Increase number with character in Java
2
I have a problem with increasing number and character combinations.
What I want is increase from
001 to ZZZ
Example: 001, 002,..., 999, 00A,..., 00Z, 0AA,..., ZZZ
My code look like this:
int numberA = 1000;
int numberB = 1024;
int numberC = 1025;
/*
* Some formulae here
*/
System.out.println(numberA);
//Result: 00A
System.out.println(numberB);
//Result: 00Z
System.out.println(numberC);
//Result: 0A0
Are there any fomulae to solve this problem?
java java-8
edited Nov 23 '18 at 12:36
deHaar
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
add a comment |
2
I have a problem with increasing number and character combinations.
What I want is increase from
001 to ZZZ
Example: 001, 002,..., 999, 00A,..., 00Z, 0AA,..., ZZZ
My code look like this:
int numberA = 1000;
int numberB = 1024;
int numberC = 1025;
/*
* Some formulae here
*/
System.out.println(numberA);
//Result: 00A
System.out.println(numberB);
//Result: 00Z
System.out.println(numberC);
//Result: 0A0
Are there any fomulae to solve this problem?
java java-8
edited Nov 23 '18 at 12:36
deHaar
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52
add a comment |
2
2
2
2
I have a problem with increasing number and character combinations.
What I want is increase from
001 to ZZZ
Example: 001, 002,..., 999, 00A,..., 00Z, 0AA,..., ZZZ
My code look like this:
int numberA = 1000;
int numberB = 1024;
int numberC = 1025;
/*
* Some formulae here
*/
System.out.println(numberA);
//Result: 00A
System.out.println(numberB);
//Result: 00Z
System.out.println(numberC);
//Result: 0A0
Are there any fomulae to solve this problem?
java java-8
edited Nov 23 '18 at 12:36
deHaar
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
I have a problem with increasing number and character combinations.
What I want is increase from
001 to ZZZ
Example: 001, 002,..., 999, 00A,..., 00Z, 0AA,..., ZZZ
My code look like this:
int numberA = 1000;
int numberB = 1024;
int numberC = 1025;
/*
* Some formulae here
*/
System.out.println(numberA);
//Result: 00A
System.out.println(numberB);
//Result: 00Z
System.out.println(numberC);
//Result: 0A0
Are there any fomulae to solve this problem?
java java-8
java java-8
edited Nov 23 '18 at 12:36
deHaar
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
edited Nov 23 '18 at 12:36
deHaar
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
edited Nov 23 '18 at 12:36
deHaar
2,66961729
edited Nov 23 '18 at 12:36
deHaar
2,66961729
edited Nov 23 '18 at 12:36
deHaar
2,66961729
2,66961729
asked Nov 23 '18 at 12:28
ThiệnThiện
285
asked Nov 23 '18 at 12:28
ThiệnThiện
285
asked Nov 23 '18 at 12:28
ThiệnThiện
285
285
based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52
add a comment |
based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52
based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52
add a comment |
3 Answers
3
active
oldest
votes
5
Maybe the following will help you get started ;-)
final Integer radix = 36; // that's 0-9 A-Z
final Double limit = Math.pow(radix.doubleValue(), 3.0 /* max number of 'chars' */);
Stream.iterate(0, i -> i+1)
.map(i -> Integer.toString(i, radix))
.map(s -> String.format("000%S", s)
.substring(s.length())) // leading 0, uppercase
.limit(limit.longValue())
.forEach(System.out::println);
Or simply:
String radix36 = Integer.toString(yourIntThatYouCanIncrement, 36);
Of course if you require the 00#-format (leading zeros and uppercase) you need to apply that functions too. Holgers comment already contains a short variant of it to combine uppercase/leading zeros:
String formatted = String.format("000%S", radix36)
.substring(radix36.length());
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
add a comment |
3
You can format your number as a base-36 number (you want to use 36 different digits: 0 - 9 = 10 digits + A - Z = 26 digits).
To get it exactly in the format you want (upper-case, with leading zeroes):
String s = Integer.toString(numberA, 36).toUpperCase();
String result = String.format("%3s", s).replace(' ', '0');
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
1
OrString s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…
– Holger
Nov 23 '18 at 13:07
add a comment |
1
Here is code that will print 001 to zzz sequence.
public static void main(String args){
String result="";
int i=0;
while(!result.equals("ZZZ")){
String s = Integer.toString(i, 36).toUpperCase();
result = String.format("%3s", s).replace(' ', '0');
System.out.println("t "+result);
i++;
}
}
answered Nov 23 '18 at 15:07
samjisamji
265
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
Maybe the following will help you get started ;-)
final Integer radix = 36; // that's 0-9 A-Z
final Double limit = Math.pow(radix.doubleValue(), 3.0 /* max number of 'chars' */);
Stream.iterate(0, i -> i+1)
.map(i -> Integer.toString(i, radix))
.map(s -> String.format("000%S", s)
.substring(s.length())) // leading 0, uppercase
.limit(limit.longValue())
.forEach(System.out::println);
Or simply:
String radix36 = Integer.toString(yourIntThatYouCanIncrement, 36);
Of course if you require the 00#-format (leading zeros and uppercase) you need to apply that functions too. Holgers comment already contains a short variant of it to combine uppercase/leading zeros:
String formatted = String.format("000%S", radix36)
.substring(radix36.length());
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
add a comment |
5
Maybe the following will help you get started ;-)
final Integer radix = 36; // that's 0-9 A-Z
final Double limit = Math.pow(radix.doubleValue(), 3.0 /* max number of 'chars' */);
Stream.iterate(0, i -> i+1)
.map(i -> Integer.toString(i, radix))
.map(s -> String.format("000%S", s)
.substring(s.length())) // leading 0, uppercase
.limit(limit.longValue())
.forEach(System.out::println);
Or simply:
String radix36 = Integer.toString(yourIntThatYouCanIncrement, 36);
Of course if you require the 00#-format (leading zeros and uppercase) you need to apply that functions too. Holgers comment already contains a short variant of it to combine uppercase/leading zeros:
String formatted = String.format("000%S", radix36)
.substring(radix36.length());
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
add a comment |
5
5
5
Maybe the following will help you get started ;-)
final Integer radix = 36; // that's 0-9 A-Z
final Double limit = Math.pow(radix.doubleValue(), 3.0 /* max number of 'chars' */);
Stream.iterate(0, i -> i+1)
.map(i -> Integer.toString(i, radix))
.map(s -> String.format("000%S", s)
.substring(s.length())) // leading 0, uppercase
.limit(limit.longValue())
.forEach(System.out::println);
Or simply:
String radix36 = Integer.toString(yourIntThatYouCanIncrement, 36);
Of course if you require the 00#-format (leading zeros and uppercase) you need to apply that functions too. Holgers comment already contains a short variant of it to combine uppercase/leading zeros:
String formatted = String.format("000%S", radix36)
.substring(radix36.length());
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
Maybe the following will help you get started ;-)
final Integer radix = 36; // that's 0-9 A-Z
final Double limit = Math.pow(radix.doubleValue(), 3.0 /* max number of 'chars' */);
Stream.iterate(0, i -> i+1)
.map(i -> Integer.toString(i, radix))
.map(s -> String.format("000%S", s)
.substring(s.length())) // leading 0, uppercase
.limit(limit.longValue())
.forEach(System.out::println);
Or simply:
String radix36 = Integer.toString(yourIntThatYouCanIncrement, 36);
Of course if you require the 00#-format (leading zeros and uppercase) you need to apply that functions too. Holgers comment already contains a short variant of it to combine uppercase/leading zeros:
String formatted = String.format("000%S", radix36)
.substring(radix36.length());
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
edited Nov 23 '18 at 13:11
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
answered Nov 23 '18 at 12:49
RolandRoland
10.5k11442
10.5k11442
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
add a comment |
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
Thank you! I'll check it out
– Thiện
Nov 23 '18 at 12:54
add a comment |
3
You can format your number as a base-36 number (you want to use 36 different digits: 0 - 9 = 10 digits + A - Z = 26 digits).
To get it exactly in the format you want (upper-case, with leading zeroes):
String s = Integer.toString(numberA, 36).toUpperCase();
String result = String.format("%3s", s).replace(' ', '0');
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
1
OrString s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…
– Holger
Nov 23 '18 at 13:07
add a comment |
3
You can format your number as a base-36 number (you want to use 36 different digits: 0 - 9 = 10 digits + A - Z = 26 digits).
To get it exactly in the format you want (upper-case, with leading zeroes):
String s = Integer.toString(numberA, 36).toUpperCase();
String result = String.format("%3s", s).replace(' ', '0');
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
1
OrString s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…
– Holger
Nov 23 '18 at 13:07
add a comment |
3
3
3
You can format your number as a base-36 number (you want to use 36 different digits: 0 - 9 = 10 digits + A - Z = 26 digits).
To get it exactly in the format you want (upper-case, with leading zeroes):
String s = Integer.toString(numberA, 36).toUpperCase();
String result = String.format("%3s", s).replace(' ', '0');
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
You can format your number as a base-36 number (you want to use 36 different digits: 0 - 9 = 10 digits + A - Z = 26 digits).
To get it exactly in the format you want (upper-case, with leading zeroes):
String s = Integer.toString(numberA, 36).toUpperCase();
String result = String.format("%3s", s).replace(' ', '0');
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
answered Nov 23 '18 at 12:54
JesperJesper
155k36251297
155k36251297
1
OrString s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…
– Holger
Nov 23 '18 at 13:07
add a comment |
1
OrString s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…
– Holger
Nov 23 '18 at 13:07
1
1
Or
String s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…– Holger
Nov 23 '18 at 13:07
Or
String s = Integer.toString(numberA, 36); String result = String.format("000%S", s) .substring(s.length());…– Holger
Nov 23 '18 at 13:07
add a comment |
1
Here is code that will print 001 to zzz sequence.
public static void main(String args){
String result="";
int i=0;
while(!result.equals("ZZZ")){
String s = Integer.toString(i, 36).toUpperCase();
result = String.format("%3s", s).replace(' ', '0');
System.out.println("t "+result);
i++;
}
}
answered Nov 23 '18 at 15:07
samjisamji
265
add a comment |
1
Here is code that will print 001 to zzz sequence.
public static void main(String args){
String result="";
int i=0;
while(!result.equals("ZZZ")){
String s = Integer.toString(i, 36).toUpperCase();
result = String.format("%3s", s).replace(' ', '0');
System.out.println("t "+result);
i++;
}
}
answered Nov 23 '18 at 15:07
samjisamji
265
add a comment |
1
1
1
Here is code that will print 001 to zzz sequence.
public static void main(String args){
String result="";
int i=0;
while(!result.equals("ZZZ")){
String s = Integer.toString(i, 36).toUpperCase();
result = String.format("%3s", s).replace(' ', '0');
System.out.println("t "+result);
i++;
}
}
answered Nov 23 '18 at 15:07
samjisamji
265
Here is code that will print 001 to zzz sequence.
public static void main(String args){
String result="";
int i=0;
while(!result.equals("ZZZ")){
String s = Integer.toString(i, 36).toUpperCase();
result = String.format("%3s", s).replace(' ', '0');
System.out.println("t "+result);
i++;
}
}
answered Nov 23 '18 at 15:07
samjisamji
265
answered Nov 23 '18 at 15:07
samjisamji
265
answered Nov 23 '18 at 15:07
samjisamji
265
answered Nov 23 '18 at 15:07
samjisamji
265
265
add a comment |
add a comment |
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based on what do you want to switch to characters? would the numbers be always 3-digit? why would you want to do it (curious)?
– Naman
Nov 23 '18 at 12:31
Number is auto increase from 1 -> 18576 (001 -> ZZZ). Yes. Those output always have 3 digits. I have a school project that need to store lots of items in the warehouse, each item must have different "code" within one day. My format is yymmdd-XXX with XXX is the number above. I want to extend as much as possible the range of those number.
– Thiện
Nov 23 '18 at 12:41
Please check this stackoverflow.com/questions/5091355/increase-string-value
– Deedar Ali Brohi
Nov 23 '18 at 12:43
Do check this out stackoverflow.com/questions/28981669/…
– Ojasvi Bhargava
Nov 23 '18 at 12:46
Thanks! I'll check it out
– Thiện
Nov 23 '18 at 12:52