The model item passed into the dictionary is of type .. but this dictionary requires a model item of type
This question and community wiki answer has been added to assist in closing out numerous unanswered questions as discussed in this meta post.
I have some code and when it executes, it throws an exception saying:
The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
What does this mean, and how do I fix it?
c# asp.net-mvc
add a comment |
This question and community wiki answer has been added to assist in closing out numerous unanswered questions as discussed in this meta post.
I have some code and when it executes, it throws an exception saying:
The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
What does this mean, and how do I fix it?
c# asp.net-mvc
I got this error when usingreturn View
instead ofreturn PartialView
so that's something to just check
– Richard Housham
Jul 5 '18 at 15:19
add a comment |
This question and community wiki answer has been added to assist in closing out numerous unanswered questions as discussed in this meta post.
I have some code and when it executes, it throws an exception saying:
The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
What does this mean, and how do I fix it?
c# asp.net-mvc
This question and community wiki answer has been added to assist in closing out numerous unanswered questions as discussed in this meta post.
I have some code and when it executes, it throws an exception saying:
The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
What does this mean, and how do I fix it?
c# asp.net-mvc
c# asp.net-mvc
edited Mar 20 '17 at 9:16
Community♦
11
11
asked Nov 2 '16 at 6:19
user3559349
I got this error when usingreturn View
instead ofreturn PartialView
so that's something to just check
– Richard Housham
Jul 5 '18 at 15:19
add a comment |
I got this error when usingreturn View
instead ofreturn PartialView
so that's something to just check
– Richard Housham
Jul 5 '18 at 15:19
I got this error when using
return View
instead of return PartialView
so that's something to just check– Richard Housham
Jul 5 '18 at 15:19
I got this error when using
return View
instead of return PartialView
so that's something to just check– Richard Housham
Jul 5 '18 at 15:19
add a comment |
3 Answers
3
active
oldest
votes
The error means that you're navigating to a view whose model is declared as typeof Foo
(by using @model Foo
), but you actually passed it a model which is typeof Bar
(note the term dictionary is used because a model is passed to the view via a ViewDataDictionary
).
The error can be caused by
Passing the wrong model from a controller method to a view (or partial view)
Common examples include using a query that creates an anonymous object (or collection of anonymous objects) and passing it to the view
var model = db.Foos.Select(x => new
{
ID = x.ID,
Name = x.Name
};
return View(model); // passes an anonymous object to a view declared with @model Foo
or passing a collection of objects to a view that expect a single object
var model = db.Foos.Where(x => x.ID == id);
return View(model); // passes IEnumerable<Foo> to a view declared with @model Foo
The error can be easily identified at compile time by explicitly declaring the model type in the controller to match the model in the view rather than using var
.
Passing the wrong model from a view to a partial view
Given the following model
public class Foo
{
public Bar MyBar { get; set; }
}
and a main view declared with @model Foo
and a partial view declared with @model Bar
, then
Foo model = db.Foos.Where(x => x.ID == id).Include(x => x.Bar).FirstOrDefault();
return View(model);
will return the correct model to the main view. However the exception will be thrown if the view includes
@Html.Partial("_Bar") // or @{ Html.RenderPartial("_Bar"); }
By default, the model passed to the partial view is the model declared in the main view and you need to use
@Html.Partial("_Bar", Model.MyBar) // or @{ Html.RenderPartial("_Bar", Model.MyBar); }
to pass the instance of Bar
to the partial view. Note also that if the value of MyBar
is null
(has not been initialized), then by default Foo
will be passed to the partial, in which case, it needs to be
@Html.Partial("_Bar", new Bar())
Declaring a model in a layout
If a layout file includes a model declaration, then all views that use that layout must declare the same model, or a model that derives from that model.
If you want to include the html for a separate model in a Layout, then in the Layout, use @Html.Action(...)
to call a [ChildActionOnly]
method initializes that model and returns a partial view for it.
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
add a comment |
Observe if the view has the model required:
View
@model IEnumerable<WFAccess.Models.ViewModels.SiteViewModel>
<div class="row">
<table class="table table-striped table-hover table-width-custom">
<thead>
<tr>
....
Controller
[HttpGet]
public ActionResult ListItems()
{
SiteStore site = new SiteStore();
site.GetSites();
IEnumerable<SiteViewModel> sites =
site.SitesList.Select(s => new SiteViewModel
{
Id = s.Id,
Type = s.Type
});
return PartialView("_ListItems", sites);
}
In my case I Use a partial view but runs in normal views
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
add a comment |
This question already has a great answer, but I ran into the same error, in a different scenario: displaying a List
in an EditorTemplate.
I have a model like this:
public class Foo
{
public string FooName { get; set; }
public List<Bar> Bars { get; set; }
}
public class Bar
{
public string BarName { get; set; }
}
And this is my main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
@Html.EditorFor(m => m.Bars)
And this is my Bar EditorTemplate (Bar.cshtml)
@model List<Bar>
<div class="some-style">
@foreach (var item in Model)
{
<label>@item.BarName</label>
}
</div>
And I got this error:
The model item passed into the dictionary is of type 'Bar', but this
dictionary requires a model item of type
'System.Collections.Generic.List`1[Bar]
The reason for this error is that EditorFor
already iterates the List
for you, so if you pass a collection to it, it would display the editor template once for each item in the collection.
This is how I fixed this problem:
Brought the styles outside of the editor template, and into the main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
<div class="some-style">
@Html.EditorFor(m => m.Bars)
</div>
And changed the EditorTemplate (Bar.cshtml) to this:
@model Bar
<label>@Model.BarName</label>
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The error means that you're navigating to a view whose model is declared as typeof Foo
(by using @model Foo
), but you actually passed it a model which is typeof Bar
(note the term dictionary is used because a model is passed to the view via a ViewDataDictionary
).
The error can be caused by
Passing the wrong model from a controller method to a view (or partial view)
Common examples include using a query that creates an anonymous object (or collection of anonymous objects) and passing it to the view
var model = db.Foos.Select(x => new
{
ID = x.ID,
Name = x.Name
};
return View(model); // passes an anonymous object to a view declared with @model Foo
or passing a collection of objects to a view that expect a single object
var model = db.Foos.Where(x => x.ID == id);
return View(model); // passes IEnumerable<Foo> to a view declared with @model Foo
The error can be easily identified at compile time by explicitly declaring the model type in the controller to match the model in the view rather than using var
.
Passing the wrong model from a view to a partial view
Given the following model
public class Foo
{
public Bar MyBar { get; set; }
}
and a main view declared with @model Foo
and a partial view declared with @model Bar
, then
Foo model = db.Foos.Where(x => x.ID == id).Include(x => x.Bar).FirstOrDefault();
return View(model);
will return the correct model to the main view. However the exception will be thrown if the view includes
@Html.Partial("_Bar") // or @{ Html.RenderPartial("_Bar"); }
By default, the model passed to the partial view is the model declared in the main view and you need to use
@Html.Partial("_Bar", Model.MyBar) // or @{ Html.RenderPartial("_Bar", Model.MyBar); }
to pass the instance of Bar
to the partial view. Note also that if the value of MyBar
is null
(has not been initialized), then by default Foo
will be passed to the partial, in which case, it needs to be
@Html.Partial("_Bar", new Bar())
Declaring a model in a layout
If a layout file includes a model declaration, then all views that use that layout must declare the same model, or a model that derives from that model.
If you want to include the html for a separate model in a Layout, then in the Layout, use @Html.Action(...)
to call a [ChildActionOnly]
method initializes that model and returns a partial view for it.
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
add a comment |
The error means that you're navigating to a view whose model is declared as typeof Foo
(by using @model Foo
), but you actually passed it a model which is typeof Bar
(note the term dictionary is used because a model is passed to the view via a ViewDataDictionary
).
The error can be caused by
Passing the wrong model from a controller method to a view (or partial view)
Common examples include using a query that creates an anonymous object (or collection of anonymous objects) and passing it to the view
var model = db.Foos.Select(x => new
{
ID = x.ID,
Name = x.Name
};
return View(model); // passes an anonymous object to a view declared with @model Foo
or passing a collection of objects to a view that expect a single object
var model = db.Foos.Where(x => x.ID == id);
return View(model); // passes IEnumerable<Foo> to a view declared with @model Foo
The error can be easily identified at compile time by explicitly declaring the model type in the controller to match the model in the view rather than using var
.
Passing the wrong model from a view to a partial view
Given the following model
public class Foo
{
public Bar MyBar { get; set; }
}
and a main view declared with @model Foo
and a partial view declared with @model Bar
, then
Foo model = db.Foos.Where(x => x.ID == id).Include(x => x.Bar).FirstOrDefault();
return View(model);
will return the correct model to the main view. However the exception will be thrown if the view includes
@Html.Partial("_Bar") // or @{ Html.RenderPartial("_Bar"); }
By default, the model passed to the partial view is the model declared in the main view and you need to use
@Html.Partial("_Bar", Model.MyBar) // or @{ Html.RenderPartial("_Bar", Model.MyBar); }
to pass the instance of Bar
to the partial view. Note also that if the value of MyBar
is null
(has not been initialized), then by default Foo
will be passed to the partial, in which case, it needs to be
@Html.Partial("_Bar", new Bar())
Declaring a model in a layout
If a layout file includes a model declaration, then all views that use that layout must declare the same model, or a model that derives from that model.
If you want to include the html for a separate model in a Layout, then in the Layout, use @Html.Action(...)
to call a [ChildActionOnly]
method initializes that model and returns a partial view for it.
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
add a comment |
The error means that you're navigating to a view whose model is declared as typeof Foo
(by using @model Foo
), but you actually passed it a model which is typeof Bar
(note the term dictionary is used because a model is passed to the view via a ViewDataDictionary
).
The error can be caused by
Passing the wrong model from a controller method to a view (or partial view)
Common examples include using a query that creates an anonymous object (or collection of anonymous objects) and passing it to the view
var model = db.Foos.Select(x => new
{
ID = x.ID,
Name = x.Name
};
return View(model); // passes an anonymous object to a view declared with @model Foo
or passing a collection of objects to a view that expect a single object
var model = db.Foos.Where(x => x.ID == id);
return View(model); // passes IEnumerable<Foo> to a view declared with @model Foo
The error can be easily identified at compile time by explicitly declaring the model type in the controller to match the model in the view rather than using var
.
Passing the wrong model from a view to a partial view
Given the following model
public class Foo
{
public Bar MyBar { get; set; }
}
and a main view declared with @model Foo
and a partial view declared with @model Bar
, then
Foo model = db.Foos.Where(x => x.ID == id).Include(x => x.Bar).FirstOrDefault();
return View(model);
will return the correct model to the main view. However the exception will be thrown if the view includes
@Html.Partial("_Bar") // or @{ Html.RenderPartial("_Bar"); }
By default, the model passed to the partial view is the model declared in the main view and you need to use
@Html.Partial("_Bar", Model.MyBar) // or @{ Html.RenderPartial("_Bar", Model.MyBar); }
to pass the instance of Bar
to the partial view. Note also that if the value of MyBar
is null
(has not been initialized), then by default Foo
will be passed to the partial, in which case, it needs to be
@Html.Partial("_Bar", new Bar())
Declaring a model in a layout
If a layout file includes a model declaration, then all views that use that layout must declare the same model, or a model that derives from that model.
If you want to include the html for a separate model in a Layout, then in the Layout, use @Html.Action(...)
to call a [ChildActionOnly]
method initializes that model and returns a partial view for it.
The error means that you're navigating to a view whose model is declared as typeof Foo
(by using @model Foo
), but you actually passed it a model which is typeof Bar
(note the term dictionary is used because a model is passed to the view via a ViewDataDictionary
).
The error can be caused by
Passing the wrong model from a controller method to a view (or partial view)
Common examples include using a query that creates an anonymous object (or collection of anonymous objects) and passing it to the view
var model = db.Foos.Select(x => new
{
ID = x.ID,
Name = x.Name
};
return View(model); // passes an anonymous object to a view declared with @model Foo
or passing a collection of objects to a view that expect a single object
var model = db.Foos.Where(x => x.ID == id);
return View(model); // passes IEnumerable<Foo> to a view declared with @model Foo
The error can be easily identified at compile time by explicitly declaring the model type in the controller to match the model in the view rather than using var
.
Passing the wrong model from a view to a partial view
Given the following model
public class Foo
{
public Bar MyBar { get; set; }
}
and a main view declared with @model Foo
and a partial view declared with @model Bar
, then
Foo model = db.Foos.Where(x => x.ID == id).Include(x => x.Bar).FirstOrDefault();
return View(model);
will return the correct model to the main view. However the exception will be thrown if the view includes
@Html.Partial("_Bar") // or @{ Html.RenderPartial("_Bar"); }
By default, the model passed to the partial view is the model declared in the main view and you need to use
@Html.Partial("_Bar", Model.MyBar) // or @{ Html.RenderPartial("_Bar", Model.MyBar); }
to pass the instance of Bar
to the partial view. Note also that if the value of MyBar
is null
(has not been initialized), then by default Foo
will be passed to the partial, in which case, it needs to be
@Html.Partial("_Bar", new Bar())
Declaring a model in a layout
If a layout file includes a model declaration, then all views that use that layout must declare the same model, or a model that derives from that model.
If you want to include the html for a separate model in a Layout, then in the Layout, use @Html.Action(...)
to call a [ChildActionOnly]
method initializes that model and returns a partial view for it.
edited Feb 27 '17 at 23:29
community wiki
3 revs, 2 users 96%
Stephen Muecke
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
add a comment |
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
14
14
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
+1 for "Note also that if the value of MyBar is null (has not been initialized), then by default Foo will be passed to the partial, in which case, it needs to be". Very important note.
– Smix
Mar 8 '18 at 6:48
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
I'm getting the same error by having a Partial View within a Layout, with no model type defined. The Partial View crashes because it receives the model from the index page when none is defined nor needed, and if I set the partial model to IndexModel, then the ViewData property is null!?? How to fix this scenario? Moving the partial into the layout does work but I want to understand how it works.
– Etienne Charland
Mar 4 at 7:59
add a comment |
Observe if the view has the model required:
View
@model IEnumerable<WFAccess.Models.ViewModels.SiteViewModel>
<div class="row">
<table class="table table-striped table-hover table-width-custom">
<thead>
<tr>
....
Controller
[HttpGet]
public ActionResult ListItems()
{
SiteStore site = new SiteStore();
site.GetSites();
IEnumerable<SiteViewModel> sites =
site.SitesList.Select(s => new SiteViewModel
{
Id = s.Id,
Type = s.Type
});
return PartialView("_ListItems", sites);
}
In my case I Use a partial view but runs in normal views
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
add a comment |
Observe if the view has the model required:
View
@model IEnumerable<WFAccess.Models.ViewModels.SiteViewModel>
<div class="row">
<table class="table table-striped table-hover table-width-custom">
<thead>
<tr>
....
Controller
[HttpGet]
public ActionResult ListItems()
{
SiteStore site = new SiteStore();
site.GetSites();
IEnumerable<SiteViewModel> sites =
site.SitesList.Select(s => new SiteViewModel
{
Id = s.Id,
Type = s.Type
});
return PartialView("_ListItems", sites);
}
In my case I Use a partial view but runs in normal views
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
add a comment |
Observe if the view has the model required:
View
@model IEnumerable<WFAccess.Models.ViewModels.SiteViewModel>
<div class="row">
<table class="table table-striped table-hover table-width-custom">
<thead>
<tr>
....
Controller
[HttpGet]
public ActionResult ListItems()
{
SiteStore site = new SiteStore();
site.GetSites();
IEnumerable<SiteViewModel> sites =
site.SitesList.Select(s => new SiteViewModel
{
Id = s.Id,
Type = s.Type
});
return PartialView("_ListItems", sites);
}
In my case I Use a partial view but runs in normal views
Observe if the view has the model required:
View
@model IEnumerable<WFAccess.Models.ViewModels.SiteViewModel>
<div class="row">
<table class="table table-striped table-hover table-width-custom">
<thead>
<tr>
....
Controller
[HttpGet]
public ActionResult ListItems()
{
SiteStore site = new SiteStore();
site.GetSites();
IEnumerable<SiteViewModel> sites =
site.SitesList.Select(s => new SiteViewModel
{
Id = s.Id,
Type = s.Type
});
return PartialView("_ListItems", sites);
}
In my case I Use a partial view but runs in normal views
edited Jun 20 '18 at 14:30
answered Nov 17 '17 at 18:46
CelzioBRCelzioBR
746
746
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
add a comment |
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
What does this have to do with the question?
– user3559349
Nov 17 '17 at 20:45
2
2
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
@StephenMuecke this champs - The model item passed into the dictionary is of type Bar but this dictionary requires a model item of type Foo
– CelzioBR
Nov 21 '17 at 13:37
add a comment |
This question already has a great answer, but I ran into the same error, in a different scenario: displaying a List
in an EditorTemplate.
I have a model like this:
public class Foo
{
public string FooName { get; set; }
public List<Bar> Bars { get; set; }
}
public class Bar
{
public string BarName { get; set; }
}
And this is my main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
@Html.EditorFor(m => m.Bars)
And this is my Bar EditorTemplate (Bar.cshtml)
@model List<Bar>
<div class="some-style">
@foreach (var item in Model)
{
<label>@item.BarName</label>
}
</div>
And I got this error:
The model item passed into the dictionary is of type 'Bar', but this
dictionary requires a model item of type
'System.Collections.Generic.List`1[Bar]
The reason for this error is that EditorFor
already iterates the List
for you, so if you pass a collection to it, it would display the editor template once for each item in the collection.
This is how I fixed this problem:
Brought the styles outside of the editor template, and into the main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
<div class="some-style">
@Html.EditorFor(m => m.Bars)
</div>
And changed the EditorTemplate (Bar.cshtml) to this:
@model Bar
<label>@Model.BarName</label>
add a comment |
This question already has a great answer, but I ran into the same error, in a different scenario: displaying a List
in an EditorTemplate.
I have a model like this:
public class Foo
{
public string FooName { get; set; }
public List<Bar> Bars { get; set; }
}
public class Bar
{
public string BarName { get; set; }
}
And this is my main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
@Html.EditorFor(m => m.Bars)
And this is my Bar EditorTemplate (Bar.cshtml)
@model List<Bar>
<div class="some-style">
@foreach (var item in Model)
{
<label>@item.BarName</label>
}
</div>
And I got this error:
The model item passed into the dictionary is of type 'Bar', but this
dictionary requires a model item of type
'System.Collections.Generic.List`1[Bar]
The reason for this error is that EditorFor
already iterates the List
for you, so if you pass a collection to it, it would display the editor template once for each item in the collection.
This is how I fixed this problem:
Brought the styles outside of the editor template, and into the main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
<div class="some-style">
@Html.EditorFor(m => m.Bars)
</div>
And changed the EditorTemplate (Bar.cshtml) to this:
@model Bar
<label>@Model.BarName</label>
add a comment |
This question already has a great answer, but I ran into the same error, in a different scenario: displaying a List
in an EditorTemplate.
I have a model like this:
public class Foo
{
public string FooName { get; set; }
public List<Bar> Bars { get; set; }
}
public class Bar
{
public string BarName { get; set; }
}
And this is my main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
@Html.EditorFor(m => m.Bars)
And this is my Bar EditorTemplate (Bar.cshtml)
@model List<Bar>
<div class="some-style">
@foreach (var item in Model)
{
<label>@item.BarName</label>
}
</div>
And I got this error:
The model item passed into the dictionary is of type 'Bar', but this
dictionary requires a model item of type
'System.Collections.Generic.List`1[Bar]
The reason for this error is that EditorFor
already iterates the List
for you, so if you pass a collection to it, it would display the editor template once for each item in the collection.
This is how I fixed this problem:
Brought the styles outside of the editor template, and into the main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
<div class="some-style">
@Html.EditorFor(m => m.Bars)
</div>
And changed the EditorTemplate (Bar.cshtml) to this:
@model Bar
<label>@Model.BarName</label>
This question already has a great answer, but I ran into the same error, in a different scenario: displaying a List
in an EditorTemplate.
I have a model like this:
public class Foo
{
public string FooName { get; set; }
public List<Bar> Bars { get; set; }
}
public class Bar
{
public string BarName { get; set; }
}
And this is my main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
@Html.EditorFor(m => m.Bars)
And this is my Bar EditorTemplate (Bar.cshtml)
@model List<Bar>
<div class="some-style">
@foreach (var item in Model)
{
<label>@item.BarName</label>
}
</div>
And I got this error:
The model item passed into the dictionary is of type 'Bar', but this
dictionary requires a model item of type
'System.Collections.Generic.List`1[Bar]
The reason for this error is that EditorFor
already iterates the List
for you, so if you pass a collection to it, it would display the editor template once for each item in the collection.
This is how I fixed this problem:
Brought the styles outside of the editor template, and into the main view:
@model Foo
@Html.TextBoxFor(m => m.Name, new { @class = "form-control" })
<div class="some-style">
@Html.EditorFor(m => m.Bars)
</div>
And changed the EditorTemplate (Bar.cshtml) to this:
@model Bar
<label>@Model.BarName</label>
edited Jul 8 '18 at 0:26
answered Jul 7 '18 at 13:37
Hooman BahreiniHooman Bahreini
4,29531034
4,29531034
add a comment |
add a comment |
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I got this error when using
return View
instead ofreturn PartialView
so that's something to just check– Richard Housham
Jul 5 '18 at 15:19