R nonlinear regression of cumulative X and Y data
I'm trying to figure how to make a nonlinear regression of some cumulative data of X and Y values. The dataset is based on cumulative items and their respective cumulated demand. I have a plot that looks like this
based on the following observation of 5299 items, which is available here: abc.csv datafile
and I would like to fit a model that can explain it quite neatly. Given the plot, I reckon that there is a high degree of detail. Hence, I would believe that it would be possible to find a function that would explain the data with very high accuracy.
The problem is, however, that I find myself trying to fit a model with nls()
by trial and error. Furthermore, some of the functions that I've tried give me some explanation, but not in full detail. For instance
nlm <- nls(abc$Cumfreq ~c*(1-exp(-a*abc$noe))+b, data=abc,
start = list(a=4.14, b=0.21, c=0.79))
Yields me:
My question is: how do I obtain a regression with a better fit? Is there a function in R or another way of achieving this? (fingers crossed for a math genius out there)
r nls non-linear-regression nonlinear-functions cumulative-frequency
add a comment |
I'm trying to figure how to make a nonlinear regression of some cumulative data of X and Y values. The dataset is based on cumulative items and their respective cumulated demand. I have a plot that looks like this
based on the following observation of 5299 items, which is available here: abc.csv datafile
and I would like to fit a model that can explain it quite neatly. Given the plot, I reckon that there is a high degree of detail. Hence, I would believe that it would be possible to find a function that would explain the data with very high accuracy.
The problem is, however, that I find myself trying to fit a model with nls()
by trial and error. Furthermore, some of the functions that I've tried give me some explanation, but not in full detail. For instance
nlm <- nls(abc$Cumfreq ~c*(1-exp(-a*abc$noe))+b, data=abc,
start = list(a=4.14, b=0.21, c=0.79))
Yields me:
My question is: how do I obtain a regression with a better fit? Is there a function in R or another way of achieving this? (fingers crossed for a math genius out there)
r nls non-linear-regression nonlinear-functions cumulative-frequency
What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04
add a comment |
I'm trying to figure how to make a nonlinear regression of some cumulative data of X and Y values. The dataset is based on cumulative items and their respective cumulated demand. I have a plot that looks like this
based on the following observation of 5299 items, which is available here: abc.csv datafile
and I would like to fit a model that can explain it quite neatly. Given the plot, I reckon that there is a high degree of detail. Hence, I would believe that it would be possible to find a function that would explain the data with very high accuracy.
The problem is, however, that I find myself trying to fit a model with nls()
by trial and error. Furthermore, some of the functions that I've tried give me some explanation, but not in full detail. For instance
nlm <- nls(abc$Cumfreq ~c*(1-exp(-a*abc$noe))+b, data=abc,
start = list(a=4.14, b=0.21, c=0.79))
Yields me:
My question is: how do I obtain a regression with a better fit? Is there a function in R or another way of achieving this? (fingers crossed for a math genius out there)
r nls non-linear-regression nonlinear-functions cumulative-frequency
I'm trying to figure how to make a nonlinear regression of some cumulative data of X and Y values. The dataset is based on cumulative items and their respective cumulated demand. I have a plot that looks like this
based on the following observation of 5299 items, which is available here: abc.csv datafile
and I would like to fit a model that can explain it quite neatly. Given the plot, I reckon that there is a high degree of detail. Hence, I would believe that it would be possible to find a function that would explain the data with very high accuracy.
The problem is, however, that I find myself trying to fit a model with nls()
by trial and error. Furthermore, some of the functions that I've tried give me some explanation, but not in full detail. For instance
nlm <- nls(abc$Cumfreq ~c*(1-exp(-a*abc$noe))+b, data=abc,
start = list(a=4.14, b=0.21, c=0.79))
Yields me:
My question is: how do I obtain a regression with a better fit? Is there a function in R or another way of achieving this? (fingers crossed for a math genius out there)
r nls non-linear-regression nonlinear-functions cumulative-frequency
r nls non-linear-regression nonlinear-functions cumulative-frequency
edited Nov 20 '18 at 23:27
neilfws
18.2k53749
18.2k53749
asked Nov 20 '18 at 23:25
LROLRO
82
82
What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04
add a comment |
What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04
What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04
add a comment |
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What is the goal? Prediction or inference?
– Roland
Nov 21 '18 at 5:55
Sorry for the delay. I guess the goal is prediction.
– LRO
Dec 3 '18 at 22:07
Then I would fit a GAM. Don't forget to validate/crossvalidate.
– Roland
Dec 4 '18 at 7:04