1 | |






sql oracle






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 2:30







sss

















asked Nov 23 '18 at 17:28









ssssss

56111




56111








  • 1





    Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

    – Clockwork-Muse
    Nov 23 '18 at 18:23











  • @Clockwork-Muse i agree

    – nikhil sugandh
    Nov 23 '18 at 18:24











  • Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

    – eaolson
    Nov 23 '18 at 21:09











  • What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

    – William Robertson
    Nov 24 '18 at 10:09














  • 1





    Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

    – Clockwork-Muse
    Nov 23 '18 at 18:23











  • @Clockwork-Muse i agree

    – nikhil sugandh
    Nov 23 '18 at 18:24











  • Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

    – eaolson
    Nov 23 '18 at 21:09











  • What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

    – William Robertson
    Nov 24 '18 at 10:09








1




1





Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

– Clockwork-Muse
Nov 23 '18 at 18:23





Your outer Person P and inner Person PR references are pointing to the same row, which probably isn't what you want. You should be able to remove one or both of the inner references (and convert the subquery to a regular JOIN, anyways). Side note: please don't use the comma-separated FROM clause - always explicitly list out JOINs, and put (almost) all criteria into the ON clause.

– Clockwork-Muse
Nov 23 '18 at 18:23













@Clockwork-Muse i agree

– nikhil sugandh
Nov 23 '18 at 18:24





@Clockwork-Muse i agree

– nikhil sugandh
Nov 23 '18 at 18:24













Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

– eaolson
Nov 23 '18 at 21:09





Does your business_contacts table have an index on person_id? If I read this right, you're doing 1095 full table scans of business_contacts.

– eaolson
Nov 23 '18 at 21:09













What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

– William Robertson
Nov 24 '18 at 10:09





What query? Looks like you removed it and part of the execution plan in an edit, which makes the question a bit meaningless. Voting to close.

– William Robertson
Nov 24 '18 at 10:09












1 Answer
1






active

oldest

votes


















0














First, you can rewrite the query using proper, explicit, standard JOIN syntax and no subqueries. I believe the query is:



select p.business_name as Aggregator_Name, 
pc.business_name as Child_Business_Name,
bc.IDV_STATUS
from business_contacts bc join
person p
on bc.person_id = p.person_id join
person pc
on pc.parent_person_id = p.person_id;


Then for this query you want indexes on person(person_id, business_name) and person(parent_person_id, business_name).






share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450839%2freaching-to-the-effective-performance-level-of-the-query%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    First, you can rewrite the query using proper, explicit, standard JOIN syntax and no subqueries. I believe the query is:



    select p.business_name as Aggregator_Name, 
    pc.business_name as Child_Business_Name,
    bc.IDV_STATUS
    from business_contacts bc join
    person p
    on bc.person_id = p.person_id join
    person pc
    on pc.parent_person_id = p.person_id;


    Then for this query you want indexes on person(person_id, business_name) and person(parent_person_id, business_name).






    share|improve this answer




























      0














      First, you can rewrite the query using proper, explicit, standard JOIN syntax and no subqueries. I believe the query is:



      select p.business_name as Aggregator_Name, 
      pc.business_name as Child_Business_Name,
      bc.IDV_STATUS
      from business_contacts bc join
      person p
      on bc.person_id = p.person_id join
      person pc
      on pc.parent_person_id = p.person_id;


      Then for this query you want indexes on person(person_id, business_name) and person(parent_person_id, business_name).






      share|improve this answer


























        0












        0








        0







        First, you can rewrite the query using proper, explicit, standard JOIN syntax and no subqueries. I believe the query is:



        select p.business_name as Aggregator_Name, 
        pc.business_name as Child_Business_Name,
        bc.IDV_STATUS
        from business_contacts bc join
        person p
        on bc.person_id = p.person_id join
        person pc
        on pc.parent_person_id = p.person_id;


        Then for this query you want indexes on person(person_id, business_name) and person(parent_person_id, business_name).






        share|improve this answer













        First, you can rewrite the query using proper, explicit, standard JOIN syntax and no subqueries. I believe the query is:



        select p.business_name as Aggregator_Name, 
        pc.business_name as Child_Business_Name,
        bc.IDV_STATUS
        from business_contacts bc join
        person p
        on bc.person_id = p.person_id join
        person pc
        on pc.parent_person_id = p.person_id;


        Then for this query you want indexes on person(person_id, business_name) and person(parent_person_id, business_name).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 24 '18 at 1:54









        Gordon LinoffGordon Linoff

        796k37318423




        796k37318423
































            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53450839%2freaching-to-the-effective-performance-level-of-the-query%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            這個網誌中的熱門文章

            Tangent Lines Diagram Along Smooth Curve

            Yusuf al-Mu'taman ibn Hud

            Zucchini